/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 Evaluate the integrals. $$\int... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the integrals. $$\int_{-2}^{2} \frac{d t}{4+3 t^{2}}$$

Short Answer

Expert verified
The value of the integral is \( \frac{\pi}{\sqrt{3}} \).

Step by step solution

01

Identify the Integral Type

The given integral \( \int_{-2}^{2} \frac{dt}{4 + 3t^2} \) is a definite integral of a rational function. This function can be simplified using trigonometric substitution or recognized as a form suitable for direct integration using an arctangent substitution.
02

Set Up the Integral with Arctangent Substitution

The integral \( \int \frac{dt}{4 + 3t^2} \) resembles the form \( \int \frac{dx}{a^2 + x^2} = \frac{1}{a}\arctan\left(\frac{x}{a}\right) + C \). In this case, set \( a^2 = 4 \) and \( x^2 = 3t^2 \), so \( a = 2 \) and \( x = \sqrt{3}t \). Thus, \( a = 2 \) and the integral becomes \( \int \frac{dt}{4 + 3t^2} = \frac{1}{2}\int \frac{dt}{1 + \left(\frac{\sqrt{3}t}{2}\right)^2} \).
03

Evaluate the Integral

Using the formula for arctangent substitution, we have: \( \frac{1}{2} \int \frac{dt}{1 + \left(\frac{\sqrt{3}t}{2}\right)^2} = \frac{1}{2} \cdot \frac{1}{\frac{\sqrt{3}}{2}} \arctan\left(\frac{\sqrt{3}t}{2}\right) + C = \frac{1}{\sqrt{3}} \arctan\left(\frac{\sqrt{3}t}{2}\right) + C \).
04

Apply the Limits of Integration

Substitute the upper and lower limits into the evaluated indefinite integral: \[ \left. \frac{1}{\sqrt{3}} \arctan\left(\frac{\sqrt{3}t}{2}\right) \right|_{-2}^{2} = \frac{1}{\sqrt{3}} \left( \arctan\left(\frac{\sqrt{3} \cdot 2}{2}\right) - \arctan\left(\frac{\sqrt{3} \cdot (-2)}{2}\right) \right) \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arctangent Substitution
Arctangent substitution is a powerful technique used to integrate rational functions that involve the square of a variable plus a constant. This type of substitution is particularly useful when the integral resembles the form \(\int \frac{dx}{a^2 + x^2}\). In this case, the solution involves recognizing the integral as an inverse tangent function.

To apply arctangent substitution, you need to:
  • Identify the constants and variable terms, matching with \(a^2+x^2\).
  • Set \(a = 2\) when you have an equation of the type \(4 + 3t^2\), by noting that \(a^2 = 4\).
  • Rearrange the terms so that the equation fits the arctangent form.
The integration results in the expression \(\frac{1}{a}\arctan\left(\frac{x}{a}\right) + C\). This makes arctangent substitution very effective for solving such integrals directly by transforming the equation into a standard inverse trigonometric function form.
Rational Functions
Rational functions are expressions that are formed by dividing one polynomial by another. In calculus, particularly in the context of definite integrals, they can either be straightforward or require special techniques such as substitution for solving.

For the integral \(\int_{-2}^{2} \frac{dt}{4 + 3t^2}\):
  • Notice that the function in the denominator, \(4 + 3t^2\), is a polynomial.
  • These are quadratic expressions, which are common in problems solved by substitution methods.
Rational functions can often be decomposed or simplified using various methods like partial fraction decomposition if they are proper fractions. However, when they mimic certain forms, such as those involving trigonometric identities, substitution techniques provide a more direct solution path.
Trigonometric Substitution
Trigonometric substitution involves replacing variables in an integral with trigonometric functions to simplify the equation, often resulting in a form that is easier to integrate. This is particularly helpful when dealing with integrands that include square roots or quadratic expressions.

In trigonometric substitution, the form \(1 + x^2\) can be approached by using substitutions like \(x = \tan(\theta)\) because the derivative \(1 + \tan^2(\theta) = \sec^2(\theta)\) simplifies the algebra.

In the exercise at hand, a transition from a rational function to a trigonometric form simplifies the process of solving the integral. This substitution helps in avoiding complex algebraic manipulation by transforming the variable related polynomial into a trigonometric identity, which is simpler to integrate and provides a clean algebraic solution post substitution.

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