/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 Find \(y^{(4)}=d^{4} y / d x^{4}... [FREE SOLUTION] | 91Ó°ÊÓ

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Find \(y^{(4)}=d^{4} y / d x^{4}\) if a. \(y=-2 \sin x\) b. \(y=9 \cos x\)

Short Answer

Expert verified
a. \(y^{(4)} = -2 \sin x\); b. \(y^{(4)} = 9 \cos x\).

Step by step solution

01

Understand the Problem

We are asked to find the fourth derivative, noted as \(y^{(4)}\), for each of the given functions: \(y = -2 \sin x\) and \(y = 9 \cos x\). This involves taking the derivative of the given function four times.
02

Find First Derivative of a. \(y = -2 \sin x\)

Use the derivative rule for sine, which is \((\sin x)' = \cos x\). Thus, the first derivative is \(y' = -2 \cos x\).
03

Find Second Derivative of a. \(y' = -2 \cos x\)

Use the derivative rule for cosine, which is \((\cos x)' = -\sin x\). Therefore, the second derivative is \(y'' = 2 \sin x\).
04

Find Third Derivative of a. \(y'' = 2 \sin x\)

Again, apply the rule for sine: \((\sin x)' = \cos x\), giving us \(y''' = 2 \cos x\).
05

Find Fourth Derivative of a. \(y''' = 2 \cos x\)

Apply the derivative rule for cosine: \((\cos x)' = -\sin x\), resulting in \(y^{(4)} = -2 \sin x\).
06

Find First Derivative of b. \(y = 9 \cos x\)

The derivative of cosine is \((\cos x)' = -\sin x\). Therefore, the first derivative is \(y' = -9 \sin x\).
07

Find Second Derivative of b. \(y' = -9 \sin x\)

Using the rule \((\sin x)' = \cos x\), the second derivative is \(y'' = -9 \cos x\).
08

Find Third Derivative of b. \(y'' = -9 \cos x\)

Using the rule for cosine again, \((\cos x)' = -\sin x\), the third derivative is \(y''' = 9 \sin x\).
09

Find Fourth Derivative of b. \(y''' = 9 \sin x\)

Apply the sine rule: \((\sin x)' = \cos x\), resulting in \(y^{(4)} = 9 \cos x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative of Trigonometric Functions
Derivatives tell us how a function changes at any given point, and when it comes to trigonometric functions, there are well-known rules. These standard rules make finding derivatives straightforward. For sine and cosine, the rules are:
  • The derivative of \( \sin x \) is \( \cos x \).
  • The derivative of \( \cos x \) is \( -\sin x \).

The cyclic nature of these derivatives means they repeat after a set number of calculations. Understanding these rules is crucial when solving calculus problems involving trigonometric functions. Figuring out each step carefully can make the whole process more intuitive.
When you encounter a problem like finding the fourth derivative, you apply these rules repeatedly. For example, if you begin with \( y = -2 \sin x \), the first derivative becomes \( y' = -2 \cos x \), and so on until you reach the fourth.
Calculus Problem Solving
Calculus requires careful, step-by-step problem-solving skills. This involves understanding the problem, applying derivative rules correctly, and keeping track of each step. Often, calculus problems break down neatly if you approach them methodically:
  • Start by reading the problem carefully and defining what you need - in our case, the fourth derivative.
  • Apply the relevant derivative rules successively.
  • Check each step to ensure it aligns with the rules and calculations are accurately carried out.

By focusing on one step at a time, it's easier to manage even complex calculus problems. Visual aids, such as differentiating each derivative stage, can also provide clarity. It's like following a recipe – each step builds on the last to form the complete solution. Ensuring each part of the work is correct leads to success in the final solution. This systematic problem-solving capability is a core part of calculus and mathematics in general.
Higher Order Derivatives
Higher order derivatives extend the concept of a derivative beyond the first derivative. They describe the rate of change of the derivative itself, which can be useful for understanding various physical phenomena like acceleration in physics.
  • The first derivative of a function describes its slope or gradient at a point.
  • The second derivative provides further insight, often concerning concavity or curvature.
  • A higher order derivative, like the fourth derivative, continues this exploration of change.

With trigonometric functions like \( \sin x \) and \( \cos x \), higher order derivatives showcase a periodic pattern or cycle. For instance, differentiating \( y = -2 \sin x \) multiple times leads back to the original function, reflecting these properties. Therefore, understanding higher order derivatives helps deeply understand these mathematical patterns. This can be particularly useful when modeling cycles or periodic behaviors in real-world scenarios.

