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Find the exact value of each expression without using a calculator. Check your answer with a calculator. $$ \frac{\sin (-5 \pi / 6)}{\cos (-5 \pi / 6)} $$

Short Answer

Expert verified
\( - \frac{1}{\sqrt{3}} \)

Step by step solution

01

- Simplify the Trigonometric Expression

Recognize that \(\frac{\sin (-5 \pi / 6)}{\cos (-5 \pi / 6)}\) can be simplified using the identity for the tangent function: \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\). Thus, \(\frac{\sin (-5 \pi / 6)}{\cos (-5 \pi / 6)} = \tan(-5 \pi / 6)\).
02

- Determine the Reference Angle

Find the reference angle for \(-5 \pi / 6\). The reference angle is the positive acute angle that the given angle makes with the x-axis. Since \(-5 \pi / 6\) is in the third quadrant when considering its positive equivalent, the reference angle is \pi - \frac{5 \pi}{6} = \frac{\pi}{6}\.
03

- Determine the Sign and Value of the Tangent Function

The tangent function is positive in both the third quadrant and negative angles that fall back into the third quadrant. Thus, \(\tan(-5 \pi / 6) = \tan(5 \pi / 6)\).
04

- Evaluate the Tangent of the Reference Angle

The tangent of \(\frac{\pi}{6}\) is known to be \(\frac{1}{\sqrt{3}}\). Therefore, \(\tan(5 \pi / 6) = - \frac{1}{\sqrt{3}}\) (since \(\tan(5 \pi / 6)\) is in the second quadrant where tangent is negative). Thus, \(\tan(-5 \pi / 6) = - \frac{1}{\sqrt{3}}\).
05

- Verify with a Calculator

Use a calculator to verify: \(\frac{\sin (-5 \pi / 6)}{\cos (-5 \pi / 6)}\) should give \(-\frac{1}{\sqrt{3}}\), confirming that the calculated value is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Function
To start, it's crucial to understand what the tangent function represents. The tangent of an angle, \(\tan(\theta)\), is defined as the ratio of the sine to the cosine of that angle. This can be expressed as \(\tan(\theta) = \frac{\text{sin}(\theta)}{\text{cos}(\theta)}\).
In this exercise, we use this property to simplify the given expression: \(\frac{\text{sin}(-5 \pi / 6)}{\text{cos}(-5 \pi / 6)}\). Using the identity \(\tan(\theta)\), we realize this is equivalent to \(\tan(-5 \pi / 6)\).
The tangent function helps transform a potentially complex sine and cosine division into a simpler tangent expression, making our trigonometric calculations more manageable.
Reference Angle
Let's talk about the reference angle, a fundamental concept in trigonometry. The reference angle for any given angle is the smallest angle it forms with the x-axis.
For \(-5 \pi / 6\), finding its reference angle means looking at its positive equivalent. This angle lands in the third quadrant when considering positive movement.
The reference angle becomes \(\frac{\pi}{6}\) given by \(\text{\pi} - \frac{5 \pi}{6} = \frac{\pi}{6}\).
Reference angles help in determining the sine, cosine, and tangent values based on known values of acute angles.
Trigonometric Identities
Trigonometric identities are equations that involve trigonometric functions and are true for every value within their domains. These identities are powerful tools in solving and simplifying trigonometric expressions.
Key identities include:
  • \(\tan(\theta) = \frac{\text{sin}(\theta)}{\text{cos}(\theta)}\)
  • \(\text{cos}^2(\theta) + \text{sin}^2(\theta) = 1\)
  • \(\text{sin}(-\theta) = -\text{sin}(\theta)\) and \(\text{cos}(-\theta) = \text{cos}(\theta)\)
These identities allow us to handle negative angles and quadrants effectively.
They played a crucial part in converting \(\frac{\text{sin}(-5 \pi / 6)}{\text{cos}(-5 \pi / 6)}\) into \(\tan(-5 \pi / 6)\).
Unit Circle
The unit circle is central to understanding trigonometry. It is a circle with a radius of 1 centered at the origin in the coordinate plane.
Points on this circle correspond to angles and their sine and cosine values. For angle \(\theta\), the coordinates are \((\text{cos}(\theta), \text{sin}(\theta))\).
In this exercise, -5\(\frac{\pi}{6}\) radians is located on the unit circle in the third quadrant, helping to determine its sine and cosine.
The unit circle allows us to see visually which quadrant an angle lands in, helping us ascertain the sign (positive/negative) of trigonometric functions. Therefore, using it, we can say that \(\tan(5 \pi / 6) = - \frac{1}{\text{\sqrt{3}}}\).

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