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For Exercises \(41-48\), for each complex number \(z\), write the complex conjugate \(\bar{z}\), and find \(z \bar{z}\). $$ z=2+5 i $$

Short Answer

Expert verified
Complex conjugate of \( z = 2 + 5i \) is \( \bar{z} = 2 - 5i \), and \( z \bar{z} = 29 \).

Step by step solution

01

Understanding the Complex Conjugate

The complex conjugate of a complex number is obtained by changing the sign of the imaginary part. For a complex number \( z = a + bi \), the complex conjugate is \( \bar{z} = a - bi \).
02

Identify the Real and Imaginary Parts

Given the complex number \( z = 2 + 5i \), identify the real part, \( a = 2 \), and the imaginary part, \( b = 5 \).
03

Determine the Complex Conjugate

Using the identified parts, the complex conjugate \( \bar{z} \) is \( 2 - 5i \).
04

Calculate the Product of z and its Conjugate

Multiply the complex number \( z \) by its conjugate \( \bar{z} \). This is given by the expression: \[ z \bar{z} = (2 + 5i)(2 - 5i) \].
05

Use the Difference of Squares Formula

Apply the formula \( (a+bi)(a-bi) = a^2 + b^2 \). For \( z \bar{z} = (2 + 5i)(2 - 5i) \), calculate it as \( 2^2 + 5^2 \).
06

Perform the Calculations

Calculate \( 2^2 = 4 \) and \( 5^2 = 25 \). Then sum these to get \( 4 + 25 = 29 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Conjugate
A complex conjugate is an important concept in the world of complex numbers. When you have a complex number, it usually has two parts: a real part and an imaginary part. Let's take a closer look at this.
For any complex number in the form of \( z = a + bi \), the complex conjugate, written as \( \bar{z} \), is simply \( a - bi \). This means that you only change the sign of the imaginary part to find the conjugate.

Why is the complex conjugate important? It helps us to perform several operations with complex numbers more easily. One main reason for using it is to find the magnitude (or modulus) of a complex number which is useful in mathematics and physics. To get \( z \bar{z} \), which is always a real number, you can simplify calculations and understand the behavior of the number better.
In our example, for \( z = 2 + 5i \), the conjugate would be \( 2 - 5i \). Understanding complex conjugates makes it a lot easier to work with and visualize complex numbers.
Imaginary Numbers
Imaginary numbers can initially seem perplexing because they don't have a tangible, real-world manifestation. However, they're an essential part of complex numbers and deeper mathematical concepts.
Imaginary numbers revolve around the idea of the square root of negative numbers. Conventionally, numbers like \( \sqrt{-1} \) didn't have solutions in real numbers, until the invention of imaginary numbers. The imaginary unit, represented as \( i \), is defined such that \( i^2 = -1 \). Thus, any imaginary number is a real number multiplied by \( i \), such as \( 5i \) in our equation. This means the number doesn't exist on the regular number line.

Where do imaginary numbers fit? They are often paired with real numbers to form complex numbers, like \( z = a + bi \), providing a more unified approach to solving quadratic equations and various mathematical problems. The imaginary part (\( bi \)) gives complex numbers their unique two-dimensional nature, which can be highly beneficial for electrical engineering, quantum physics, and more. In the given example, the imaginary piece is \( 5i \). Knowing how to work with imaginary numbers is crucial for delving into the world of complex numbers.
Multiplication of Complex Numbers
When it comes to multiplying complex numbers, the operation is similar to expanding two binomials using the distributive property. The product of a complex number and its conjugate is particularly straightforward because it results in a real number.
Take the complex number \( z = 2 + 5i \) and its complex conjugate \( \bar{z} = 2 - 5i \). Their multiplication is expressed as \( (2 + 5i)(2 - 5i) \).

By applying the difference of squares formula, \[(a+bi)(a-bi) = a^2 + b^2,\]
you simplify the product of \( z \) and \( \bar{z} \) to \( 2^2 + 5^2 \). This is because the imaginary components cancel each other out, leaving you with a sum of squares of the real and imaginary parts. Calculating this leads to \( 4 + 25 = 29 \).
Multiplying a complex number by its conjugate is a powerful tool, as it gives its modulus squared and ensures results remain on the real number line. Understanding this process is key to mastering complex arithmetic and aids in other operations, such as division of complex numbers.

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