Chapter 3: Problem 5
Find \(d y / d x\). $$y=\csc x-4 \sqrt{x}+7$$
Short Answer
Expert verified
\( \frac{dy}{dx} = -\csc x \cot x - \frac{2}{\sqrt{x}} \).
Step by step solution
01
Differentiate the Cosecant Function
To find the derivative of the function, we start by differentiating each term separately. The first term is \( \csc x \). Remember that \( \csc x = \frac{1}{\sin x} \). The derivative is \( \frac{d}{dx}[\csc x] = -\csc x \cot x \).
02
Differentiate the Square Root Term
Next, differentiate the term \(-4 \sqrt{x}\). Since \( \sqrt{x} = x^{1/2} \), use the power rule: \( \frac{d}{dx}[x^{n}] = n x^{n-1} \). For \( x^{1/2} \), it becomes \( \frac{1}{2}x^{-1/2} \). Therefore, \( \frac{d}{dx}[-4\sqrt{x}] = -4 \cdot \frac{1}{2} x^{-1/2} = -2 x^{-1/2} \).
03
Differentiate the Constant Term
The final term is the constant \( 7 \). The derivative of any constant is zero. Therefore, \( \frac{d}{dx}[7] = 0 \).
04
Combine the Derivatives
Combine the results of the previous steps to find the complete derivative. The derivative of the entire function \( y = \csc x - 4 \sqrt{x} + 7 \) is \( \frac{dy}{dx} = -\csc x \cot x - 2 x^{-1/2} + 0 \). Simplifying gives \( \frac{dy}{dx} = -\csc x \cot x - \frac{2}{\sqrt{x}} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiation Techniques
Differentiation is a crucial concept in calculus. It allows us to understand how a function changes at any given point. The process involves taking derivatives, which are formulas that provide the rate of change of a function. When approaching a problem, various differentiation techniques can be employed to tackle functions with different characteristics.
- **Product Rule:** Used when dealing with functions that are products of two functions. If you have a product of functions, the derivative brings in both functions and their individual derivatives.
- **Quotient Rule:** Similar to the product rule but applicable to divisions of functions.
- **Chain Rule:** Essential when you have compositions of functions, meaning one function inside another.
- **Power Rule:** This is probably the most essential and simplest technique, ideal for differentiating polynomials.
Cosecant Function
The cosecant function, denoted as \( \csc x \), is important in trigonometry and calculus. It is the reciprocal of the sine function so \( \csc x = \frac{1}{\sin x} \). For differentiation purposes, the derivative of \( \csc x \) has a specific form. The derivative formula is: \[ \frac{d}{dx}[\csc x] = -\csc x \cot x \]The derivative involves both the cosecant and cotangent functions. This means that a small change in \( x \) leads to a change in \( \csc x \), and this rate of change is influenced by the value of \( \cot x \) (cotangent of \( x \)).
- **Why is it negative?** The change in the cosecant function is negative due to the chain rule applied to the reciprocal function in combination with the sine function's derivative.
- **Use in Calculus:** Recognizing this derivative is essential when dealing with integrals and derivatives that involve \( \csc x \).
Power Rule
The power rule is a fundamental tool in calculus. It provides a quick way to find the derivative of power functions. When you have a function \( x^n \), the power rule states that the derivative is given by multiplying the power by the coefficient in front and then subtracting one from the power. The formula is: \[ \frac{d}{dx}[x^{n}] = n x^{n-1} \]This rule is remarkably straightforward and requires no complex calculations. It can be applied to polynomials directly or any function that can be expressed as a power of \( x \). When applying this to a square root, remember that \( \sqrt{x} = x^{1/2} \).
- **Example Application:** If you need to differentiate \( \sqrt{x} \), rewrite it as \( x^{1/2} \) and apply the power rule to get \( \frac{1}{2}x^{-1/2} \).
- **Multiple Terms:** The power rule can be applied to each term separately in a polynomial or combination of terms, making it versatile for various differentiation tasks.