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In Exercises 1-20, graph the curve defined by the following sets of parametric equations. Be sure to indicate the direction of movement along the curve. $$ x=(t+1)^{2}, y=(t+2)^{3}, t \text { in }[0,1] $$

Short Answer

Expert verified
Graph starts at (1, 8) and ends at (4, 27), moving in the diagonal direction from bottom-left to top-right.

Step by step solution

01

Understand the parametric equations

The parametric equations provided are \( x = (t+1)^2 \) and \( y = (t+2)^3 \). Here, \( t \) is the parameter that varies within the interval \([0, 1]\). As \( t \) changes, both \( x \) and \( y \) also change, describing a path in the Cartesian plane.
02

Determine the range of \(x\)

Let's find the values of \(x\) at the ends of the interval. When \(t = 0\), \( x = (0+1)^2 = 1 \). When \( t = 1 \), \( x = (1+1)^2 = 4 \). Therefore, the range of \(x\) over the interval \([0, 1]\) is from 1 to 4.
03

Determine the range of \(y\)

Now find the values of \(y\) at the interval ends. When \(t = 0\), \( y = (0+2)^3 = 8 \). When \( t = 1 \), \( y = (1+2)^3 = 27 \). Hence, the range of \(y\) over the interval \([0, 1]\) is from 8 to 27.
04

Identify the curve's direction

Evaluate the coordinates as \(t\) moves from 0 to 1. The starting point when \( t = 0 \) is \((1, 8)\), and the ending point when \( t = 1 \) is \((4, 27)\). As \( t \) increases, \( x \) and \( y \) increase, indicating that the curve moves from bottom-left to top-right.
05

Sketch the graph

Plot the points \((1, 8)\) and \((4, 27)\) on a Cartesian plane. Draw a smooth curve beginning at \((1, 8)\) and ending at \((4, 27)\), representing the path dictated by the parametric equations. Include direction arrows along the curve to show movement is from the starting to the ending point.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Parametric Equations
Graphing parametric equations involves plotting points on a Cartesian plane. These points are determined by parameter values that typically vary over a specific interval. In the given exercise, we have the parametric equations \( x = (t+1)^2 \) and \( y = (t+2)^3 \), with the parameter \( t \) ranging from 0 to 1.

Firstly, understand that each value of \( t \) provides a pair of \( (x, y) \) coordinates. We substitute the values of \( t \) into each equation to find corresponding \( x \) and \( y \) values. As \( t \) varies, it maps out a trajectory or path on the plane.

Visualizing this path starts by calculating the \( (x, y) \) coordinates for key values of \( t \) within the interval \([0, 1]\). For example:
  • When \( t = 0 \), \( x = 1 \) and \( y = 8 \).
  • When \( t = 1 \), \( x = 4 \) and \( y = 27 \).
Plot these on the Cartesian plane.

Connect the points with a line or curve, which denotes how the coordinates change continuously as \( t \) progresses. This creates a graphical representation of the path dictated by the equations.
Curve Sketching
Curve sketching using parametric equations involves creating a visual graph or shape based on the trajectories described by parametric forms. With parametric equations, each variable is expressed as a function of a common parameter. This allows complex curves to be defined with simple expressions.

In our given set of parametric equations:\( x = (t+1)^2 \) and \( y = (t+2)^3 \), the task is to sketch the path described as \( t \) varies from 0 to 1. This involves:
  • Calculating the minimum and maximum values of \( x \) and \( y \), which were found to be from 1 to 4 and 8 to 27 respectively.
  • Recognizing that as \( t \) increases, both \( x \) and \( y \) values increase smoothly, suggesting a path that stretches from lower coordinates to higher ones.
To produce an accurate sketch, note the behavior of \( x \) and \( y \) as \( t \) changes in small increments. This helps in drawing a more precise and fluid curve.

For instance, the points calculated for \( t = 0 \) and \( t = 1 \) lay on a curve extending from lower-left to upper-right in the graph. By plotting these points and ensuring a smooth connection, you provide a clear depiction of the curve.
Direction of Curve in Parametric Graphs
The direction of a curve in parametric graphs indicates how the curve progresses as the parameter \( t \) changes. This is often shown using arrows on the graph, illustrating the path or movement along the curve.

In the exercise at hand, as \( t \) increases from 0 to 1, the curve's direction moves from the point \((1, 8)\) to the point \((4, 27)\). Hence, the movement is clearly from left-to-right and bottom-to-top. This directionality is crucial for understanding how the system described by the parametric equations unfolds over time.

For clarity while graphing:
  • Start by plotting the initial and final points defined by the boundary values of \( t \).
  • Draw arrows on the curve to visually indicate the direction of movement, which goes from \( t = 0 \) to \( t = 1 \).
The directional arrows serve as a guide, providing insight into how and where the curve shifts on the graph. Understanding this concept is essential for accurately interpreting parametric curves in mathematics and applied fields.

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Most popular questions from this chapter

In Exercises 1-20, graph the curve defined by the following sets of parametric equations. Be sure to indicate the direction of movement along the curve. $$ x=t^{3}+1, y=t^{3}-1, t \text { in }[-2,2] $$

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