/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Write each product as a sum or d... [FREE SOLUTION] | 91Ó°ÊÓ

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Write each product as a sum or difference of sines and/or cosines. $$ \sin \left(\frac{\pi x}{2}\right) \sin \left(\frac{5 \pi x}{2}\right) $$

Short Answer

Expert verified
\( \frac{1}{2} [ \cos(2\pi x) - \cos(3\pi x) ] \).

Step by step solution

01

Identify the Formula to Use

To write the product \( \sin A \sin B \) as a sum or difference, we use the trigonometric product-to-sum identity:\[ \sin A \sin B = \frac{1}{2} \left[ \cos(A-B) - \cos(A+B) \right] \].
02

Assign Values to A and B

Identify \(A\) and \(B\) in the given expression \(\sin\left(\frac{\pi x}{2}\right)\sin\left(\frac{5\pi x}{2}\right)\). Here, \(A=\frac{\pi x}{2}\) and \(B=\frac{5\pi x}{2}\).
03

Compute A - B and A + B

Calculate \(A - B\) and \(A + B\) using the given values of \(A\) and \(B\):- \(A - B = \frac{\pi x}{2} - \frac{5\pi x}{2} = -2\pi x\)- \(A + B = \frac{\pi x}{2} + \frac{5\pi x}{2} = 3\pi x\)
04

Apply the Formula

Substitute \(A - B = -2\pi x\) and \(A + B = 3\pi x\) into the identity:\[ \sin\left(\frac{\pi x}{2}\right) \sin\left(\frac{5\pi x}{2}\right) = \frac{1}{2} \left[ \cos(-2\pi x) - \cos(3\pi x) \right] \].
05

Simplify the Expression

Use the even property of the cosine function \(\cos(-x) = \cos(x)\) to simplify:\[ \cos(-2\pi x) = \cos(2\pi x) \]. Thus, the expression becomes:\[ \frac{1}{2} \left[ \cos(2\pi x) - \cos(3\pi x) \right] \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Product-to-sum identities
The product-to-sum identities are valuable tools in trigonometry. They allow us to convert products of trigonometric functions into sums or differences. Specifically, the identity for the product of sine functions is given by:\[ \sin A \sin B = \frac{1}{2} \left[ \cos(A-B) - \cos(A+B) \right] \]This is particularly useful for solving problems that require simplification or transformation of trigonometric expressions. The identities help in evaluating integrals or simplifying expressions during algebraic operations. Knowing these identities by heart can make many mathematical steps much quicker and more manageable.
Sine and cosine transformations
Transformations involving sine and cosine functions are central to many areas of mathematics and physics. These functions may be expanded, compressed, shifted, or even reflected to suit different mathematical needs.### Identifying Components for TransformationWhen transforming products of sine and cosine using product-to-sum identities, it is vital to correctly identify the components that will be substituted. For example, in the exercise given:
  • Identify \(A\) as \(\frac{\pi x}{2}\)
  • Identify \(B\) as \(\frac{5\pi x}{2}\)
Calculating \(A-B\) and \(A+B\) is crucial in finding the correct transformed expression.### Application in ExpressionsBy calculating these transformations, we can simplify expressions and make them easier to work with. This is particularly useful for solving equations, analyzing signals, or understanding wave behaviors in physics and engineering.These transformations act as a bridge between different trigonometric forms, allowing more flexible manipulation of mathematical problems.
Trigonometric simplification
Trigonometric simplification involves reducing trigonometric expressions to their simplest form. This process often uses identities like product-to-sum to make evaluations and algebraic manipulations easier.### Simplification ProcessTo simplify the expression \( \sin \left(\frac{\pi x}{2}\right)\sin\left(\frac{5\pi x}{2}\right) \), we applied these steps:
  • Recognized and applied the appropriate identity.
  • Substituted known values for \(A\) and \(B\).
  • Calculated \(A-B\) and \(A+B\) accurately.
  • Simplified using the properties of cosine, noting that \(\cos(-x) = \cos(x)\).
This results in a cleaner, more concise expression: \( \frac{1}{2} \left[ \cos(2\pi x) - \cos(3\pi x) \right] \).Simplifying trigonometric expressions not only aids in solving equations more effectively but also enhances understanding of the patterns and behaviors of trigonometric functions themselves.

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Most popular questions from this chapter

Graph the functions. $$ y=\frac{1-\tan ^{2}\left(\frac{x}{2}\right)}{1+\tan ^{2}\left(\frac{x}{2}\right)} $$

In Exercises 1-16, use the half-angle identities to find the exact values of the trigonometric expressions. $$ \cos \left(\frac{11 \pi}{12}\right) $$

Verify the identities. $$ \csc ^{2}\left(\frac{A}{2}\right)=\frac{2(1+\cos A)}{\sin ^{2} A} $$

For Exercises 69-72, refer to the following: One cannot prove that an equation is an identity using technology, but one can use it as a first step to see whether the equation seems to be an identity. Using a graphing calculator, plot \(Y_{1}=\left(\frac{x}{2}\right)-\frac{\left(\frac{x}{2}\right)^{3}}{3 !}+\frac{\left(\frac{x}{2}\right)^{5}}{5 !}\) and \(Y_{2}=\sin \left(\frac{x}{2}\right)\) for \(x\) range \([-1,1]\). Is \(Y_{1}\) a good approximation to \(Y_{2}\) ?

Consider the triangle below, where the vertex angle measures \(\theta\), the equal sides measure \(a\), the height is \(h\), and half the base is \(b\). (In an isosceles triangle, the perpendicular dropped from the vertex angle divides the triangle into two congruent triangles.) The two triangles formed are right triangles. In the right triangles, \(\sin \left(\frac{\theta}{2}\right)=\frac{b}{a}\) and \(\cos \left(\frac{\theta}{2}\right)=\frac{h}{a}\). Multiply each side of each equation by \(a\) to get \(b=a \sin \left(\frac{\theta}{2}\right), h=a \cos \left(\frac{\theta}{2}\right)\). The area of the entire isosceles triangle is \(A=\frac{1}{2}(2 b) h=b h\). Substitute the values for \(b\) and \(h\) into the area formula. Show that the area is equivalent to \(\frac{a^{2}}{2} \sin \theta\).

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