Chapter 8: Problem 25
Let \(f\) be a real function continuous at \(a,\) and let \(\left\langle a_{n}\right\rangle\) be a sequence converging to \(a\). Prove that $$ \lim _{n \rightarrow \infty} f\left(a_{n}\right)=f(a). $$
Short Answer
Expert verified
The limit \(\lim_{n \to \infty} f(a_n) = f(a)\) follows from the continuity of \(f\) at \(a\) and the convergence of \(\langle a_n \rangle\) to \(a\).
Step by step solution
01
Understand the definition of continuity
We are given that the function \(f\) is continuous at the point \(a\). By definition, a function \(f\) is continuous at a point \(a\) if for every \(\varepsilon > 0\), there exists a \(\delta > 0\) such that whenever \(|x - a| < \delta\), it follows that \(|f(x) - f(a)| < \varepsilon\).
02
Recall the definition of sequence convergence
The sequence \(\langle a_n \rangle\) is converging to \(a\). This means that for every \(\delta > 0\), there exists an \(N \in \mathbb{N}\) such that for all \(n \geq N\), \(|a_n - a| < \delta\).
03
Apply continuity to sequence limits
Because \(f\) is continuous at \(a\), and \(\langle a_n \rangle\) converges to \(a\), for every \(\varepsilon > 0\), there exists a \(\delta > 0\) so that if \(|a_n - a| < \delta\) then \(|f(a_n) - f(a)| < \varepsilon\).
04
Check sequence convergence condition
From convergence of \(\langle a_n \rangle\) to \(a\), for the \(\delta\) given in Step 3, there exists \(N \in \mathbb{N}\) such that for all \(n \geq N\), \(|a_n - a| < \delta\).
05
Prove the limit statement
For each \(n \geq N\), \(|a_n - a| < \delta\) implies \(|f(a_n) - f(a)| < \varepsilon\). This means that \(\lim_{n \to \infty} f(a_n) = f(a)\) since for every \(\varepsilon > 0\), there exists \(N\) such that for all \(n \geq N\), \(|f(a_n) - f(a)| < \varepsilon\). Thus, the sequence \(f(a_n)\) converges to \(f(a)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Continuity
Continuity is a fundamental concept in calculus and analysis. When we say a function is continuous at a point, it means there are no abrupt jumps or breaks at that point. Specifically, for a function \(f\) to be continuous at a point \(a\), it must satisfy the condition that for every positive number, \(\varepsilon\), no matter how small, there is a corresponding positive number \(\delta\). This \(\delta\) ensures that whenever \(|x - a| < \delta\), the difference \(|f(x) - f(a)|\) is less than \(\varepsilon\).
\(\varepsilon\) and \(\delta\) are like controls that measure closeness:
\(\varepsilon\) and \(\delta\) are like controls that measure closeness:
- \(\varepsilon\) represents how close \(f(x)\) should be to \(f(a)\).
- \(\delta\) determines how close \(x\) should be to \(a\).
Real Function
Real functions are mathematical expressions that associate real numbers to real numbers. A function \(f: \mathbb{R} \to \mathbb{R}\) means that for every input \(x\) from the set of real numbers (\(\mathbb{R}\)), there is a specific output \(f(x)\), which is also a real number. Understanding real functions involves:
- Domain: The set of all possible input values (\(x\)-values).
- Range: The set of all possible output values (\(f(x)\)-values).
- Graphical Representation: Often depicted as a curve or line on the Cartesian coordinate system, showing the relationship between input and output values.
Limit of a Function
The limit of a function describes the behavior of the function as the input approaches a certain value. Understanding limits is essential for grasping calculus concepts like differentiation and integration. Essentially, \(\lim_{x \to a} f(x) = L\) means that as \(x\) gets closer and closer to \(a\), \(f(x)\) gets closer and closer to \(L\). Here are some key points regarding limits:
- Limits help determine continuity at a point. If a function has a limit at \(a\) and equals the function's value at \(a\), the function is continuous at that point.
- They provide insights into the function's behavior near important points, like maxima, minima, or points of inflection.