Chapter 7: Problem 21
Solve the differential equations. $$\frac{1}{x} \frac{d y}{d x}=y e^{x^{2}}+2 \sqrt{y} e^{x^{2}}$$
Short Answer
Expert verified
The solution is \( y = (C' e^{\frac{1}{4} e^{x^2}} - 1)^2 \), with \( C' \) an arbitrary constant.
Step by step solution
01
Simplify the Right-Hand Side
The given differential equation is \( \frac{1}{x} \frac{dy}{dx} = y e^{x^2} + 2 \sqrt{y} e^{x^2} \). Factor out \( e^{x^2} \) from the right-hand side: \( \frac{dy}{dx} = e^{x^2} (y + 2 \sqrt{y}) x \).
02
Substitute and Transform
Let \( u = \sqrt{y} \), so \( y = u^2 \) and \( \frac{dy}{dx} = 2u \frac{du}{dx} \). Substitute: \( 2u \frac{du}{dx} = e^{x^2} (u^2 + 2u)x \).
03
Simplify the Transformed Equation
Divide both sides by \( 2u \), to get \( \frac{du}{dx} = \frac{e^{x^2} (u + 2)x}{2} \), i.e. \( \frac{du}{dx} = \frac{e^{x^2} x}{2} + \frac{e^{x^2} ux}{2} \).
04
Separate Variables
Rewrite as \( \frac{du}{1+u} = \frac{e^{x^2} x}{2} dx \). Separate variables: \( \frac{1}{1+u} du = \frac{1}{2} x e^{x^2} dx \).
05
Integrate Both Sides
Integrate the left side: \( \int \frac{1}{1+u} du = \ln|1+u| + C_1 \). For the right side, use substitution method: \( \int \frac{1}{2} x e^{x^2} dx \) let \( v = x^2 \), \( dv = 2x dx \). Thus, \( \int \frac{1}{2} x e^{x^2} dx = \frac{1}{4} \int e^v dv = \frac{1}{4} e^{x^2} + C_2 \).
06
Solve for u
Equating the integrated expressions: \( \ln|1+u| = \frac{1}{4} e^{x^2} + C \). Exponentiate: \( |1+u| = e^{\frac{1}{4} e^{x^2} + C} \). Let \( C' = e^C \), \( 1+u = \pm C' e^{\frac{1}{4} e^{x^2}} \).
07
Solve for y
Recall \( u = \sqrt{y} \), so \( \sqrt{y} = \pm C' e^{\frac{1}{4} e^{x^2}} - 1 \). Squaring both sides gives: \( y = (C' e^{\frac{1}{4} e^{x^2}} - 1)^2 \).
08
Conclusion
Thus, the solution to the differential equation is \( y = (C' e^{\frac{1}{4} e^{x^2}} - 1)^2 \), where \( C' \) is an arbitrary constant.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Separation of Variables
Separation of Variables is a technique used to solve differential equations where variables can be rearranged and isolated on opposite sides of an equation. This method involves:
- Rewriting the differential equation such that all terms involving one variable are on one side and terms involving the other variable are on the opposite side.
- It leads to an equation where each side can be integrated independently.
Integration Techniques
Integration techniques are crucial to solving differential equations after variables have been separated. These techniques involve: For the left side, we directly integrated: \[ \int \frac{1}{1+u} du = \ln|1+u| + C_1 \] this standard form leads to a logarithm function. The right side required substitution, recognizing \( v = x^2 \), yielding: \[ \int \frac{1}{2} x e^{x^2} dx = \frac{1}{4} e^{x^2} + C_2 \] This highlights the importance of choosing a suitable substitution that simplifies the problem into an easily computable form.
- Recognizing standard integral forms.
- Using substitution to simplify the integral calculation.
- Applying integration by parts when necessary.
Substitution Method
The substitution method in solving differential equations is a smart way to simplify complex expressions, particularly during integration. This method typically involves:
- Selecting a substitution that transforms complicated functions into simpler ones.
- Changing variables to new ones that make integration straightforward.