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$$ \text { For Exercises 65-76, simplify and express in standard form. } $$ $$ i^{15} $$

Short Answer

Expert verified
The simplified form of \( i^{15} \) is \(-i\).

Step by step solution

01

Understand the Properties of i

The imaginary unit \( i \) is defined by the property \( i^2 = -1 \). From this, we derive that \( i^3 = i^2 \cdot i = -i \) and \( i^4 = i^2 \cdot i^2 = 1 \). Notice that every power of \( i \) repeats in a cycle of length 4: \( i, -1, -i, 1 \).
02

Reduce the Exponent 15 Modulo 4

Since the powers of \( i \) repeat every 4 terms, calculating \( i^{15} \) is simplified by finding \( 15 \mod 4 \). Dividing 15 by 4 gives a remainder of 3. Therefore, \( i^{15} = i^3 \).
03

Simplify Using the Cycle Property

From Step 1, we know \( i^3 = -i \). Therefore, \( i^{15} = i^3 = -i \).
04

Express in Standard Form

The standard form for complex numbers is \( a + bi \). Since \( i^{15} = -i \), it can be expressed as \( 0 - 1i \) or just \( -i \) in standard form.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Imaginary Unit
The concept of imaginary numbers begins with the imaginary unit, denoted as \(i\). The defining property of \(i\) is that it is a solution to the equation \(x^2 = -1\).
The imaginary unit is used to expand our understanding of number systems beyond real numbers. In essence, \(i\) represents the square root of negative one, a number that does not exist in the set of real numbers.

This leads us to a new set of numbers called complex numbers. These are expressed as a combination of real and imaginary parts, typically in the form \(a + bi\), where both \(a\) and \(b\) are real numbers. The imaginary unit \(i\) itself does not have a numeric value in ordinary sense but allows for computations that involve the roots of negative numbers.
Powers of i
Understanding the powers of \(i\) is crucial to simplifying expressions involving complex numbers. The powers of \(i\) follow a predictable cycle of four:
  • \(i^1 = i\)
  • \(i^2 = -1\)
  • \(i^3 = -i\)
  • \(i^4 = 1\)
This cycle repeats for higher powers. For example, \(i^5\) begins with \(i\) again, and the pattern continues: \(i, -1, -i, 1, i, -1, -i, 1, \ldots\).

Knowing this cycle helps in quickly simplifying powers of \(i\) to their simplest form. When you encounter a problem that requires you to evaluate higher powers of \(i\), you can reduce the power modulo 4 (which we'll discuss later) to find the equivalent power in the basic cycle. This simplification forms the basis for many operations with complex numbers.
Standard Form
Complex numbers are typically expressed in what is called the 'standard form.' This form is written as \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part.
Expressing numbers in standard form makes it easier to perform arithmetic operations such as addition, subtraction, multiplication, and division on complex numbers.

To express a pure imaginary number in standard form, you simply set the real part \(a\) to zero. For example, the expression \(i^{15}\) simplifies to \(-i\), which can be expressed in standard form as \(0 - 1i\) or simply \(-i\). The standard form helps in organizing the components of complex numbers so they can be easily compared or manipulated.
Modulo Arithmetic
Modulo arithmetic is a mathematical technique used to simplify expressions by focusing on the remainder when dividing by a number, in this case, 4. This technique is particularly useful when dealing with powers of the imaginary unit \(i\) because of its repeating cycle every four powers.
To simplify \(i^{15}\), we perform the division of 15 by 4, which gives us a quotient and a remainder. It's the remainder that is most important here:
  • 15 divided by 4 equals 3 with a remainder of 3
This tells us that \(i^{15} = i^3\).

Modulo arithmetic allows us to reduce any power of \(i\) to one of the first four powers \(i, -1, -i, 1\) by simply calculating the remainder when the exponent is divided by 4. Using modulo makes problems involving complex numbers much simpler and less time-consuming.

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Most popular questions from this chapter

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