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In Exercises \(11-20\), convert each point given in rectangular coordinates to exact polar coordinates. Assume \(0 \leq \theta<2 \pi\). $$ (-4,4) $$

Short Answer

Expert verified
\((4\sqrt{2}, \frac{3\pi}{4})\)

Step by step solution

01

Identify Rectangular Coordinates

The point given is in rectangular coordinates: \((-4, 4)\). This means the x-coordinate is -4 and the y-coordinate is 4.
02

Use the Formulas for Polar Coordinates

Polar coordinates \((r, \theta)\) are related to rectangular coordinates \((x, y)\) by the formulas: \(r = \sqrt{x^2 + y^2}\) and \(\theta = \tan^{-1}\left(\frac{y}{x}\right)\).
03

Calculate the Radius

Substitute \(x = -4\) and \(y = 4\) into the formula for \(r\):\[r = \sqrt{(-4)^2 + 4^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2}.\]
04

Calculate the Angle

Using the formula \(\theta = \tan^{-1}\left(\frac{y}{x}\right)\), substitute \(x = -4\) and \(y = 4\):\[\theta = \tan^{-1}\left(\frac{4}{-4}\right) = \tan^{-1}(-1).\]Since the point is in the second quadrant where the tangent is negative, \(\theta = \pi - \frac{\pi}{4} = \frac{3\pi}{4}\).
05

Write the Polar Coordinates

The polar coordinates are \((r, \theta) = \left(4\sqrt{2}, \frac{3\pi}{4}\right)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rectangular Coordinates
Rectangular coordinates are an essential way to depict points on a plane using two values: the x-coordinate and the y-coordinate. These coordinates tell us exactly how far and in which direction a point is located from the origin (where the x-axis and y-axis meet). For example, the point \((-4, 4)\) is described by moving 4 units to the left (because of the negative sign) on the x-axis and 4 units up on the y-axis.
Using rectangular coordinates is very intuitive as it resembles the grid patterns we often see in graphs or maps. This coordinate system is also known as the Cartesian coordinate system, named after the mathematician René Descartes.
Radius Calculation
Calculating the radius in polar coordinates involves determining the distance from the origin to the given point in rectangular coordinates. This distance (or radius) can be calculated using the Pythagorean theorem. In general, the formula to find the radius \(r\) is:\[r = \sqrt{x^2 + y^2}\]Using the point \((-4, 4)\), we substitute:
  • \(x = -4\)
  • \(y = 4\)
We then calculate:\[r = \sqrt{(-4)^2 + 4^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2}.\]This tells us that the point is \(4\sqrt{2}\) units away from the origin. Calculating the radius is a crucial step in converting to polar coordinates since it provides a rotational distance that is consistent regardless of the point's location.
Angle Calculation
Finding the angle \(\theta\) in polar coordinates involves determining the angle a line from the origin to the point makes with the positive x-axis. For this, you use the inverse tangent function, represented as \(\tan^{-1}\). The angle is calculated using the formula:\[\theta = \tan^{-1}\left(\frac{y}{x}\right)\]By substituting \(x = -4\)and\(y = 4\)for our given point, we calculate:\[\theta = \tan^{-1}\left(\frac{4}{-4}\right) = \tan^{-1}(-1).\]Since our point is located in the second quadrant (where x is negative and y is positive), it is important to adjust the angle accordingly. Typically, \(\tan^{-1}(-1)\) gives \(-\frac{\pi}{4}\), but in the second quadrant, the angle is: \(\pi - \frac{\pi}{4} = \frac{3\pi}{4}\).
Correctly finding \(\theta\) ensures the point's accurate angular direction in polar coordinates.
Trigonometric Functions
Trigonometric functions such as sine, cosine, and tangent are vital when working with both rectangular and polar coordinates. They allow us to describe relationships between angles and distances in a right triangle, which is crucial for converting coordinates. In our context:
  • \(\sin(\theta) = \frac{\text{opposite side}}{\text{hypotenuse}}\)
  • \(\cos(\theta) = \frac{\text{adjacent side}}{\text{hypotenuse}}\)
  • \(\tan(\theta) = \frac{\text{opposite side}}{\text{adjacent side}}\)
When converting coordinates, the tangent function's inverse helps us find the angle \(\theta\), as \(\theta = \tan^{-1}\left(\frac{y}{x}\right)\).This formula links the vertical change (\(y\)) and the horizontal change (\(x\)) to the tangent.
Remember, in trigonometry involving angles, radians, not degrees, are often used. A full circle \(360°\) is equivalent to \(2\pi\)radians. This ensures smoother calculations in mathematical expressions and operations.

