Chapter 2: Problem 15
Determine amplitude, period, and phase shift for each function. $$ y=-2 \cos \left(2 x+\frac{\pi}{2}\right)-1 $$
Short Answer
Expert verified
Amplitude is 2, period is \(\pi\), and phase shift is \(-\frac{\pi}{4}\).
Step by step solution
01
Identify the general form of the cosine function
The general form of the cosine function is given by \[ y = A \cos(Bx + C) + D \]. Compare this general form with the given function \[ y = -2 \cos \left(2x + \frac{\pi}{2}\right) - 1 \].
02
Determine the amplitude
The amplitude is given by the absolute value of the coefficient in front of the cosine function. Here, the coefficient is -2. Thus, the amplitude is \[ \|A\| = |-2| = 2 \].
03
Determine the period
The period of the cosine function is determined by the formula \[ \frac{2\pi}{B} \]. In this case, \[ B = 2 \], so the period is \[ \frac{2\pi}{2} = \pi \].
04
Determine the phase shift
The phase shift is calculated using the formula \[ -\frac{C}{B} \]. In the given function, \[ C = \frac{\pi}{2} \] and \[ B = 2 \], so the phase shift is \[ -\frac{\frac{\pi}{2}}{2} = -\frac{\pi}{4} \].
05
Determine the vertical shift
The vertical shift is given by \[ D \]. In the given function, \[ D = -1 \], so there is a downward shift of 1 unit.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
cosine function
The cosine function is a fundamental trigonometric function that describes the relationship between the angle of a right triangle and the length of the adjacent side to the hypotenuse. The general form of the cosine function is given by \( y = A \, \text{cos}(Bx + C) + D \). In this equation:
- \( A \): Amplitude, representing the peak value from the midline.
- \( B \): Affects the period or the length of one complete cycle.
- \( C \): Phase shift, moving the graph horizontally.
- \( D \): Vertical shift, moving the graph up or down.
amplitude calculation
The amplitude of a cosine function determines the maximum and minimum values the function can achieve relative to its midline. It is calculated using the absolute value of the coefficient \( A \) in front of the cosine. For the given function \( y = -2 \, \text{cos}(2x + \frac{\text{Ï€}}{2}) - 1 \), the amplitude is found by taking \( | -2 | = 2 \). Hence, the amplitude is 2. This means the highest point of the graph will be 2 units away from the midline, and the lowest point will also be 2 units away in the opposite direction.
period calculation
The period of a cosine function determines how long it takes for one complete cycle of the wave. It is calculated using the formula \( \frac{2 \text{Ï€}}{B} \). For the function \( y = -2 \, \text{cos}(2x + \frac{\text{Ï€}}{2}) - 1 \), \( B = 2 \). Plugging this into the formula, we get the period: \( \frac{2 \text{Ï€}}{2} = \text{Ï€} \). This means the wave will repeat itself every \( \text{Ï€} \) units along the x-axis.
phase shift calculation
The phase shift of a cosine function describes how much the graph is shifted horizontally from its usual position. It is given by the formula \( -\frac{C}{B} \). In our function \( y = -2 \, \text{cos}(2x + \frac{\text{Ï€}}{2}) - 1 \), \( C = \frac{\text{Ï€}}{2} \) and \( B = 2 \). Substituting these values, we get the phase shift: \( -\frac{\frac{\text{Ï€}}{2}}{2} = -\frac{\text{Ï€}}{4} \). This tells us that the graph of the cosine function is shifted to the left by \( \frac{\text{Ï€}}{4} \) units.
vertical shift
The vertical shift of a cosine function indicates how much the entire graph is moved up or down along the y-axis. It is represented by the constant \( D \). For our function \( y = -2 \, \text{cos}(2x + \frac{\text{Ï€}}{2}) - 1 \), the vertical shift is \( -1 \). This means the graph is shifted down by 1 unit.
To summarize:
To summarize:
- Amplitude: 2
- Period: \( \text{Ï€} \)
- Phase Shift: \( -\frac{\text{Ï€}}{4} \)
- Vertical Shift: Down 1 unit