Chapter 8: Problem 67
$$ \text { For Exercises 65-76, simplify and express in standard form. } $$ $$ i^{40} $$
Short Answer
Expert verified
The standard form of \( i^{40} \) is 1.
Step by step solution
01
Understand the Imaginary Number
The imaginary unit is denoted as \( i \). By definition, \( i \) is the square root of -1, so \( i^2 = -1 \). Powers of \( i \) follow a cyclic pattern: \( i^1 = i \), \( i^2 = -1 \), \( i^3 = -i \), and \( i^4 = 1 \). This cycle repeats every four powers.
02
Determine the Power in the Cycle
To find \( i^{40} \), identify where it falls in the cycle of powers. Since the powers of \( i \) repeat every 4 terms, divide 40 by 4. Calculate the remainder to determine the equivalent power.
03
Calculate the Remainder
Perform the division: \( 40 \div 4 = 10 \) with a remainder of 0. This means that \( i^{40} \) corresponds to \( i^0 \) in the cycle.
04
Simplify Using the Cycle
Since \( i^0 = 1 \) within the cycle of powers, we know that \( i^{40} = 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Imaginary Unit
The imaginary unit, denoted by the symbol \( i \), is a fundamental concept in mathematics, especially in the field of complex numbers. The term 'imaginary' might sound elusive or non-existent, but the imaginary unit is a well-defined mathematical entity. By definition, \( i \) is the square root of \(-1\). This is expressed as \( i = \sqrt{-1} \). This definition allows us to work with square roots of negative numbers, which are not possible within the realm of real numbers.
Using this property, when you square \( i \), you get a real number: \( i^2 = -1 \). This is a critical identity that supports further calculations involving imaginary numbers. In essence:
Using this property, when you square \( i \), you get a real number: \( i^2 = -1 \). This is a critical identity that supports further calculations involving imaginary numbers. In essence:
- \( i^1 = i \)
- \( i^2 = -1 \)
- \( i^3 = -i \)
- \( i^4 = 1 \)
Cyclic Pattern
When dealing with powers of the imaginary unit \( i \), it's essential to recognize the cyclic pattern it follows. This cyclic nature emerges from the repetitive results when multiplying \( i \) by itself. Every four powers, this pattern repeats, making it quite predictable.
Here's how it unfolds:
To find any power like \( i^{40} \), you can divide 40 by 4 to find the remainder, which tells you where the power falls within the cycle. Since 40 divided by 4 leaves a remainder of 0, it corresponds to \( i^4 \), which we know equals 1.
Here's how it unfolds:
- \( i^1 = i \)
- \( i^2 = -1 \)
- \( i^3 = -i \)
- \( i^4 = 1 \)
To find any power like \( i^{40} \), you can divide 40 by 4 to find the remainder, which tells you where the power falls within the cycle. Since 40 divided by 4 leaves a remainder of 0, it corresponds to \( i^4 \), which we know equals 1.
Simplifying Powers of i
Simplifying powers of \( i \) is made easy due to the cyclic pattern described earlier. Every time you encounter a power of \( i \) that's larger than 4, you can leverage this cycle to quickly find the simplest form of the expression.
The core idea is to reduce the given power to a remainder that fits within the cycle range of 1 to 4 by using modular arithmetic, specifically dividing by 4. Here's a step-by-step approach:
The core idea is to reduce the given power to a remainder that fits within the cycle range of 1 to 4 by using modular arithmetic, specifically dividing by 4. Here's a step-by-step approach:
- Take the exponent you have, for instance, 40.
- Divide by 4 and note the remainder.
- 0, the power reduces to \( i^4 \): therefore \( i^{40} = 1 \)
- 1, it reduces to \( i \)
- 2, it reduces to \( -1 \)
- 3, it reduces to \( -i \)