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Diving. When viewing a person diving into a swimming pool from the side, the equation \(y=4+\sec \left(2 x+\frac{\pi}{2}\right)\) can be used to model the motion, where \(\frac{\pi}{8} \leq x<\frac{\pi}{2}\). Sketch the path of the diver as modeled by this equation.

Short Answer

Expert verified
The diver's path is a transformed secant curve within \(\frac{\pi}{8} \leq x < \frac{\pi}{2}\), showing an upward arc.

Step by step solution

01

Understanding the Function

The function given is \(y = 4 + \sec\left(2x + \frac{\pi}{2}\right)\). This is a secant function transformed vertically and horizontally, as well as shifted. \(y\) represents the vertical position, and \(x\) is associated with the horizontal movement of the diver.
02

Horizontal Transformation

The angle \(2x + \frac{\pi}{2}\) indicates a horizontal shift. The addition of \(\frac{\pi}{2}\) suggests a leftward shift by \(\frac{\pi}{4}\) when considering the period of the function. The factor \(2\) inside the secant affects the period, shortening it to \(\frac{\pi}{2}\) from the typical \(2\pi\) of a standard secant function.
03

Vertical Transformation

The entire secant function is lifted up by 4 units due to the addition of 4 outside the function. This changes the baseline level from \(0\) to \(4\).
04

Determine the Domain

The domain for \(x\) is given as \(\frac{\pi}{8} \leq x < \frac{\pi}{2}\). This influences which part of the curve we are considering for the dive. No jumps or asymptotes appear as the input to secant stays within a manageable range.
05

Sketching the Function

Plot key points by choosing values for \(x\) in the domain \(\frac{\pi}{8} \leq x < \frac{\pi}{2}\), calculating \(y\) for each value using the function. Note the general secant curve shape with vertical asymptotes and intervals of increase and decrease adjusted horizontally and vertically as calculated.
06

Analyzing Path Characteristics

The path will appear as a wave due to the secant shape. Note that within the specified domain, this part of the path represents a snapshot of the motion, capturing the diver in a dive phase that arcs smoothly.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Secant Function
The secant function is a crucial concept in trigonometry. It's represented as \( \sec(x) = \frac{1}{\cos(x)} \). Understanding its behavior is vital for solving many trigonometric problems. The secant function has characteristics that include periodicity, vertical asymptotes, and undefined points corresponding to where the cosine is zero.
  • Periodicity: The secant function repeats every \(2\pi\).
  • Vertical Asymptotes: These occur where cosine equals zero, making secant undefined.
  • Range: The range of \(y = \sec(x)\) is \((-\infty, -1] \cup [1, \infty)\).\
In the exercise, these properties are modified when transformations are applied, shifting and altering the standard pattern.
Transformation of Functions
Transformations modify the basic graph of a function into a new graph. They include translations (shifts) and scaling, either vertically or horizontally. For the secant function given by \(y = 4 + \sec(2x + \frac{\pi}{2})\), let’s break down the transformations:
  • Vertical Shift: Adding 4 to the function \(\sec(2x + \frac{\pi}{2})\) shifts the graph up by four units.
  • Horizontal Shift: The function \(2x + \frac{\pi}{2}\) indicates a leftward shift by \(\frac{\pi}{4}\). This is derived from setting \(2x + \frac{\pi}{2} = 0\).
  • Horizontal Compression: The factor of 2 affects the period, compressing it to \(\frac{\pi}{2}\).
These transformations result in a distorted version of the basic secant function, requiring careful attention when sketching its path.
Domain and Range
The domain of a function consists of all the permissible input values of \(x\), while the range comprises all possible output values of \(y\). These concepts are essential when dealing with functions like the secant.
For our diving equation, \(y = 4 + \sec(2x + \frac{\pi}{2})\), the given domain is \(\frac{\pi}{8} \leq x < \frac{\pi}{2}\) , ensuring that no undefined values of the function, such as points leading to division by zero, are included. This keeps everything straightforward for our specific interval.
  • The range of the transformed function, dictated mainly by the vertical shift of 4 units, shifts the overall potential for y-values.
  • Standard secant varies from negative infinity to -1 and from 1 to positive infinity. After transformation, this function's values reflect similar ranges shifted upward to the different amplitudes due to translations.
Understanding the domain and range helps predict the behavior of the function, ensuring accurate graphing.
Graphing Trigonometric Functions
Graphing trigonometric functions involves plotting their wave-like patterns, taking into account any transformations applied. For the function \(y = 4 + \sec(2x + \frac{\pi}{2})\), this includes completing several steps to ensure accuracy.
Start by identifying key points within the given domain \(\frac{\pi}{8} \leq x < \frac{\pi}{2}\). Calculate corresponding y-values using the transformed function formula. Characteristic points typically include maximums, minimums, or undefined points where vertical asymptotes occur. These points help shape the graph.
  • Plot each calculated point to establish the function's form.
  • Recognize vertical asymptotes derived from secant's inherent nature.
  • Map intervals of increase and decrease reflecting secant's periodic up and downs.
Emphasizing these features helps create a true representation of the diver's motion, accurately capturing the secant function's transformed behavior.

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Most popular questions from this chapter

In Exercises 51-62, add the ordinates of the indicated functions to graph each summed function on the indicated interval. $$ y=\cos \left(\frac{x}{2}\right)+\cos (2 x), \text { on } 0 \leq x \leq 4 \pi $$

For Exercises 63 and 64, refer to the following: If water is polluted by organic material, the levels of dissolved oxygen generally decrease. Oxygen depletion (oxygen levels below 4 milligrams per liter) can be detrimental to fish and other aquatic life. Oxygen levels from samples taken from the same location in a lake were studied over a period of 10 years. It was found that over the course of a year, the oxygen levels in the lake could be approximated by the function $$ f(t)=3.1 \cos t+7.4 \quad 1 \leq t \leq 365 $$ where \(t\) is the day of the year and \(t=1\) represents January \(1 \mathrm{st}\). Assume that it is not a leap year. Environment/Life Sciences. Find the oxygen level of the lake (to two decimal places) on November 20th.

Biology. The number of deer on an island varies over time because of the amount of available food on the island. If the number of deer is determined by \(y=500 \sin \left(\frac{\pi t}{2}\right)+1000\), where \(t\) is in years, then what are the highest and lowest numbers of deer on the island, and how long is the cycle?

In Exercises 37-46, sketch the graph of each sinusoidal function over the indicated interval. $$ y=2-3 \cos \left(3 x-\frac{\pi}{2}\right),\left[-\frac{\pi}{2}, \frac{5 \pi}{6}\right] $$

In Exercises 31-42, graph the functions over the indicated intervals. $$ y=2 \csc (2 x+\pi),-2 \pi \leq x \leq 2 \pi $$

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