Chapter 4: Problem 65
Right, or wrong? Say which for each formula and give a brie reason for each answer. a. \(\int(2 x+1)^{2} d x=\frac{(2 x+1)^{3}}{3}+C\) b. \(\int 3(2 x+1)^{2} d x=(2 x+1)^{3}+C\) c. \(\int 6(2 x+1)^{2} d x=(2 x+1)^{3}+C\)
Short Answer
Expert verified
a: Wrong, b: Wrong, c: Right.
Step by step solution
01
Analyze Part a
The integral given is \(\int(2x+1)^{2}dx\). Using substitution \(u=2x+1\), then \(du=2dx\) or \(dx=\frac{1}{2}du\). The integral becomes \(\int u^2 \cdot \frac{1}{2} du\). The antiderivative of \(u^2\) is \(\frac{u^3}{3}\), so the integral is \(\frac{1}{2} \cdot \frac{u^3}{3} = \frac{(2x+1)^3}{6} + C\). The formula \(\frac{(2x+1)^{3}}{3} + C\) is incorrect because it lacks the factor of \(\frac{1}{2}\).
02
Analyze Part b
The integral here is \(\int 3(2x+1)^2 dx\). Using the same substitution \(u=2x+1\), \(dx=\frac{1}{2}du\). The integral becomes \(3 \cdot \int u^2 \cdot \frac{1}{2} du = \frac{3}{2} \cdot \int u^2 du\). The result is \(\frac{3}{2} \cdot \frac{u^3}{3} = \frac{(2x+1)^3}{2} + C\). The given formula \((2x+1)^3 + C\) is incorrect because \(\frac{1}{2}\) is missing.
03
Analyze Part c
The integral here is \(\int 6(2x+1)^2 dx\). Using the same substitution, \(u=2x+1\), \(dx=\frac{1}{2}du\). The integral becomes \(6 \cdot \int u^2 \cdot \frac{1}{2} du = 3 \cdot \int u^2 du\). The result is \(3 \cdot \frac{u^3}{3} = (2x+1)^3 + C\). The given formula matches the integration result, so it is correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
In integral calculus, the substitution method is a technique used to simplify integration problems by making a substitution that converts the integral into a more manageable form. Imagine substitution as a clever way of changing variables that transforms complex expressions into simpler ones. Here's how it typically works:
- First, identify a part of the integrand (the function being integrated) that can be set equal to a new variable. This is your substitution. For example, if you have \(2x+1\), you can set \(u = 2x+1\).
- Next, compute the derivative of your substitution choice in terms of \(dx\). In our example, the derivative would be \(du = 2dx\) or \(dx = \frac{1}{2} du\).
- Replace \(dx\) and the original integral function with their equivalents in terms of \(du\) and \(u\), respectively.
- Integrate the simpler function of \(u\) and solve for \(u\).
Indefinite Integral
An indefinite integral, in mathematics, refers to the general form of an antiderivative. It represents a family of functions, each differing by a constant, whose derivative is the given function. In symbolic terms, the indefinite integral of a function \(f(x)\) is written as \(\int f(x) \, dx\).Indefinite integrals are easy to spot because they do not have upper and lower limits, unlike definite integrals which calculate a specific area under a curve:
- The result of an indefinite integral includes a constant \(C\), known as the constant of integration. This constant accounts for the fact that differentiation of a constant gives zero, meaning multiple functions can share the same derivative.
- An indefinite integral represents all possible antiderivatives of a function.
- The notation does not have numerical limits, hence the name 'indefinite.'
Antiderivative
An antiderivative is essentially the opposite of a derivative. While differentiation deals with finding the rate of change of a function, finding an antiderivative involves determining the original function given its derivative.Every continuously differentiable function has an antiderivative. Here's what you need to know:
- The process of finding an antiderivative is called integration.
- Antiderivatives are not unique. If \(F(x)\) is an antiderivative of \(f(x)\), then any function of the form \(F(x) + C\), where \(C\) is a constant, is also an antiderivative of \(f(x)\).
- Planning to reach these functions involves reversing differentiation rules, such as remembering that the derivative of \(x^n\) is \(n\cdot x^{n-1}\), so its antiderivative would return \(\frac{x^{n+1}}{n+1}+C\).