/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 In Exercises 25-40, graph the gi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises 25-40, graph the given sinusoidal functions over one period. $$ y=-2 \sin \left(\frac{1}{4} x\right) $$

Short Answer

Expert verified
Graph the sine function with amplitude 2, period \(8\pi\), no phase or vertical shifts, completing one cycle from 0 to \(8\pi\).

Step by step solution

01

Identify the General Form of the Sine Function

The general form of a sinusoidal function is given by \( y = A \sin(Bx + C) + D \). In this case, the function is \( y = -2 \sin \left(\frac{1}{4} x \right) \). From this, we can identify: \( A = -2 \), \( B = \frac{1}{4} \), \( C = 0 \), and \( D = 0 \).
02

Determine the Amplitude

Amplitude is the absolute value of the coefficient \( A \). Since \( A = -2 \), the amplitude is \( |A| = 2 \). This means the graph will oscillate 2 units above and below the midline of the function.
03

Calculate the Period

The period of a sine function is calculated using the formula \( \frac{2\pi}{|B|} \). Here, \( B = \frac{1}{4} \), so the period is \( \frac{2\pi}{\frac{1}{4}} = 8\pi \). This is the length of one complete cycle of the sine wave.
04

Determine the Phase Shift

The phase shift is given by \( -\frac{C}{B} \). With \( C = 0 \), there's no phase shift in this function, meaning the graph doesn't horizontally translate.
05

Identify the Vertical Shift

Since \( D = 0 \), there is no vertical shift, and the midline of the graph remains at \( y = 0 \).
06

Plot Key Points

Identify key points within one period: starting point, maximum, midpoint, minimum, back to midpoint and end of the cycle. For \( y = -2 \sin \left(\frac{1}{4} x \right) \), the key points are: start at \( (0, 0) \), go to the minimum \( (2\pi, -2) \), return to 0 at \( (4\pi, 0) \), reach maximum at \( (6\pi, 2) \), and conclude the period at \( (8\pi, 0) \).
07

Draw the Graph

Using a smooth, sinusoidal curve, connect the key points you've plotted. Make sure the graph oscillates between \( -2 \) and \( 2 \), maintaining the overall characteristics of a flipped sine wave due to the negative amplitude.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Amplitude
The amplitude of a sinusoidal function relates directly to the value of the leading coefficient, usually represented as \( A \) in the function's general form, \( y = A \sin(Bx + C) + D \).
This value signifies the maximum extent of the wave from its central axis or midline.
For example, in the function \( y = -2 \sin \left( \frac{1}{4} x \right) \), the amplitude is determined by the absolute value of \( A \).

  • Since \( A = -2 \), the amplitude is calculated as \( |A| = 2 \).
This means that the wave will reach 2 units above and below the center line, creating a range that spans a total of 4 units.
It is important to note that amplitude is always a positive quantity, even if the function itself includes a negative sign.
The negative sign in the coefficient signifies a reflection over the midline, flipping the standard waves pattern without changing the amplitude's magnitude.
Period
Understanding the period of a sinusoidal function helps us determine how long it takes for the wave to complete one full oscillation.
The formula for calculating the period is \( \frac{2\pi}{|B|} \), where \( B \) is the coefficient attached to \( x \) in the argument of the sine (or cosine) function.

In the case of \( y = -2 \sin \left( \frac{1}{4} x \right) \):
  • The \( B \) here is \( \frac{1}{4} \).
  • Thus, the period is \( \frac{2\pi}{\frac{1}{4}} = 8\pi \).

This tells us that one complete cycle of the sine wave stretches over an \( 8\pi \) interval along the x-axis.
Recognizing the period allows for precise plotting of key points across the function's graph.
Phase Shift
Phase shift describes the horizontal displacement of a sinusoidal wave from its standard starting position.
This is computed using the expression \(-\frac{C}{B}\), where \( C \) and \( B \) are coefficients from the general form \( y = A \sin(Bx + C) + D \).

In the function \( y = -2 \sin \left( \frac{1}{4} x \right) \):
  • \( C = 0 \).
  • \( B = \frac{1}{4} \).
  • The phase shift becomes \(-\frac{0}{\frac{1}{4}} = 0 \).

This indicates that there is no horizontal shift; the wave starts at the origin and cycles symmetrically about this point over its period.
Understanding phase shifts are crucial when comparing the alignment of multiple sinusoidal functions.
Vertical Shift
Vertical shifts in sinusoidal functions represent how much the entire wave moves up or down along the y-axis.
This aspect is represented by the \( D \) term in the generic equation \( y = A \sin(Bx + C) + D \).

For the function \( y = -2 \sin \left( \frac{1}{4} x \right) \):
  • The \( D \) value is \( 0 \).

Thus, there is no vertical shift, and the midline of the wave remains exactly at \( y = 0 \).
Even with significant oscillation, the sinusoidal curve centers around this stable line.
Being aware of vertical shifts helps determine the baseline from which the wave elevates or drops in its cycle.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Life Sciences. Suppose the cycle of a Circadian rhythm in photosynthesis is 22 hours and the maximum and minimum values obtained are 12 and 6 micromoles of carbon per square meter per second. Find an equation that models this photosynthesis.

In Exercises 43-50, graph the functions over at least one period. $$ y=-3+2 \csc \left(x+\frac{\pi}{2}\right) $$

In Exercises 9-18, determine the period and phase shift (if there is one) for each function. $$ y=\cot (2 x+2) $$

In Exercises 81 and 82, explain the mistake that is made. Graph \(y=1+\sin (2 x)\). Solution: Step 1: Graph \(y=\sin (2 x)\). Find the amplitude. \(|A|=|-1|=1\) Make a table. \begin{tabular}{|l|c|c|} \hline\(x\) & \(y=-\sin (2 x)\) & \((x, y)\) \\ \hline 0 & \(y=-\sin 0=0\) & \((0,0)\) \\ \hline\(\pi\) & \(y=-\sin (2 \pi)=0\) & \((\pi, 0)\) \\ \hline \(2 \pi\) & \(y=-\sin (4 \pi)=0\) & \((2 \pi, 0)\) \\ \hline \end{tabular} Plot the points. Step 2: Shift the graph of \(y=\sin (2 x)\) up one unit to arrive at the graph of \(y=1+\sin (2 x)\). This is incorrect. What mistake was made?

For Exercises 65-68, refer to the following: Computer sales are generally subject to seasonal fluctuations. An analysis of the sales of QualComp computers during 2008-2010 is approximated by the function $$ s(t)=0.098 \sin (0.79 t+2.37)+0.387 \quad 1 \leq t \leq 12 $$ where \(t\) represents time in quarters ( \(t=1\) represents the end of the first quarter of 2008), and s(t) represents computer sales (quarterly revenue) in millions of dollars. Business/Economics. Find the vertical shift. Interpret its meaning.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.