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Chapter 7: Problem 79

Volume A region in the first quadrant is bounded above by the curve \(y=\cosh x,\) below by the curve \(y=\sinh x,\) and on the left and right by the \(y\) -axis and the line \(x=2,\) respectively. Find the volume of the solid generated by revolving the region about the \(x\) -axis.

Short Answer

Expert verified
The volume of the solid is \(2\pi\).

Step by step solution

01

Set Up the Problem

We are looking to find the volume of the solid generated by rotating the region defined by \(y = \cosh x\) and \(y = \sinh x\) about the \(x\)-axis from \(x = 0\) to \(x = 2\). This can be done using the method of washers (or disks) in calculus.
02

Express the Volume Element

The volume of a thin washer at a given \(x\) is the area of the washer times its thickness, \(dx\). The outer radius of the washer is given by \(\cosh x\) and the inner radius by \(\sinh x\). The area of the washer is \(\pi((\cosh x)^2 - (\sinh x)^2)\).
03

Simplify the Washer Area

Using the hyperbolic identity, \((\cosh x)^2 - (\sinh x)^2 = 1\), we see that the area simplifies to \(\pi(1) = \pi\). Thus, the volume element becomes \(\pi \cdot dx\).
04

Integrate to Find the Volume

Integrate the volume element from \(x = 0\) to \(x = 2\): \[V = \int_{0}^{2} \pi \cdot dx = \pi [x]_{0}^{2} = \pi (2 - 0) = 2\pi.\]
05

State the Result

The volume of the solid generated by revolving the given region about the \(x\)-axis is \(2\pi\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Method of Washers
The method of washers is a powerful tool in integral calculus used for finding the volume of a solid of revolution. This method involves revolving a region around an axis to form a solid and then calculating its volume.
  • The basic idea is to slice the solid perpendicular to the axis of revolution.
  • Each slice forms a washer or disk - essentially a flat cylinder.
  • The volume of each thin washer is computed by finding the area of the washer face and multiplying by its negligible thickness, denoted as \(dx\) or \(dy\).
When applying the method of washers, consider two radii:
  • Outer radius: the distance from the axis to the outer edge, given by the function farther from the axis.
  • Inner radius: the distance from the axis to the inner edge, represented by the function closer to the axis.
In the problem, the outer radius is \(\cosh x\), and the inner radius is \(\sinh x\). The section's area is \(\pi((\cosh x)^2 - (\sinh x)^2)\), simplifying beautifully to \(\pi\) using hyperbolic identities.
Hyperbolic Functions
Hyperbolic functions serve as analogs to trigonometric functions, yet they arise from hyperbolas rather than circles.
  • Definitions:
    • Hyperbolic sine, \(\sinh x = \frac{e^x - e^{-x}}{2}\).
    • Hyperbolic cosine, \(\cosh x = \frac{e^x + e^{-x}}{2}\).
  • These functions are useful in scenarios where growth models, physics equations, or calculus problems extend beyond circular arcs.
A crucial hyperbolic identity is \((\cosh x)^2 - (\sinh x)^2 = 1\). This relationship mirrors the Pythagorean trigonometric identity \(\cos^2 x + \sin^2 x = 1\) for circular functions.
In this exercise, this identity allows us to easily simplify the washer method's area calculation. By identifying that the area equation \(\pi((\cosh x)^2 - (\sinh x)^2)\) simplifies to \(\pi\), the problem becomes computationally straightforward.
Integral Calculus
Integral calculus is fundamental for finding areas, volumes, and other quantities under curves or surfaces. By summarizing infinitesimal slices, integration helps calculate continuous processes.
  • Definite integrals accumulate quantities over an interval \([a, b]\), providing results like total volume or area.
  • In this problem, the integral \(\int_{0}^{2} \pi \, dx\) calculates the total volume of the solid between \(x = 0\) and \(x = 2\).
The process involves substituting the simplified washer area \(\pi\) into the integral, making the computation \(\pi [x]_{0}^{2}\). The result, \(2\pi\), is a straightforward application of integral calculus following the simplification.
Integration, especially in the context of solids of revolution, is a step-by-step summing reality, piecing together infinitesimally small slices into a coherent, complete volume measure.

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