Chapter 5: Problem 13
Evaluate the indefinite integrals by using the given substitutions to reduce the integrals to standard form. $$\int \sqrt{x} \sin ^{2}\left(x^{3 / 2}-1\right) d x, \quad u=x^{3 / 2}-1$$
Short Answer
Expert verified
The indefinite integral evaluates to \( \frac{1}{3} (x^{3/2} - 1 - \frac{1}{2} \sin(2(x^{3/2} - 1))) + C \).
Step by step solution
01
Identify the Substitution
We are given the substitution \( u = x^{3/2} - 1 \) for the integral \( \int \sqrt{x} \sin^2(x^{3/2} - 1) \, dx \). Our goal is to express \( dx \) and other terms in terms of \( du \) and \( u \).
02
Differentiate the Substitution
Differentiate \( u \) with respect to \( x \):\[ \frac{du}{dx} = \frac{d}{dx}(x^{3/2} - 1) = \frac{3}{2}x^{1/2} \]Thus, we have \( du = \frac{3}{2}x^{1/2} \, dx \). Solve for \( x^{1/2} \, dx \):\[ x^{1/2} \, dx = \frac{2}{3} \, du \].
03
Express the Integral in Terms of u
Substitute the expression for \( x^{1/2} \, dx \) into the integral:\[ \int \sqrt{x} \sin^{2}(x^{3/2} - 1) \, dx = \int \sin^2(u) \cdot \frac{2}{3} \, du \].This simplifies to:\[ \frac{2}{3} \int \sin^2(u) \, du \].
04
Use the Trigonometric Identity
We use the identity \( \sin^2(u) = \frac{1 - \cos(2u)}{2} \) to simplify the integral:\[ \frac{2}{3} \int \left(\frac{1 - \cos(2u)}{2}\right) \, du = \frac{1}{3} \int (1 - \cos(2u)) \, du \].
05
Integrate the Simplified Expression
Integrate each term separately:\[ \int 1 \, du = u \]\[ \int \cos(2u) \, du = \frac{1}{2}\sin(2u) \]Substitute these back into the integral:\[ \frac{1}{3} \left( u - \frac{1}{2} \sin(2u) \right) + C \], where \( C \) is the constant of integration.
06
Substitute Back for x
Recall \( u = x^{3/2} - 1 \). Substitute \( u \) back into the integrated expression:\[ \frac{1}{3} \left( x^{3/2} - 1 - \frac{1}{2} \sin(2(x^{3/2} - 1)) \right) + C \].
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration by Substitution
Integration by substitution is a useful technique for solving indefinite integrals. This method transforms a complex integral into a simpler form. Here's how it works: you choose a substitution—usually a part of the integrand—and substitute it with a new variable. In the exercise given, the substitution is denoted by \( u = x^{3/2} - 1 \). This makes the integral easier to evaluate.
- First, you identify an expression within the integral to use as the substitution. Here, \( x^{3/2} - 1 \) is replaced by \( u \).
- Next, you compute the derivative of \( u \) with respect to \( x \), resulting in \( \frac{du}{dx} = \frac{3}{2}x^{1/2} \).
- This derivative is then used to express \( dx \) in terms of \( du \): \( x^{1/2} \, dx = \frac{2}{3} \, du \).
Trigonometric Identities
Trigonometric identities are essential tools that simplify the integration of trigonometric functions. In this exercise, after you've made the substitution, you encounter an integral involving \( \sin^2(u) \). The identity \( \sin^2(u) = \frac{1 - \cos(2u)}{2} \) is particularly useful.
- This identity transforms the integral of \( \sin^2(u) \) into a much simpler form.
- When applied, the integral becomes \( \frac{1}{3} \int (1 - \cos(2u)) \, du \).
- Trigonometric identities like this are powerful because they convert complex trigonometric expressions into polynomials, which are generally straightforward to integrate.
Differentiation
Differentiation plays a pivotal role in integration by substitution. It helps express one variable in terms of another, making the integration more accessible.
- In the example, to change variables from \( x \) to \( u \), you compute the derivative of the substitution function \( u = x^{3/2} - 1 \).
- The derivative, \( \frac{du}{dx} = \frac{3}{2}x^{1/2} \), allows you to express the original \( dx \) part of the integral as a function of \( du \).
- This transformation is vital as it translates the integral from one variable to another, opening up new pathways to solve it.