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In Exercises 45-68, graph each equation. In Exercises 63-68, convert the equation from polar to rectangular form first and identify the resulting equation as a line, parabola, or circle. $$ r=-2 \cos \theta $$

Short Answer

Expert verified
The resulting equation is a line, specifically \( x = 0 \).

Step by step solution

01

Recall Polar to Rectangular Conversion Formulas

In polar coordinates, the formulas to convert to rectangular coordinates are:\[ x = r \cos\theta \] \[ y = r \sin\theta \] \[ r^2 = x^2 + y^2 \].
02

Substitute and Rearrange the Given Equation

Given the polar equation \( r = -2 \cos \theta \), we substitute \( r = \frac{x}{\cos \theta} \) to obtain:\[ \frac{x}{\cos \theta} = -2 \cos \theta \].Simplifying this gives:\[ x = -2\cos^2 \theta \].
03

Convert to Rectangular Equation Using Simplification

Use the identity \( \cos^2 \theta = \frac{x^2}{x^2 + y^2} \), we substitute to get:\[ x = -2 \times \frac{x^2}{x^2 + y^2} \]. Multiplying through by \( x^2 + y^2 \), we have:\[ x(x^2 + y^2) = -2x^2 \].Rearrange to get:\[ x^3 + xy^2 + 2x^2 = 0 \].
04

Simplify the Equation

Factor the equation from Step 3:\[ x(x^2 + 2x + y^2) = 0 \].This can be simplified to find that either \( x = 0 \) or \( x^2 + 2x + y^2 = 0 \).
05

Identify the Equation

Since \( x = 0 \) represents a vertical line at \( x = 0 \), and the term \( x^2 + 2x + y^2 = 0 \) is nonstandard and doesn't represent a simple conic section, the predominant solution is the line \( x = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
Polar coordinates are a method for representing points in a plane using a distance and an angle. Instead of using a Cartesian coordinate system with an "x" and "y" axis, this system uses a radius \( r \) and an angle \( \theta \). Here’s how they work:

- \( r \): This is the distance from the origin (center of the coordinate system) to the point. It is always a non-negative value.
- \( \theta \): This is the angle measured from the positive x-axis to the line connecting the origin to the point. The angle is usually measured in radians.

This system is especially useful for problems involving circular or rotational symmetry. By converting a problem to polar coordinates, complex patterns can become simpler and easier to understand. It's like using the right tool for the job, ensuring you handle problems like rotations with greater ease.
Rectangular Coordinates
Also known as Cartesian coordinates, rectangular coordinates are the most common way to describe points in a plane. Each point is identified by an ordered pair \((x, y)\).

- "x" coordinate: The horizontal distance from the origin. Essentially tells you how far to move right or left.
- "y" coordinate: The vertical distance from the origin. Indicates how far to move up or down.

This system is incredibly useful for graphs, equations, and models in most mathematical contexts. For example, plotting a circle or a straight line is typically done in rectangular coordinates as it's straightforward and intuitive. Rectangular coordinates are integral in not just math, but also fields like physics and engineering, where precise location plotting is crucial.
Trigonometric Identities
Trigonometric identities involve relationships between sine, cosine, and other trigonometric functions that are incredibly useful in simplifying complex equations. These identities allow for conversion between polar and rectangular forms.

Some important identities include:
  • The Pythagorean identity: \( \cos^2\theta + \sin^2\theta = 1 \)
  • Expression of \( \cos^2\theta \) in terms of \( x \) and \( r \): \( \cos^2\theta = \frac{x^2}{x^2 + y^2} \)
  • The basic \( x = r \cos\theta \) and \( y = r \sin\theta \) formulas.
These tools help in the conversion process and ensure that every trigonometric equation can be interpreted in multiple forms. They are not just formulas but keys to understanding and bridging different mathematical worlds.
Equation Conversion
Equation conversion involves transforming a mathematical expression from one form to another. In this exercise, we are converting a polar equation to a rectangular form. This involves using the trigonometric identities and conversion formulas we've discussed.

