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In Exercises 13-28, express each complex number in polar form. $$ \frac{7}{16}+\frac{7}{16} i $$

Short Answer

Expert verified
The polar form is \( \frac{\sqrt{98}}{16} \left( \cos\left(\frac{\pi}{4}\right) + i\sin\left(\frac{\pi}{4}\right) \right) \).

Step by step solution

01

Identify the complex number

The complex number given is \( \frac{7}{16} + \frac{7}{16}i \). This can be expressed in the form \( a + bi \), where \( a = \frac{7}{16} \) and \( b = \frac{7}{16} \).
02

Calculate the magnitude of the complex number

The magnitude \( r \) of a complex number \( a + bi \) is given by the formula \( r = \sqrt{a^2 + b^2} \). Substituting the values, we have \( r = \sqrt{\left( \frac{7}{16} \right)^2 + \left( \frac{7}{16} \right)^2} \).
03

Simplify to find the magnitude

Calculate \( r = \sqrt{\frac{49}{256} + \frac{49}{256}} = \sqrt{\frac{98}{256}} \). Simplify further: \( r = \sqrt{\frac{98}{256}} = \frac{\sqrt{98}}{16} \).
04

Calculate the angle in radians

The angle \( \theta \) can be found using \( \tan(\theta) = \frac{b}{a} \). Here, \( \tan(\theta) = \frac{\frac{7}{16}}{\frac{7}{16}} = 1 \). Therefore, \( \theta = \frac{\pi}{4} \) given the complex number is in the first quadrant.
05

Write the polar form of the complex number

The polar form of a complex number is \( r(\cos(\theta) + i\sin(\theta)) \). Substituting the values we got: \( \frac{\sqrt{98}}{16} \left( \cos\left(\frac{\pi}{4}\right) + i\sin\left(\frac{\pi}{4}\right) \right) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Numbers
Complex numbers are numbers that have both a real part and an imaginary part. They have the general form \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit, satisfying \( i^2 = -1 \). In our exercise, we are asked to convert \( \frac{7}{16} + \frac{7}{16}i \) into polar form. Here, \( a \) and \( b \) are both equal to \( \frac{7}{16} \), representing the real and imaginary components respectively.

Some key points about complex numbers include:
  • They can be represented on the complex plane, where the x-axis is the real axis and the y-axis is the imaginary axis.
  • They are essential in various fields, including engineering and physics, for representing oscillatory and wave functions.
  • Complex numbers can be added, subtracted, and multiplied like ordinary numbers, but division involves expressing them in polar form or using complex conjugates.
Magnitude and Angle
The magnitude of a complex number, sometimes called the modulus, is the distance from the origin to the point \( (a, b) \) on the complex plane. It is calculated using the formula \( r = \sqrt{a^2 + b^2} \). In our example, we calculate the magnitude \( r \) of \( \frac{7}{16} + \frac{7}{16}i \) and find it is \( \frac{\sqrt{98}}{16} \).

Understanding the angle \( \theta \), also known as the argument, is vital for expressing complex numbers in polar form. The angle is measured from the positive real axis to the line representing the complex number. It can be computed using the tangent function: \( \tan(\theta) = \frac{b}{a} \). For the exercise, since \( \frac{b}{a} \) is 1, \( \theta \) is \( \frac{\pi}{4} \). This angle places the complex number in the first quadrant of the polar coordinate system.

Key points for calculating magnitude and angle include:
  • Magnitude gives the overall size of the number, helping in analyzing the amplitude in oscillatory applications.
  • The angle defines the direction of the number in its polar form, influencing the phases in wave mechanics.
First Quadrant
The first quadrant is the section of the complex plane where both the real and imaginary parts of the complex number are positive. It is the region where the angles of complex numbers are between \( 0 \) and \( \frac{\pi}{2} \) radians. In our exercise, the angle \( \theta = \frac{\pi}{4} \) confirms that the number \( \frac{7}{16} + \frac{7}{16}i \) lies in the first quadrant.

Being in the first quadrant has several implications:
  • Numbers here naturally have positive real and imaginary components.
  • The conversion from rectangular to polar form in this quadrant is typically straightforward since \( \theta \) can be directly obtained from \( \tan^{-1}(\frac{b}{a}) \).
  • The first quadrant is often considered the default starting point when studying polar coordinates due to its simplicity and symmetry.

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Most popular questions from this chapter

In Exercises 55 and 56, explain the mistake that is made. Find the rectangular equation that corresponds to the plane curve defined by the parametric equations \(x=t+1\) and \(y=\sqrt{t}\). Describe the plane curve. Solution: Square \(y=\sqrt{t}\). \(y^{2}=t\) Substitute \(t=y^{2}\) into \(x=t+1 . \quad x=y^{2}+1\) The graph of \(x=y^{2}+1\) is a parabola opening to the right with vertex at \((1,0)\). This is incorrect. What mistake was made?

Bullet Fired. A gun is fired from the ground at an angle of \(60^{\circ}\), and the bullet has an initial speed of 2000 feet per second. How high does the bullet go? What is the horizontal (ground) distance between where the gun was fired and where the bullet hit the ground?

For Exercises 77 and 78, refer to the following: The sword artistry of the samurai is legendary in Japanese folklore and myth. The elegance with which a samurai could wield a sword rivals the grace exhibited by modern figure skaters. In more modern times, such legends have been rendered digitally in many different video games (e.g., Ominusha). In order to make the characters realistically move across the screen-and in particular, wield various sword motions true to the legends-trigonometric functions are extensively used in constructing the underlying graphics module. One famous movement is a figure eight, swept out with two hands on the sword. The actual path of the tip of the blade as the movement progresses in this figure-eight motion depends essentially on the length \(L\) of the sword and the speed with which the figure is swept out. Such a path is modeled using a polar equation of the form \(r^{2}(\theta)=L \cos (A \theta)\) or \(r^{2}(\theta)=L \sin (A \theta), \theta_{1} \leq \theta \leq \theta_{2}\). Video Games. Graph the following equations: a. \(r^{2}(\theta)=5 \cos \theta, 0 \leq \theta \leq 2 \pi\) b. \(r^{2}(\theta)=5 \cos (2 \theta), 0 \leq \theta \leq \pi\) c. \(r^{2}(\theta)=5 \cos (4 \theta), 0 \leq \theta \leq \frac{\pi}{2}\) What do you notice about all of these graphs? Suppose that the movement of the tip of the sword in a game is governed by these graphs. Describe what happens if you change the domain in (b) and (c) to \(0 \leq \theta \leq 2 \pi\).

Dwarf Planet Pluto. The dwarf planet Pluto travels in an elliptical orbit that can be modeled with the polar equation \(r=\frac{29.62(1+0.249)}{1-0.249 \cos \theta} .\) Sketch the graph of Pluto's orbit.

In Exercises 45-68, graph each equation. In Exercises 63-68, convert the equation from polar to rectangular form first and identify the resulting equation as a line, parabola, or circle. $$ r=4 \theta $$

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