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Most popular questions from this chapter

For Exercises 37-46, recall that the flight of a projectile can be modeled with the parametric equations $$ x=\left(v_{0} \cos \theta\right) t \quad y=-16 t^{2}+\left(v_{0} \sin \theta\right) t+h $$ where \(t\) is in seconds, \(v_{0}\) is the initial velocity in feet per second, \(\theta\) is the initial angle with the horizontal, and \(h\) is the initial height above ground, where \(x\) and \(y\) are in feet. Flight of a Projectile. A projectile is launched from the ground at a speed of 400 feet per second at an angle of \(45^{\circ}\) with the horizontal. How far does the projectile travel (what is the horizontal distance), and what is its maximum altitude? (Note the symmetry of the projectile path.)

For Exercises 37-46, recall that the flight of a projectile can be modeled with the parametric equations $$ x=\left(v_{0} \cos \theta\right) t \quad y=-16 t^{2}+\left(v_{0} \sin \theta\right) t+h $$ where \(t\) is in seconds, \(v_{0}\) is the initial velocity in feet per second, \(\theta\) is the initial angle with the horizontal, and \(h\) is the initial height above ground, where \(x\) and \(y\) are in feet. Bullet Fired. A gun is fired from the ground at an angle of \(60^{\circ}\), and the bullet has an initial speed of 700 feet per second. How high does the bullet go? What is the horizontal (ground) distance between where the gun was fired and where the bullet hit the ground?

In Exercises 1-20, graph the curve defined by the following sets of parametric equations. Be sure to indicate the direction of movement along the curve. $$ x=4 \cos (2 t), y=t, t \text { in }[0,2 \pi] $$

In Exercises 45-68, graph each equation. In Exercises 63-68, convert the equation from polar to rectangular form first and identify the resulting equation as a line, parabola, or circle. $$ r=4 \theta $$

For Exercises 47 and 48 , refer to the following: Modern amusement park rides are often designed to push the envelope in terms of speed, angle, and ultimately \(g\)-force, and usually take the form of gargantuan roller coasters or skyscraping towers. However, even just a couple of decades ago, such creations were depicted only in fantasy-type drawings, with their creators never truly believing their construction would become a reality. Nevertheless, thrill rides still capable of nauseating any would-be rider were still able to be constructed; one example is the Calypso. This ride is a not-too-distant cousin of the better-known Scrambler. It consists of four rotating arms (instead of three like the Scrambler), and on each of these arms, four cars (equally spaced around the circumference of a circular frame) are attached. Once in motion, the main piston to which the four arms are connected rotates clockwise, while each of the four arms themselves rotates counterclockwise. The combined motion appears as a blur to any onlooker from the crowd, but the motion of a single rider is much less chaotic. In fact, a single rider's path can be modeled by the following graph: The equation of this graph is defined parametrically by $$ \begin{aligned} &x(t)=A \cos t+B \cos (-3 t) \\ &y(t)=A \sin t+B \sin (-3 t), 0 \leq t \leq 2 \pi \end{aligned} $$ Amusement Rides. Suppose the ride conductor was rather sinister and speeded up the ride to twice the speed. How would you modify the parametric equations to model such a change? Now vary the values of \(A\) and \(B\). What do you conjecture these parameters are modeling in this problem?

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