/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Solve the differential equations... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the differential equations. \((1+x) y^{\prime}+y=\sqrt{x}\)

Short Answer

Expert verified
The solution is \(y = \frac{2}{3} \frac{x^{3/2}}{1+x} + \frac{2}{5} \frac{x^{5/2}}{1+x} + \frac{C}{1+x}\).

Step by step solution

01

Identify the Type of Differential Equation

The given differential equation is \((1+x) y^{\prime}+y=\sqrt{x}\). This is a first-order linear differential equation of the form \(a(x)y' + b(x)y = c(x)\) where \(a(x) = 1+x\), \(b(x) = 1\), and \(c(x) = \sqrt{x}\).
02

Find the Integrating Factor

To solve the equation, we first calculate the integrating factor, \(\mu(x)\), given by \(\mu(x) = e^{\int \frac{b(x)}{a(x)}\, dx } = e^{\int \frac{1}{1+x}\, dx}=e^{\ln|1+x|} = 1+x\).
03

Multiply the Equation by the Integrating Factor

Multiply the entire differential equation by the integrating factor \(1+x\):\[(1+x)^2 y' + (1+x) y = (1+x) \sqrt{x}\].
04

Rewrite as a Derivative

Notice the left-hand side can be rewritten as the derivative:\[\frac{d}{dx}((1+x)y) = (1+x) y' + y\].So,\[\frac{d}{dx}((1+x)y) = \sqrt{x} (1+x)\].
05

Integrate Both Sides

Integrate both sides with respect to \(x\).\[\int \frac{d}{dx}((1+x)y) \, dx = \int \sqrt{x}(1+x) \, dx\].The left side simply becomes \((1+x)y\). On the right, expand and integrate:\[\int \sqrt{x} + \int x\sqrt{x} \, dx = \frac{2}{3}x^{3/2} + \frac{2}{5}x^{5/2} + C\].
06

Solve for \(y(x)\)

The integral gives:\[(1+x)y = \frac{2}{3}x^{3/2} + \frac{2}{5}x^{5/2} + C\].Divide through by \(1+x\):\[y = \frac{2}{3} \frac{x^{3/2}}{1+x} + \frac{2}{5} \frac{x^{5/2}}{1+x} + \frac{C}{1+x}\].
07

Verification

Verify the solution by differentiating \(y(x)\) and substituting back into the original equation to check that both sides are equal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First-Order Linear Differential Equations
First-order linear differential equations are a fundamental type of differential equation.
These equations involve derivatives of the first order (meaning we only deal with the first derivative). The standard form of such an equation is \(a(x) y' + b(x) y = c(x)\), where:\
  • \(a(x)\), the coefficient of \(y'\), is a function of \(x\).
  • \(b(x)\), the coefficient of \(y\), is another function of \(x\).
  • \(c(x)\) is the non-homogeneous part, also depending on \(x\).
These equations are important because they appear frequently in various natural and applied sciences, such as engineering, physics, and biology. Solving them generally involves finding a function \(y(x)\) that satisfies this equation.
Understanding the structure of the differential equation is crucial as it informs us about the possible methods we can use for solving, such as utilizing an integrating factor. First-order linear differential equations can be solved systematically and provide a stepping stone to more complex mathematical concepts.
Integrating Factor
The integrating factor in solving first-order linear differential equations is like a magic key.
It's a mathematical function we multiply through the entire differential equation to turn it into a form that’s easier to handle.When dealing with an equation of the form \(a(x) y' + b(x) y = c(x)\), you can find the integrating factor \(\mu(x)\) by using the formula:\[\mu(x) = e^{\int \frac{b(x)}{a(x)} \, dx} \]This interesting tool allows us to convert the left side of the equation into a single derivative. So, when the integrating factor is multiplied across, the left side becomes of the form \(\frac{d}{dx}(\mu(x)y)\), making the equation set up for easy integration.
With our given equation, the integrating factor was calculated as \(1+x\), a simple yet powerful tweak that transformed the problem into a more manageable form.
Solution Verification
Verifying the solution of a differential equation ensures that the final function we find is indeed correct.
This step is vital to confirm that every part of our solution satisfies the original differential equation given in the problem.After solving the equation for \(y(x)\), you verify by differentiating your solution and substituting back into the original equation:\[ (1+x) y' + y = \sqrt{x} \]Substitute \(y(x)\) back in from your solution and check that both sides are indeed equal.
If they are, it is a strong confirmation that the solution is correct. This step highlights the precision needed in solving differential equations and showcases how beautifully mathematics allows us to check our work systematically.
Mathematical Integration
Mathematical integration is essential in solving differential equations, especially in the final stages where it helps find the solution function from its derivative.
In our context, it was used after rewriting the differential equation using the integrating factor. Here’s the general process:
  • We begin by setting up the integral on both sides of the equation.
  • The left side of the equation integrates to give back the function expression \((1+x)y\).
  • On the right side, we expand and calculate the integral of expressions like \(\sqrt{x}(1+x)\), which breaks into two separate terms.
In our exercise, integration gave terms like \(\frac{2}{3}x^{3/2}\) and \(\frac{2}{5}x^{5/2}\), showcasing how integrations can unravel complex expressions.
Including the constant of integration is a crucial part of this process, representing an infinite set of solutions aligned with the differential equation. This element adds depth and completeness to the finalized function \(y(x)\).

