/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 When a circular plate of metal i... [FREE SOLUTION] | 91Ó°ÊÓ

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When a circular plate of metal is heated in an oven, its radius increases at the rate of \(0.01 \mathrm{cm} / \mathrm{min}\). At what rate is the plate's area increasing when the radius is \(50 \mathrm{cm} ?\)

Short Answer

Expert verified
The area is increasing at a rate of \( \pi \) cm\(^2\)/min when the radius is 50 cm.

Step by step solution

01

Understand the Problem

We are given that the radius \( r \) of a circular plate increases at a rate of \( 0.01 \) cm/min. We need to find the rate at which the area \( A \) of the circular plate is increasing when the radius is \( 50 \) cm.
02

Establish the Relationship

The area \( A \) of a circle is given by the formula \( A = \pi r^2 \). To find the rate of change of the area, we need to differentiate this formula with respect to time \( t \).
03

Differentiate the Area

Differentiate \( A = \pi r^2 \) with respect to time \( t \) using the chain rule, which gives \( \frac{dA}{dt} = 2\pi r \frac{dr}{dt} \).
04

Substitute Known Values

We know \( r = 50 \) cm and \( \frac{dr}{dt} = 0.01 \) cm/min. Substitute these values into the derivative: \[ \frac{dA}{dt} = 2\pi (50) (0.01) \].
05

Calculate the Rate of Change

Perform the calculation: \[ \frac{dA}{dt} = 2\pi (50) (0.01) = \pi \]. The rate at which the area is increasing is \( \pi \) cm\(^2\)/min.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a key concept in calculus. It helps us understand how functions change. In this exercise, we're looking at how the area of a circular plate changes with time. The relationship between the area of a circle and its radius is given by the formula \( A = \pi r^2 \). This formula tells us how the area depends on the radius. To find how the area changes, we need to differentiate this expression with respect to time. This means we'll be considering how both the radius and area change over time. Differentiating \( A = \pi r^2 \) gives us \( \frac{dA}{dt} = 2\pi r \frac{dr}{dt} \). This result shows the rate of change of area with respect to time, combining the circle's geometry with the rate of radius change. Differentiation here allows us to transform static geometric relationships into dynamic rates of change. Differentiation is essential for analyzing how various quantities change over time.
Chain Rule
The chain rule is a fundamental principle in calculus. It helps us differentiate functions that are composed of other functions. In this problem, we are dealing with the area of a circle, expressed in terms of its radius. The radius itself is changing with time, which means the area changes indirectly as the radius changes. To apply the chain rule, we start with the formula for the area: \( A = \pi r^2 \). Differentiating with respect to time, we use the chain rule: \( \frac{dA}{dt} = \frac{d}{dt}(\pi r^2) \). Through the chain rule, this becomes \( \frac{dA}{dt} = 2\pi r \frac{dr}{dt} \).
  • \( \frac{dr}{dt} \) is the rate of change of the radius, given as \( 0.01 \) cm/min.
  • \( 2\pi r \) comes from differentiating \( \pi r^2 \) in terms of \( r \), then accounting for the change in \( r \) over \( t \).
Thus, the chain rule links the change in area due to the time-dependent change in radius. It is an indispensable tool for problems involving related rates.
Geometry of Circles
Understanding the geometry of circles is crucial when analyzing problems like this one. The circle is a simple yet fundamental shape in mathematics. Its area is determined by its radius, with the formula \( A = \pi r^2 \). This formula is derived from the circle's intrinsic properties and is central to many mathematical applications. In this problem, as the circle's radius expands, its area also increases. The geometry tells us that for every unit increase in the radius, the area increases by much more due to the square power in the formula.
  • The formula for the circumference, \( C = 2\pi r \), supports understanding that both circumference and area depend on \( \pi \), revealing how expansive these properties become.
  • As shown, geometry guides us to understand why the area increases quadratically with the radius.
Knowing the geometry of circles allows us to predict and calculate changes in properties like the area when other parameters such as the radius change.

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