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\(\csc 60^{\circ}\)

Short Answer

Expert verified
\( \csc 60^{\circ} = \frac{2\sqrt{3}}{3} \).

Step by step solution

01

Understanding the Function

The exercise asks for the cosecant of 60 degrees. The cosecant function, denoted as \( \csc \), is the reciprocal of the sine function. Therefore, \( \csc \theta = \frac{1}{\sin \theta} \). In this case, we need to find \( \sin 60^{\circ} \) first in order to compute \( \csc 60^{\circ} \).
02

Finding Sine of 60 Degrees

Recall that \( \sin \theta \) for 60 degrees is a standard trigonometric value. We have \( \sin 60^{\circ} = \frac{\sqrt{3}}{2} \). It's helpful to remember this common value from the unit circle or from an equilateral triangle split into two 30-60-90 triangles.
03

Calculating the Cosecant

Given \( \sin 60^{\circ} = \frac{\sqrt{3}}{2} \), we use the reciprocal relationship to find \( \csc 60^{\circ} \). Thus, \( \csc 60^{\circ} = \frac{1}{\sin 60^{\circ}} = \frac{1}{\frac{\sqrt{3}}{2}} = \frac{2}{\sqrt{3}} \).
04

Rationalizing the Denominator

The expression \( \frac{2}{\sqrt{3}} \) can be further simplified by rationalizing the denominator. To do this, multiply the numerator and the denominator by \( \sqrt{3} \): \( \frac{2}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{2\sqrt{3}}{3} \). This is the simplified value of \( \csc 60^{\circ} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Values
Trigonometric values are essential in understanding angles and triangles. They relate the angles of a triangle to the lengths of its sides. In trigonometry, \(\sin\), \(\cos\), and \(\tan\) are the primary functions you will encounter. Each of these functions provides a ratio of two sides of a right-angled triangle.
Common angles you will frequently use are 30°, 45°, and 60°, each corresponding to specific trigonometric values. These angles often appear in problems because their trigonometric values can be derived from special triangles or the unit circle.
The sine of 60°, which is \(\sin 60^\circ = \frac{\sqrt{3}}{2}\), is one such value. Recognizing these standard values can speed up calculations and provide a deeper understanding of trigonometric functions.
Reciprocal Functions
Reciprocal functions in trigonometry are fascinating because they offer alternative perspectives on the main trigonometric functions. The primary reciprocal trigonometric functions are cosecant (\(\csc\)), secant (\(\sec\)), and cotangent (\(\cot\)). These functions are defined as the reciprocals of sine, cosine, and tangent respectively.
For example:
  • \(\csc \theta = \frac{1}{\sin \theta}\)
  • \(\sec \theta = \frac{1}{\cos \theta}\)
  • \(\cot \theta = \frac{1}{\tan \theta}\)
In our exercise, \(\csc 60^\circ\) is calculated using the sine value of 60°. The reciprocal relationship between sine and cosecant allows us to transform the problem into an easier task. Understanding reciprocal functions provides flexibility when solving trigonometric problems.
Unit Circle
The unit circle is a powerful tool in trigonometry, giving insight into angle measures and trigonometric function values. It's a circle with a radius of one centered at the origin of a coordinate plane. The unit circle helps visualize how trigonometric functions repeat or mimic periodic cycles.
On the unit circle, the coordinates of any point (x, y) correspond to \(\cos \theta\) and \(\sin \theta\) respectively, for a given angle \(\theta\). This property makes the unit circle a quick reference for determining trigonometric values.
For \(\sin 60^\circ\), the y-value of the point on the unit circle is \(\frac{\sqrt{3}}{2}\). The unit circle ensures that these values are standardized and easy to remember, making calculations with trigonometric functions more straightforward.
Rationalizing Denominators
Rationalizing denominators is a technique used to simplify expressions involving roots in the denominator. This practice is rooted in making calculations easier and results cleaner by eliminating irrational numbers from the denominator.
The process involves multiplying the numerator and denominator by the same root present in the denominator. In our case, for \(\frac{2}{\sqrt{3}}\), we multiply both parts by \(\sqrt{3}\), yielding \(\frac{2\sqrt{3}}{3}\).
Rationalizing keeps expressions neat and ready for further mathematical operations and applications. It reflects a fundamental step in making sure trigonometric solutions are presented in their most understandable form.

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Most popular questions from this chapter

Angle of Inclination (Skiing). The angle of inclination of a mountain with triple black diamond ski paths is \(65^{\circ}\). If a skier at the top of the mountain is at an elevation of 4000 feet, how long is the ski run from the top to the base of the mountain?

Obstacle Course. As part of an obstacle course, participants are required to ascend to the top of a ladder placed against a building and then use a rope to climb the rest of the way to the roof. The distance traveled can be calculated using the formula \(d=15 \sin \theta+4 \sqrt{3}\), where \(\theta\) is the angle the ladder makes with the ground and \(d\) is the distance traveled, measured in feet. Find the exact distance traveled by the participants if \(\theta=60^{\circ}\).

Angle of Elevation (Traffic). A person driving in a sedan is driving too close to the back of an 18 wheeler on an interstate highway. He decides to back off until he can see the entire truck (to the top). If the height of the trailer is 15 feet and the sedan driver's angle of elevation (to the top of the trailer from the horizontal line with the bottom of the trailer) is roughly \(30^{\circ}\), how far is he sitting from the end of the trailer?

Glide Path of the Space Shuttle Orbiter. If the same pilot in Exercise 55 raises the nose of the gliding shuttle so that she drops only 500 feet by the time she is 7800 feet from the shuttle landing strip (ground distance), what is her glide angle at that time (round to the nearest degree)? Is she within the specs \(\left(18^{\circ}-20^{\circ}\right)\) to land the shuttle?

\(\csc 51^{\circ}\)

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