Chapter 8: Problem 2
In Exercises 1-20, graph the curve defined by the following sets of parametric equations. Be sure to indicate the direction of movement along the curve. $$ x=3 t, y=t^{2}-1, t \text { in }[0,4] $$
Short Answer
Expert verified
Graph the curve passing through points (0, -1), (3, 0), (6, 3), (9, 8), (12, 15) with arrows showing it moves from left to right.
Step by step solution
01
Understanding the Parametric Equations
We begin with the parametric equations given as \( x = 3t \) and \( y = t^2 - 1 \). The parameter \( t \) ranges from 0 to 4. This means we need to compute the values of \( x \) and \( y \) for each value of \( t \) within this range to understand the shape of the curve and its path.
02
Calculating Key Points
Let's calculate a few key points to help graph the curve. For \( t = 0 \), \( x = 3 \times 0 = 0 \) and \( y = 0^2 - 1 = -1 \). For \( t = 1 \), \( x = 3 \times 1 = 3 \) and \( y = 1^2 - 1 = 0 \). For \( t = 2 \), \( x = 3 \times 2 = 6 \) and \( y = 2^2 - 1 = 3 \). Continue similarly for \( t = 3 \) and \( t = 4 \) to get more points.
03
Plotting the Points
Plot these points on a graph. You should have points \((0, -1)\), \((3, 0)\), \((6, 3)\), \((9, 8)\), and \((12, 15)\). Connect these points smoothly to form a curve. This shape is a parabolic curve opening upwards.
04
Indicating the Direction
The direction of the curve is determined by the increasing values of \( t \). As \( t \) increases from 0 to 4, \( x \) and \( y \) increase. Therefore, the curve moves from left to right as you increase \( t \) from 0 to 4. Indicate this direction on the graph with arrows along the curve.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Equations
Parametric equations offer a unique way to describe curves in the coordinate plane. Unlike standard Cartesian equations, which relate \( x \) and \( y \) directly, parametric equations use a parameter, usually denoted as \( t \), to express both \( x \) and \( y \). For example, in our exercise, the equations are \( x = 3t \) and \( y = t^2 - 1 \). These equations allow each point on the curve to be represented as a function of \( t \). This method effectively describes curves that may be difficult to express with a single equation in \( x \) and \( y \). Parametric equations can make it easier to sketch complex shapes and patterns, like spirals or ellipses, by manipulating the parameter \( t \).
Graphing Curves
Graphing parametric curves involves calculating specific coordinates for different values of the parameter \( t \). In our given problem, the range for \( t \) is from 0 to 4. We need to compute both \( x \) and \( y \) coordinates for specific \( t \) values to plot and sketch the curve correctly. To start, compute the points as shown:
- For \( t=0 \), \( (x, y) = (0, -1) \)
- For \( t=1 \), \( (x, y) = (3, 0) \)
- For \( t=2 \), \( (x, y) = (6, 3) \)
- For \( t=3 \), \( (x, y) = (9, 8) \)
- For \( t=4 \), \( (x, y) = (12, 15) \)
Direction of Parametric Graphs
The direction of a parametric graph indicates how the curve progresses as the parameter \( t \) changes. For any parametric equation, observing how \( x \) and \( y \) change as \( t \) increases is key to identifying the curve's direction. In this exercise, as \( t \) varies from 0 to 4:
- \( x \) moves from 0 to 12
- \( y \) moves from -1 to 15
Calculating Key Points
Key points on a parametric curve serve as guideposts for accurately drawing the curve. To find key points, substitute several distinct values of \( t \) within the defined range (0 to 4 in our situation) into the parametric equations \( x = 3t \) and \( y = t^2 - 1 \). Record the \( (x, y) \) pairs calculated:
- \( t = 0 \) leads to the point \((0, -1)\)
- \( t = 1 \) leads to the point \((3, 0)\)
- \( t = 2 \) leads to the point \((6, 3)\)
- \( t = 3 \) leads to the point \((9, 8)\)
- \( t = 4 \) leads to the point \((12, 15)\)