Chapter 7: Problem 75
Find the derivative of \(y\) with respect to the given independent variable. $$y=\theta \sin \left(\log _{7} \theta\right)$$
Short Answer
Expert verified
The derivative is \( \frac{dy}{d\theta} = \sin(\log_{7}\theta) + \frac{\cos(\log_{7}\theta)}{\ln 7} \).
Step by step solution
01
Understand the Function
The function we are given is \( y = \theta \sin (\log_{7} \theta) \). Here, \( \theta \) is the independent variable, and \( \log_{7} \theta \) is the logarithm of \( \theta \) to the base 7.
02
Apply Product Rule
The function \( y = \theta \sin (\log_{7} \theta) \) is a product of two functions: \( u = \theta \) and \( v = \sin(\log_{7}\theta) \). According to the product rule, the derivative of the product \( uv \) is \( u'v + uv' \).
03
Differentiate \( u \)
The function \( u = \theta \) is straightforward. The derivative \( u' = \frac{d}{d\theta} (\theta) = 1 \).
04
Differentiate \( v \) using Chain Rule
To find \( v' \), first note \( v = \sin(\log_{7}\theta) \). Let \( g = \log_{7}\theta \), thus \( v = \sin(g) \), and apply the chain rule: 1. Differentiate \( \sin(g) \) with respect to \( g \): \( \cos(g) \). 2. Differentiate \( g = \log_{7}\theta \) with respect to \( \theta \). Using change-of-base formula, \( \log_{7}\theta = \frac{\ln \theta}{\ln 7} \), giving \( \frac{d}{d\theta}(\log_{7}\theta) = \frac{1}{\theta \ln 7} \).Therefore, \( v' = \cos(\log_{7}\theta) \cdot \frac{1}{\theta \ln 7} \).
05
Apply Results in Product Rule Formula
Substitute \( u = \theta \), \( v = \sin(\log_{7}\theta) \), \( u' = 1 \), and \( v' = \cos(\log_{7}\theta) \cdot \frac{1}{\theta \ln 7} \) into the product rule: \[ \frac{dy}{d\theta} = 1 \cdot \sin(\log_{7}\theta) + \theta \cdot \cos(\log_{7}\theta) \cdot \frac{1}{\theta \ln 7} \].
06
Simplify the Derivative Expression
Simplify the expression: \[ \frac{dy}{d\theta} = \sin(\log_{7}\theta) + \frac{\cos(\log_{7}\theta)}{\ln 7} \]. This is the derivative of the original function \( y \) with respect to \( \theta \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Product Rule
The product rule is a useful technique for finding the derivative of a function composed of two multiplied sub-functions.
For example, if you have a function given by the product of two smaller functions, say, \( u \) and \( v \), the product rule will help us differentiate it.
The rule states:\[(uv)' = u'v + uv'\]This means you take the derivative of the first function, \( u \), and multiply it by the second function, \( v \), as it is. Then, add the product of \( u \) and the derivative of \( v \).
In our specific exercise, \( y = \theta \sin(\log_{7} \theta) \) can be broken into:
For example, if you have a function given by the product of two smaller functions, say, \( u \) and \( v \), the product rule will help us differentiate it.
The rule states:\[(uv)' = u'v + uv'\]This means you take the derivative of the first function, \( u \), and multiply it by the second function, \( v \), as it is. Then, add the product of \( u \) and the derivative of \( v \).
In our specific exercise, \( y = \theta \sin(\log_{7} \theta) \) can be broken into:
- \( u = \theta \)
- \( v = \sin(\log_{7} \theta) \)
Diving Into the Chain Rule
The chain rule is another fundamental technique in calculus, specifically used when you're differentiating a composite function.
This involves a function nested within another function, like \( \sin(\log_{7}\theta) \).For a composite function of the form \( f(g(x)) \), the derivative is given by the chain rule:\[\frac{d}{dx} f(g(x)) = f'(g(x)) \cdot g'(x)\]Here's how it applies:
This involves a function nested within another function, like \( \sin(\log_{7}\theta) \).For a composite function of the form \( f(g(x)) \), the derivative is given by the chain rule:\[\frac{d}{dx} f(g(x)) = f'(g(x)) \cdot g'(x)\]Here's how it applies:
- Differentiate the outer function \( \sin(g) \), where the inner function \( g(x) = \log_{7} \theta \), gives \( \cos(g) \).
- Then, differentiate \( g(x) \) itself: using the property of logarithms, \( g'(x) = \frac{1}{\theta \ln 7} \).
Exploring Logarithmic Differentiation
When confronted with functions involving logarithms, specifically a term like \( \log_{7}\theta \), simplifying the differentiation process often involves the change-of-base formula from logarithms.
Here's how it works: Convert \( \log_{7}\theta \) into natural logarithms for easier differentiation using the formula:
\[\log_{7}\theta = \frac{\ln \theta}{\ln 7}\]Now, differentiate the expression \( \log_{7}\theta \) with respect to \( \theta \) as it's vital for the chain rule:
Here's how it works: Convert \( \log_{7}\theta \) into natural logarithms for easier differentiation using the formula:
\[\log_{7}\theta = \frac{\ln \theta}{\ln 7}\]Now, differentiate the expression \( \log_{7}\theta \) with respect to \( \theta \) as it's vital for the chain rule:
- The derivative \( \frac{d}{d\theta}(\log_{7}\theta) = \frac{1}{\theta \ln 7} \).
- This result helps us find the necessary parts for the derivative of the inner function in the chain rule setting.