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The two most common ways of writing the inverse function for \(y=\sin x\) are _____ and _____.

Short Answer

Expert verified
The two notations are \(\sin^{-1}(y)\) and \(\arcsin(y)\).

Step by step solution

01

Understanding Inverse Functions

The inverse of a function reverses the original function's operation. For example, the sine function, denoted as \(y = \sin x\), can be inverted to find an angle whose sine value is a specified value.
02

Identifying the Inverse of Sine

The inverse of the sine function is used to determine an angle from a given sine value. This inverse function is commonly denoted as either \(\sin^{-1}(x)\) or \(\arcsin(x)\).
03

Specify Common Notations

In mathematics, there are two widely used notations for expressing the inverse of the sine function: \(\sin^{-1}(y)\) and \(\arcsin(y)\). These notations indicate the angle whose sine is \(y\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Function
An inverse function essentially undoes the action of the original function. For any function, the inverse performs the opposite operation when possible. This concept can be likened to undoing a specific action. For example, consider wrapping a gift. If the gift-wrapping is the original function, then unwrapping the gift can be seen as the inverse function. When it comes to mathematical functions, the idea is the same. The inverse function swaps the dependent and independent variables. If you apply a function and then apply its inverse, you end up back where you started. In terms of notation, if you have a function denoted by \( f(x) \), its inverse is generally denoted as \( f^{-1}(x) \). A critical point to remember is that not all functions have inverses. A function must be one-to-one (bijective) to have an inverse that is also a function. This indicates that for every output of the function, there is a unique input.
Sine Function
The sine function is a fundamental aspect of trigonometry that relates the angle of a right triangle to the ratio of its opposite side to its hypotenuse. In mathematical terms, for a given angle \( \theta \) in a right triangle, the sine function is defined as: \[ \sin(\theta) = \frac{{\text{opposite}}}{{\text{hypotenuse}}} \] This function is periodic, meaning it repeats its values in regular intervals or cycles. The periodicity of the sine function occurs every \(2\pi\) radians or 360 degrees. Because of this cyclical nature, the sine function is not inherently one-to-one and thus not naturally invertible over its entire range. To ensure it has an inverse, we restrict its domain. The principal domain where the sine function is one-to-one is from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\). This restricted portion is what allows us to define the inverse sine or arcsine function.
Arcsin Notation
Arcsin notation is used to refer to the inverse of the sine function. When you see \( \arcsin(x) \) or \( \sin^{-1}(x) \), it indicates the angle whose sine is \(x\). These notations are interchangeable and often used based on personal or regional preferences.
  • \( \arcsin(x) \) or \( \sin^{-1}(x) \) returns an angle in the interval \([-\frac{\pi}{2}, \frac{\pi}{2}]\).
  • This means arcsin only provides angles within this narrow range, also noted as the principal value range.
The term "arcsin" comes from "arc sine," which reflects finding an angle from a ratio rather than calculating the ratio from an angle. Since the sine function is not one-to-one over all possible inputs, the principal value range is applied so that each value of \(x\) gives a unique angle in the domain of arcsin. This concept is crucial for solving problems involving trigonometric equations and is very useful in various fields, such as physics and engineering.

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Most popular questions from this chapter

Find the inverse of each function \(f(x)\) given, then prove (by composition) your inverse function is correct. Note the domain of \(f\) is all real numbers. $$ f(x)=\frac{(x+3)^{3}}{-27} $$

The area of a circular segment (the shaded portion shown) is given by the formula \(A=\frac{1}{2} r^{2}(\theta-\sin \theta)\), where \(\theta\) is in radians. If the circle has a radius of \(10 \mathrm{~cm}\), find the angle \(\theta\) that gives an area of \(12 \mathrm{~cm}^{2}\).

A projectile is any object that is shot, thrown, slung, or otherwise projected and has no continuing source of propulsion. The horizontal and vertical position of the projectile depends on its initial velocity, angle of projection, and height of release (air resistance is neglected). The horizontal position of the projectile is given by \(x=v_{0} \cos \theta t\), while its vertical position is modeled by \(y=y_{0}+v_{0} \sin \theta t-16 t^{2}\), where \(y_{0}\) is the height it is projected from, \(\theta\) is the projection angle, and \(t\) is the elapsed time in seconds. A circus clown is shot out of a specially made cannon at an angle of \(55^{\circ}\), with an initial velocity of \(85 \mathrm{ft} / \mathrm{sec}\), and the end of the cannon is \(10 \mathrm{ft}\) high. a. Find the position of the safety net (distance from the cannon and height from the ground) if the clown hits the net after \(4.3 \mathrm{sec}\). b. Find the angle at which the clown was shot if the initial velocity was \(75 \mathrm{ft} / \mathrm{sec}\) and the clown hits a net that is placed \(175.5 \mathrm{ft}\) away after \(3.5 \mathrm{sec}\).

Find all real solutions. Note that identities are not required to solve these exercises. $$ 2 \sqrt{3} \tan x=2 $$

(a) Determine a domain restriction that preserves all range values, then state this domain and range. (b) Find the inverse function and state its domain and range. $$ f(x)=(x+5)^{2} $$

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