/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Find the exact value of each fun... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the exact value of each function without using a calculator. $$ \cot (13 \pi / 6) $$

Short Answer

Expert verified
The exact value of \( \text{cot}(13π/6) \) is \ √3 \.

Step by step solution

01

Identify the Angle in Standard Position

Determine the angle in terms of \(\frac{\theta}{2\text{π}}\) by subtracting multiples of \2π\ until the angle is between \0\ and \2π\. Since \(13π/6\) is more than \2π\, subtract \2π\ from \(13π/6\)\.\[ 13π/6 - 2π = 13π/6 - 12π/6 = π/6 \]
02

Use the Cotangent Function

Determine the cotangent of the angle found in Step 1. \(π/6\) is a known angle where exact trigonometric values are typically memorized. The cotangent of \(π/6\) can be found using the definition \(\frac{\text{adjacent}}{\text{opposite}}\) or the reciprocal of the tangent function:\[ \tan(π/6) = \frac{1}{\frac{\text{√}3}{3}} = \text{√}3 \]Then, \[ \tan^{-1}(\text{√}3) = \frac{1}{\frac{1}{\text{√}3}} = \text{√}3 \]
03

Conclusion

Combine the findings to determine the exact value of \(\text{cot}(13π/6) = \text{cot}(π/6) = √3\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angle Conversion
To solve trigonometric problems effectively, mastering angle conversion is essential. Often, angles are provided in radians, and you might need to identify the equivalent angle within a standard range. For example, the given angle \( \frac{13\text{Ï€}}{6} \) exceeds \ 2Ï€ \, so you need to bring it within the primary circle range by subtracting multiples of \ 2Ï€ \.
Let's break it down: \( \frac{13\text{Ï€}}{6} - 2Ï€ = \frac{13\text{Ï€}}{6} - \frac{12\text{Ï€}}{6} = \frac{Ï€}{6} \).
This step simplifies the problem and brings the angle to an easy-to-manage form. Practicing such conversions helps when dealing with angles larger than a full circle (360 degrees or \(2\text{Ï€} \) radians).
Key points to remember:
  • Subtract (or add) \(2\text{Ï€} \) to fit the angle within \( [0, 2\text{Ï€}) \).
  • Use the reduced angle for easier calculations.
Exact Trigonometric Values
Knowing exact trigonometric values is crucial for solving problems without a calculator. Specific angles, like \( \frac{Ï€}{6} \), \( \frac{Ï€}{4} \), and \( \frac{Ï€}{3}\), have known trigonometric values that are often memorized.
For \ \frac{Ï€}{6} \, the key trigonometric values are:
  • \( \tan(\frac{Ï€}{6}) = \frac{1}{\text{√}3} \)
  • \( \text{cot}(\frac{Ï€}{6}) \) is the reciprocal of the tangent function
Since \( \text{tan}(\frac{π}{6}) = \frac{1}{\text{√}3} \),
\(\text{cot}(\frac{π}{6}) = \text{√}3 \).
This method, knowing the exact values, helps you compute functions quickly and accurately.
Unit Circle
The unit circle is a fantastic tool for visualizing and understanding trigonometric functions. The unit circle is a circle with a radius of 1, centered at the origin (0,0) on the coordinate plane.
Each point on the unit circle corresponds to an angle formed with the positive x-axis.
Important angles, such as \( \frac{Ï€}{6} \), have known coordinates that simplify trigonometric calculations:
For example, the coordinates at \( \frac{π}{6} \) are \( \frac{\text{√}3}{2} \, \ \frac{1}{2} \)
  • \( \text{tan}(\frac{Ï€}{6}) = \frac{\text{opposite}}{\text{adjacent}} = \frac{1/3 - (-1/2)}{\text{√2} - x} \)
  • \text{cot}(\frac{Ï€}{6}) = \frac{adjacent}{opposite} = \text{√3]}
By practicing with the unit circle, you can quickly determine trigonometric identities and their respective values.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Fifteen experts are voting to determine the best convertible of the year. The choices are a Porsche Carrera, a Chrysler Crossfire, and a Nissan Roadster. The experts will rank the three cars 1 st, 2nd, and 3 rd. There are three common ways to determine the winner: a. Plurality: The car with the most first-place votes (preferences) is the winner. b. Instant runoff: The car with the least number of preferences is eliminated. Then the ballots for which the eliminated car is first are revised so that the second-place car is moved to first. Finally, the car with the most preferences is the winner. c. The point system: Two points are given for each time a car is ranked first place on a ballot, one point for each time the car appears in second place on a ballot, and no points for third place. When the ballots were cast, the Porsche won when plurality was used, the Chrysler won when instant runoff was used, and the Nissan won when the point system was used. Determine 15 actual votes for which this result would occur.

True or false? Do not use a calculator. $$ \cos (9 \pi / 5)=\cos (\pi / 5) $$

Use a calculator to find the value of each function. Round answers to four decimal places. $$ \sec \left(-9^{\circ} 4^{\prime} 7^{\prime \prime}\right) $$

A sector of a circle with radius 8 meters has a central angle of \(\pi / 8\). Find the area of the sector to the nearest tenth of a square meter.

Use a calculator to evaluate each expression. Round approximate answers to four decimal places. $$ \frac{1-\cos \left(98.6^{\circ}\right)}{\sin \left(98.6^{\circ}\right)} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.