The process generally follows these steps:
  • Substitute polar expressions like \( r = -2 \cos \theta \) into known formulas.
  • Simplify the expression by applying identities like \( \cos^2\theta = \frac{x^2}{x^2 + y^2} \).
  • Rearrange and simplify further to obtain a clean rectangular form, such as \( x^3 + xy^2 + 2x^2 = 0 \).
Ultimately, this process organizes and expresses the geometry of equations in terms familiar to the rectangular coordinate system. Understanding both forms allows mathematicians to choose the most efficient path to solving equations, depending on the context. Often the resulting equation can provide additional insights, such as identifying the graph's shape or symmetry.

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Most popular questions from this chapter

For Exercises 37-46, recall that the flight of a projectile can be modeled with the parametric equations $$ x=\left(v_{0} \cos \theta\right) t \quad y=-16 t^{2}+\left(v_{0} \sin \theta\right) t+h $$ where \(t\) is in seconds, \(v_{0}\) is the initial velocity in feet per second, \(\theta\) is the initial angle with the horizontal, and \(h\) is the initial height above ground, where \(x\) and \(y\) are in feet. Flight of a Baseball. A baseball is hit at an initial speed of \(105 \mathrm{mph}\) and an angle of \(20^{\circ}\) at a height of 3 feet above the ground. If home plate is 420 feet from the back fence, which is 15 feet tall, will the baseball clear the back fence for a home run?

In Exercises 1-20, graph the curve defined by the following sets of parametric equations. Be sure to indicate the direction of movement along the curve. $$ x=1, y=\sin t, t \text { in }[-2 \pi, 2 \pi] $$

Bicycle Racing. A boy on a bicycle racing around an oval track has a position given by the equations \(x=-100 \sin \left(\frac{t}{4}\right)\) and \(y=75 \cos \left(\frac{t}{4}\right)\), where \(x\) and \(y\) are the horizontal and vertical positions in feet relative to the center of the track \(t\) seconds after the start of the race. Another racer has a position given by the equations \(x=-100 \sin \left(\frac{t}{3}\right)\) and \(y=75 \cos \left(\frac{t}{3}\right)\). Which racer is going faster?

In Exercises 21-36, each set of parametric equations defines a plane curve. Find an equation in rectangular form that also corresponds to the plane curve. $$ x=4\left(t^{2}+1\right), y=1-t^{2} $$

For Exercises 47 and 48 , refer to the following: Modern amusement park rides are often designed to push the envelope in terms of speed, angle, and ultimately \(g\)-force, and usually take the form of gargantuan roller coasters or skyscraping towers. However, even just a couple of decades ago, such creations were depicted only in fantasy-type drawings, with their creators never truly believing their construction would become a reality. Nevertheless, thrill rides still capable of nauseating any would-be rider were still able to be constructed; one example is the Calypso. This ride is a not-too-distant cousin of the better-known Scrambler. It consists of four rotating arms (instead of three like the Scrambler), and on each of these arms, four cars (equally spaced around the circumference of a circular frame) are attached. Once in motion, the main piston to which the four arms are connected rotates clockwise, while each of the four arms themselves rotates counterclockwise. The combined motion appears as a blur to any onlooker from the crowd, but the motion of a single rider is much less chaotic. In fact, a single rider's path can be modeled by the following graph: The equation of this graph is defined parametrically by $$ \begin{aligned} &x(t)=A \cos t+B \cos (-3 t) \\ &y(t)=A \sin t+B \sin (-3 t), 0 \leq t \leq 2 \pi \end{aligned} $$ Amusement Rides. What is the location of the rider at \(t=0, t=\frac{\pi}{2}, t=\pi, t=\frac{3 \pi}{2}\), and \(t=2 \pi\) ?

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