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Most popular questions from this chapter

Use a CAS to explore graphically each of the differential equations.Perform the following steps to help with your explorations. a. Plot a slope field for the differential equation in the given \(x y\) -window. b. Find the general solution of the differential equation using your CAS DE solver. c. Graph the solutions for the values of the arbitrary constant \(C=-2,-1,0,1,2\) superimposed on your slope field plot. d. Find and graph the solution that satisfies the specified initial condition over the interval \([0, b].\) e. Find the Euler numerical approximation to the solution of the initial value problem with 4 subintervals of the \(x\) -interval and plot the Euler approximation superimposed on the graph produced in part (d). f. Repeat part (e) for \(8,16,\) and 32 subintervals. Plot these three Euler approximations superimposed on the graph from part (e). g. Find the error ( \(y\) (exact) \(-y\) (Euler)) at the specified point \(x=b\) for each of your four Euler approximations. Discuss the improvement in the percentage error.$$\begin{array}{l}y^{\prime}=(\sin x)(\sin y), \quad y(0)=2 ; \quad-6 \leq x \leq 6, \quad-6 \leq y \leq 6 \\\b=3 \pi / 2\end{array}.$$

Solve the initial value problems. \(\theta \frac{d y}{d \theta}+y=\sin \theta, \quad \theta>0, \quad y(\pi / 2)=1\)

Obtain a slope field and add to it graphs of the solution curves passing through the given points.\(y^{\prime}=\frac{x y}{x^{2}+4}\) with a. \((0,2)\) b. \((0,-6)\) c. \((-2 \sqrt{3},-4)\)

Suppose that a pearl is sinking in a thick fluid, like shampoo, subject to a frictional force opposing its fall and proportional to its velocity. Suppose that there is also a resistive buoyant force exerted by the shampoo. According to Archimedes' principle, the buoyant force equals the weight of the fluid displaced by the pearl. Using \(m\) for the mass of the pearl and \(P\) for the mass of the shampoo displaced by the pearl as it descends, complete the following steps. a. Draw a schematic diagram showing the forces acting on the pearl as it sinks, as in Figure 9.19. b. Using \(v(t)\) for the pearl's velocity as a function of time \(t\) write a differential equation modeling the velocity of the pearl as a falling body. c. Construct a phase line displaying the signs of \(v^{\prime}\) and \(v^{\prime \prime}\). d. Sketch typical solution curves. e. What is the terminal velocity of the pearl?

Show that the second-order differential equation \(y^{\prime \prime}=F\left(x, y, y^{\prime}\right)\) can be reduced to a system of two first-order differential equations $$\begin{array}{l}\frac{d y}{d x}=z \\\\\frac{d z}{d x}=F(x, y, z)\end{array}$$ Can something similar be done to the \(n\) th-order differential equation \(y^{(n)}=F\left(x, y, y^{\prime}, y^{\prime \prime}, \ldots, y^{(n-1)}\right) ?\)

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