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Most popular questions from this chapter

Suppose that functions \(f\) and \(g\) and their derivatives with respect to \(x\) have the following values at \(x=2\) and \(x=3\) $$\begin{array}{ccccc}\hline x & f(x) & g(x) & f^{\prime}(x) & g^{\prime}(x) \\\\\hline 2 & 8 & 2 & 1 / 3 & -3 \\ 3 & 3 & -4 & 2 \pi & 5 \\\\\hline\end{array}$$ Find the derivatives with respect to \(x\) of the following combinations at the given value of \(x\) a. \(2 f(x), \quad x=2\) b. \(f(x)+g(x), \quad x=3\) c. \(f(x) \cdot g(x), \quad x=3\) d. \(f(x) / g(x), \quad x=2\) e. \(f(g(x)), \quad x=2\) f. \(\sqrt{f(x)}, \quad x=2\) g. \(1 / g^{2}(x), \quad x=3\) h. \(\sqrt{f^{2}(x)+g^{2}(x)}, \quad x=2\)

For oscillations of small amplitude (short swings), we may safely model the relationship between the period \(T\) and the length \(L\) of a simple pendulum with the equation $$T=2 \pi \sqrt{\frac{L}{g}}$$where \(g\) is the constant acceleration of gravity at the pendulum's location. If we measure \(g\) in centimeters per second squared, we measure \(L\) in centimeters and \(T\) in seconds. If the pendulum is made of metal, its length will vary with temperature, either increasing or decreasing at a rate that is roughly proportional to \(L\). In symbols, with \(u\) being temperature and \(k\) the proportionality constant, $$\frac{d L}{d u}=k L$$ Assuming this to be the case, show that the rate at which the period changes with respect to temperature is \(k T / 2\)

Use a CAS to estimate the magnitude of the error in using the linearization in place of the function over a specified interval \(I\). Perform the following steps: a. Plot the function \(f\) over \(I\) b. Find the linearization \(L\) of the function at the point \(a\) c. Plot \(f\) and \(L\) together on a single graph. d. Plot the absolute error \(|f(x)-L(x)|\) over \(I\) and find its maximum value. e. From your graph in part (d), estimate as large a \(\delta>0\) as you can, satisfying \(|x-a|<\delta \quad \Rightarrow \quad|f(x)-L(x)|<\epsilon\) for \(\epsilon=0.5,0.1,\) and \(0.01 .\) Then check graphically to see if your \(\delta\) -estimate holds true. $$f(x)=\sqrt{x}-\sin x, \quad[0,2 \pi], \quad a=2$$

Give the position function \(s=f(t)\) of an object moving along the \(s\) -axis as a function of time \(t\). Graph \(f\) together with the velocity function \(v(t)=d s / d t=f^{\prime}(t)\) and the acceleration function \(a(t)=d^{2} s / d t^{2}=f^{\prime \prime}(t) .\) Comment on the object's behavior in relation to the signs and values of \(v\) and \(a .\) Include in your commentary such topics as the following: a. When is the object momentarily at rest? b. When does it move to the left (down) or to the right (up)? c. When does it change direction? d. When does it speed up and slow down? e. When is it moving fastest (highest speed)? Slowest? f. When is it farthest from the axis origin? $$s=t^{2}-3 t+2, \quad 0 \leq t \leq 5$$

a. Let \(Q(x)=b_{0}+b_{1}(x-a)+b_{2}(x-a)^{2}\) be a quadratic approximation to \(f(x)\) at \(x=a\) with the properties: i) \(Q(a)=f(a)\) ii) \(Q^{\prime}(a)=f^{\prime}(a)\) iii) \(Q^{\prime \prime}(a)=f^{\prime \prime}(a)\) Determine the coefficients \(b_{0}, b_{1},\) and \(b_{2}\) b. Find the quadratic approximation to \(f(x)=1 /(1-x)\) at \(x=0\) c. Graph \(f(x)=1 /(1-x)\) and its quadratic approximation at \(x=0 .\) Then zoom in on the two graphs at the point (0,1) Comment on what you see. d. Find the quadratic approximation to \(g(x)=1 / x\) at \(x=1\) Graph \(g\) and its quadratic approximation together. Comment on what you see. e. Find the quadratic approximation to \(h(x)=\sqrt{1+x}\) at \(x=0 .\) Graph \(h\) and its quadratic approximation together. Comment on what you see. f. What are the linearizations of \(f, g,\) and \(h\) at the respective points in parts (b), (d), and (e)?

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