/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 83 Find the polar equation that is ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the polar equation that is equivalent to a vertical line, \(x=a\).

Short Answer

Expert verified
The polar equation for a vertical line \(x=a\) is \(r \cos \theta = a\).

Step by step solution

01

Understanding the Problem

To find the polar equation equivalent to a vertical line in Cartesian coordinates, we start by understanding the given equation, which is a vertical line given by \(x = a\). Our goal is to convert this Cartesian equation into polar form.
02

The Polar Coordinate System

In polar coordinates, any point is represented as \((r, \theta)\), where \(r\) is the distance from the origin to the point, and \(\theta\) is the angle from the positive x-axis to the radius vector in a counterclockwise direction. The relationship between Cartesian and polar coordinates is given by the equations: \(x = r \cos \theta\) and \(y = r \sin \theta\).
03

Substitute Cartesian to Polar

Substitute the Cartesian equation \(x = a\) with the polar relation \(x = r \cos \theta\). This gives us the relation \(r \cos \theta = a\). This is the polar form of the given Cartesian equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cartesian Coordinates
The Cartesian coordinate system, named after the French mathematician René Descartes, is a two-dimensional plane formed by two perpendicular axes: the x-axis (horizontal) and the y-axis (vertical). Each point on this plane is defined by a pair of numerical coordinates \(x, y\). Imagine this as a grid where you can locate any point by moving a particular distance along the width (x) and height (y).

It's commonly used because of its straightforwardness and the ease of visualizing geometric concepts like lines, circles, and points. Mathematical functions and equations are often expressed using Cartesian coordinates, such as the equation of a vertical line, \(x = a\), where every point on the line has the same x-coordinate 'a', and any y-coordinate.

  • Vertical Lines: In this system, a vertical line means that all points have the same x-value, illustrating a constant horizontal position.
  • Simplicity: The system breaks down the position of any point into two orthogonal directions, which makes many mathematical operations simple to perform.
Conversion between Coordinate Systems
The conversion between Cartesian coordinates and polar coordinates is a pivotal concept when tackling problems where different forms better express the underlying geometry. Polar coordinates use a different approach, representing points based on their distance from a central origin and a corresponding angular direction.

To convert between these coordinate systems, employ the following relationships:
  • From Cartesian to Polar:
    • Distance, \( r = \sqrt{x^2 + y^2} \)
    • Angle, \( \theta = \arctan\left(\frac{y}{x}\right) \)
  • From Polar to Cartesian:
    • Horizontal coordinate, \( x = r \cos \theta \)
    • Vertical coordinate, \( y = r \sin \theta \)
Understanding these conversions is crucial for solving problems in physics, engineering, and mathematics where spherical, circular, or spiral shapes may be more naturally described in one system over the other.
Polar Equation of a Vertical Line
The problem involves converting the vertical line equation \(x = a\) from Cartesian coordinates into polar coordinates. In polar coordinates, each point on the plane is expressed by \( (r, \theta) \), so we must translate the given linear equation using this system's descriptors.

The key relationship in this conversion is found through the equation \(x = r \cos \theta\). Substituting the Cartesian condition \(x = a\) into this relationship gives us \(r \cos \theta = a\). This equation describes the set of points in polar coordinates that make up the vertical line in equal measure to its Cartesian counterpart.

  • Geometric Interpretation: The line is represented by analyzing the radial distance and angular position while keeping the product with the cosine of the angle constant.
  • Equation Adjustments: Depending on the specific value of \(a\), you adjust \(r\) and \(\theta\) to illustrate the line appropriately in a polar grid.
This equation elegantly captures the nature of the vertical line while employing the polar system’s radial-angle framework.

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Most popular questions from this chapter

For Exercises 77 and 78, refer to the following: The sword artistry of the samurai is legendary in Japanese folklore and myth. The elegance with which a samurai could wield a sword rivals the grace exhibited by modern figure skaters. In more modern times, such legends have been rendered digitally in many different video games (e.g., Ominusha). In order to make the characters realistically move across the screen-and in particular, wield various sword motions true to the legends-trigonometric functions are extensively used in constructing the underlying graphics module. One famous movement is a figure eight, swept out with two hands on the sword. The actual path of the tip of the blade as the movement progresses in this figure-eight motion depends essentially on the length \(L\) of the sword and the speed with which the figure is swept out. Such a path is modeled using a polar equation of the form \(r^{2}(\theta)=L \cos (A \theta)\) or \(r^{2}(\theta)=L \sin (A \theta), \theta_{1} \leq \theta \leq \theta_{2}\). Video Games. Write a polar equation that would describe the motion of a sword 12 units long that makes 8 complete motions in \([0,2 \pi]\).

In Exercises 1-20, graph the curve defined by the following sets of parametric equations. Be sure to indicate the direction of movement along the curve. $$ x=t^{3}+1, y=t^{3}-1, t \text { in }[-2,2] $$

For Exercises 47 and 48 , refer to the following: Modern amusement park rides are often designed to push the envelope in terms of speed, angle, and ultimately \(g\)-force, and usually take the form of gargantuan roller coasters or skyscraping towers. However, even just a couple of decades ago, such creations were depicted only in fantasy-type drawings, with their creators never truly believing their construction would become a reality. Nevertheless, thrill rides still capable of nauseating any would-be rider were still able to be constructed; one example is the Calypso. This ride is a not-too-distant cousin of the better-known Scrambler. It consists of four rotating arms (instead of three like the Scrambler), and on each of these arms, four cars (equally spaced around the circumference of a circular frame) are attached. Once in motion, the main piston to which the four arms are connected rotates clockwise, while each of the four arms themselves rotates counterclockwise. The combined motion appears as a blur to any onlooker from the crowd, but the motion of a single rider is much less chaotic. In fact, a single rider's path can be modeled by the following graph: The equation of this graph is defined parametrically by $$ \begin{aligned} &x(t)=A \cos t+B \cos (-3 t) \\ &y(t)=A \sin t+B \sin (-3 t), 0 \leq t \leq 2 \pi \end{aligned} $$ Amusement Rides. What is the location of the rider at \(t=0, t=\frac{\pi}{2}, t=\pi, t=\frac{3 \pi}{2}\), and \(t=2 \pi\) ?

For Exercises 73 and 74, refer to the following: The lemniscate motion occurs naturally in the flapping of birds' wings. The bird's vertical lift and wing sweep create the distinctive figure-eight pattern. The patterns vary with different wing profiles. Flapping Wings of Birds. Compare the two following possible lemniscate patterns by graphing them on the same polar graph: \(r^{2}=4 \cos (2 \theta)\) and \(r^{2}=4 \cos (2 \theta+2)\).

In Exercises 21-36, each set of parametric equations defines a plane curve. Find an equation in rectangular form that also corresponds to the plane curve. $$ x=\cos t, y=-\cos ^{2} t $$

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