/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Given the following triangles, f... [FREE SOLUTION] | 91Ó°ÊÓ

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Given the following triangles, find the values of the indicated functions. a. \(\sec 60^{\circ}\) b. \(\csc 60^{\circ}\) c. \(\cot 60^{\circ}\)

Short Answer

Expert verified
a. 2, b. \(\frac{2\sqrt{3}}{3}\), c. \(\frac{\sqrt{3}}{3}\)

Step by step solution

01

Understanding Trigonometric Functions

To solve for \( \sec, \csc, \text{and} \cot \) of \( 60^{\circ} \), remember that these are the reciprocal of cosine, sine, and tangent, respectively.
02

Calculating \( \sec 60^{\circ} \)

The secant function is the reciprocal of cosine. First, recall that \( \cos 60^{\circ} = \frac{1}{2} \). Therefore, \( \sec 60^{\circ} = \frac{1}{\cos 60^{\circ}} = \frac{1}{\frac{1}{2}} = 2 \).
03

Calculating \( \csc 60^{\circ} \)

The cosecant function is the reciprocal of sine. Recall that \( \sin 60^{\circ} = \frac{\sqrt{3}}{2} \). So, \( \csc 60^{\circ} = \frac{1}{\sin 60^{\circ}} = \frac{1}{\frac{\sqrt{3}}{2}} = \frac{2}{\sqrt{3}} \). To rationalize the denominator, \( \csc 60^{\circ} = \frac{2 \cdot \sqrt{3}}{3} = \frac{2\sqrt{3}}{3} \).
04

Calculating \( \cot 60^{\circ} \)

The cotangent function is the reciprocal of tangent. \( \tan 60^{\circ} = \sqrt{3} \). Hence, \( \cot 60^{\circ} = \frac{1}{\tan 60^{\circ}} = \frac{1}{\sqrt{3}} \). To rationalize the denominator, \( \cot 60^{\circ} = \frac{\sqrt{3}}{3} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Secant Function
The secant function, represented as \( \sec \theta \), is one of the lesser-known trigonometric functions but is fundamentally important. It is defined as the reciprocal of the cosine function. Specifically, the secant of an angle \( \theta \) in a right-angled triangle is \( \sec \theta = \frac{1}{\cos \theta} \). This means that we divide 1 by the cosine of the angle to find the secant.
For example, let's consider the angle \( 60^{\circ} \). The cosine of \( 60^{\circ} \) is \( \frac{1}{2} \). Hence, the secant would be calculated as follows:
  • \( \sec 60^{\circ} = \frac{1}{\frac{1}{2}} = 2 \)

Secant is particularly useful in calculus when dealing with problems that involve hyperbolic structures or in trigonometry when a formula requires the reciprocal of cosine. Understanding **secant** bridges the gap between simple sine and cosine functions and more complex calculations.
Cosecant Function
The cosecant function, denoted as \( \csc \theta \), is the reciprocal of the sine function. Simply put, it is found by dividing 1 by the sine of an angle. Mathematically, it is expressed as \( \csc \theta = \frac{1}{\sin \theta} \). This means that wherever sine is zero, cosecant is undefined because we cannot divide by zero.
For \( 60^{\circ} \), the sine is \( \frac{\sqrt{3}}{2} \). Therefore, the calculation for cosecant is:
  • \( \csc 60^{\circ} = \frac{1}{\sin 60^{\circ}} = \frac{1}{\frac{\sqrt{3}}{2}} = \frac{2}{\sqrt{3}} \)

Then, we rationalize the denominator to get:
  • \( \csc 60^{\circ} = \frac{2 \cdot \sqrt{3}}{3} = \frac{2\sqrt{3}}{3} \)

**Cosecant** is particularly beneficial in various areas of mathematics, especially in solving equations and evaluating trigonometric expressions where sine is at the core of the equation.
Cotangent Function
The cotangent function, denoted by \( \cot \theta \), is another reciprocal trigonometric function. It is the inverse of the tangent function and is calculated by \( \cot \theta = \frac{1}{\tan \theta} \).
This is especially useful when dealing with angles that have large or complex tangent values.
For a \( 60^{\circ} \) angle, since \( \tan 60^{\circ} = \sqrt{3} \), the cotangent is calculated as follows:
  • \( \cot 60^{\circ} = \frac{1}{\tan 60^{\circ}} = \frac{1}{\sqrt{3}} \)

To simplify, we rationalize the denominator:
  • \( \cot 60^{\circ} = \frac{\sqrt{3}}{3} \)

In practical applications, **cotangent** is often used in coordinate geometry, particularly in finding slopes and angles between intersecting lines. Grasping the concept of cotangent is vital for advanced study in mathematics and related fields.

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Most popular questions from this chapter

The sine of an angle between two sides of a triangle: \(\sin \theta=\frac{2 A}{a b}\) If the area \(A\) and two sides \(a\) and \(b\) of a triangle are known, the sine of the angle between the two sides is given by the formula shown. Find the angle \(\theta\) for the triangle shown given \(A=38.9\), and use it to solve the triangle. (Hint: Apply the same concept to angle \(\gamma\) or \(\beta\).)

Use a calculator to find the acute angle whose corresponding ratio is given. Round to the nearest 10th of a degree. For Exercises 25 through 32 , use Exercises 17 through 24 as a check. $$\cos B=0.3090$$

Angle of elevation: In January 2009, Burj Dubai unofficially captured the record as the world's tallest building, according to the Council on Tall Buildings and Urban Habitat (Source: www.ctbuh.org). Measured at a point \(159 \mathrm{~m}\) from its base, the angle of elevation to the top of the spire is \(79^{\circ}\). From a distance of about \(134 \mathrm{~m}\), the angle of elevation to the top of the roof is also \(79^{\circ}\). How tall is Burj Dubai from street level to the top of the spire? How tall is the spire itself?

Angle of elevation: For a person standing \(100 \mathrm{~m}\) from the center of the base of the Eiffel Tower, the angle of elevation to the top of the tower is \(71.6^{\circ}\). How tall is the Eiffel Tower?

Angles of rotation: A large sign spans an east/west highway. From a point \(35 \mathrm{~m}\) due west of the southern base of the sign, a surveyor finds the northern base lies on a bearing of \(\mathrm{N} \mathrm{} 67^{\circ} 11^{\prime} 42^{\prime \prime} \mathrm{E}\). To the nearest centimeter, how wide is the sign?

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