/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Find the first and second deriva... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the first and second derivatives. $$w=3 z^{7}-7 z^{3}+21 z^{2}$$

Short Answer

Expert verified
The first derivative is \( 21z^6 - 21z^2 + 42z \), and the second derivative is \( 126z^5 - 42z + 42 \).

Step by step solution

01

Set Up the Function

Identify the function we want to differentiate. In this case, it's given as \[ w = 3z^7 - 7z^3 + 21z^2. \]
02

First Derivative

Apply the power rule for differentiation to each term of the function. The power rule states that if \( f(z) = az^n \), then \( f'(z) = anz^{n-1} \). This leads to:\[ \frac{dw}{dz} = 3 \times 7z^{7-1} - 7 \times 3z^{3-1} + 21 \times 2z^{2-1}. \]Simplifying, we have:\[ \frac{dw}{dz} = 21z^6 - 21z^2 + 42z. \]
03

Simplifying the First Derivative

Notice there is a common factor in the first derivative expression:\[ \frac{dw}{dz} = 21z^6 - 21z^2 + 42z. \]Factor out the common factor of 21:\[ \frac{dw}{dz} = 21(z^6 - z^2 + 2z). \]
04

Second Derivative

Differentiate the simplified first derivative function \( \frac{dw}{dz} \) to find the second derivative. Again, apply the power rule to each term:\[ \frac{d^2w}{dz^2} = 21 \times (6z^{6-1} - 2z^{2-1} + 2). \]Simplifying gives:\[ \frac{d^2w}{dz^2} = 126z^5 - 42z + 42. \]
05

Final Expression of the Second Derivative

Combine like terms if possible; here there are none, so the final expression for the second derivative is:\[ \frac{d^2w}{dz^2} = 126z^5 - 42z + 42. \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule
The power rule is a fundamental rule for finding derivatives in calculus. It allows us to differentiate expressions where the variable is raised to a power. When using the power rule, if you have a function of the form \( f(z) = az^n \), the derivative is found by multiplying the exponent \( n \) by the coefficient \( a \), and then reducing the exponent by one.
For example, in the term \( 3z^7 \), applying the power rule gives us \( 7 \times 3z^{7-1} = 21z^6 \). This method is efficient for polynomial expressions and forms the backbone of more complex differentiation tasks.
The simplicity of the power rule is due to the fact that each term is treated separately. Ensure to reduce the exponent by exactly one, which reflects how the rate of change is inherently tied to each increase in power.
First Derivative
The first derivative of a function provides us with valuable information about the slope or inclination of the curve at any given point. In simpler terms, it tells us how fast or slow the function is changing.
For the function \( w = 3z^7 - 7z^3 + 21z^2 \), applying the power rule to each term separately gives us the first derivative:
  • \( 21z^6 \)
  • \(-21z^2 \)
  • \(42z \)

Thus, the expression for the first derivative is \( \frac{dw}{dz} = 21z^6 - 21z^2 + 42z \). This expression can tell us the nature of the curve, such as whether it is increasing or decreasing at various points, and where it might have a peak or a dip.
Second Derivative
Finding the second derivative involves differentiating the first derivative. While the first derivative tells us about the rate of change, the second derivative gives information on the curvature or concavity of the function.
For the expression \( 21(z^6 - z^2 + 2z) \), applying the power rule once more to each term, you get:
  • \( 126z^5 \)
  • \(-42z \)
  • \(42 \)

This results in the second derivative \( \frac{d^2w}{dz^2} = 126z^5 - 42z + 42 \). The second derivative can indicate the points of inflection, where the curve changes from concave to convex or vice versa.
Differentiation
Differentiation is a key operation in calculus that focuses on computing the derivative of functions. It is vital in understanding the behavior of a function's graph. In practical terms, differentiation helps in finding the slope and curvature, analyzing rates of change, and determining local extrema.
The steps for differentiation generally include:
  • Identifying each term in the function
  • Applying rules such as the power rule to find derivatives
  • Simplifying the expression to get cleaner results

In the exercise, differentiation begins by identifying the function \( w = 3z^7 - 7z^3 + 21z^2 \) and then progressing through finding the first and second derivatives using the power rule. This technique provides a structured approach to analyzing and solving problems involving rates and slopes efficiently.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use a CAS to estimate the magnitude of the error in using the linearization in place of the function over a specified interval \(I\). Perform the following steps: a. Plot the function \(f\) over \(I\) b. Find the linearization \(L\) of the function at the point \(a\) c. Plot \(f\) and \(L\) together on a single graph. d. Plot the absolute error \(|f(x)-L(x)|\) over \(I\) and find its maximum value. e. From your graph in part (d), estimate as large a \(\delta>0\) as you can, satisfying \(|x-a|<\delta \quad \Rightarrow \quad|f(x)-L(x)|<\epsilon\) for \(\epsilon=0.5,0.1,\) and \(0.01 .\) Then check graphically to see if your \(\delta\) -estimate holds true. $$f(x)=\sqrt{x}-\sin x, \quad[0,2 \pi], \quad a=2$$

Use a CAS to perform the following steps a. Plot the equation with the implicit plotter of a CAS. Check to see that the given point \(P\) satisfies the equation. b. Using implicit differentiation, find a formula for the derivative \(d y / d x\) and evaluate it at the given point \(P\). c. Use the slope found in part (b) to find an equation for the tangent line to the curve at \(P .\) Then plot the implicit curve and tangent line together on a single graph. $$x+\tan \left(\frac{y}{x}\right)=2, \quad P\left(1, \frac{\pi}{4}\right)$$

Find \(d y / d t\) $$y=\sin ^{2}(\pi t-2)$$

Two ships are steaming straight away from a point \(O\) along routes that make a \(120^{\circ}\) angle. Ship \(A\) moves at 14 knots (nautical miles per hour; a nautical mile is \(1852 \mathrm{m}\) ). Ship \(B\) moves at 21 knots. How fast are the ships moving apart when \(O A=5\) and \(O B=3\) nautical miles?

In the late 1860 s, Adolf Fick, a professor of physiology in the Faculty of Medicine in Würzberg, Germany, developed one of the methods we use today for measuring how much blood your heart pumps in a minute. Your cardiac output as you read this sentence is probably about \(7 \mathrm{L} / \mathrm{min} .\) At rest it is likely to be a bit under \(6 \mathrm{L} / \mathrm{min}\). If you are a trained marathon runner running a marathon, your cardiac output can be as high as \(30 \mathrm{L} / \mathrm{min}\). Your cardiac output can be calculated with the formula $$y=\frac{Q}{D},$$ where \(Q\) is the number of milliliters of \(\mathrm{CO}_{2}\) you exhale in a minute and \(D\) is the difference between the \(\mathrm{CO}_{2}\) concentration \((\mathrm{mL} / \mathrm{L})\) in the blood pumped to the lungs and the \(\mathrm{CO}_{2}\) concentration in the blood returning from the lungs. With \(Q=233 \mathrm{mL} / \mathrm{min}\) and \(D=97-56=41 \mathrm{mL} / \mathrm{L}\), \(y=\frac{233 \mathrm{mL} / \mathrm{min}}{41 \mathrm{mL} / \mathrm{L}} \approx 5.68 \mathrm{L} / \mathrm{min}\), fairly close to the \(6 \mathrm{L} / \mathrm{min}\) that most people have at basal (resting) conditions. (Data courtesy of J. Kenneth Herd, M.D., Quillan College of Medicine, East Tennessee State University.) Suppose that when \(Q=233\) and \(D=41,\) we also know that \(D\) is decreasing at the rate of 2 units a minute but that \(Q\) remains unchanged. What is happening to the cardiac output?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.