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Find \(d y / d x\). $$y=\frac{3}{x}+5 \sin x$$

Short Answer

Expert verified
The derivative is \(dy/dx = -\frac{3}{x^2} + 5\cos x\).

Step by step solution

01

Differentiate the terms separately

First, differentiate each term of the function separately. Begin with the term \(y = \frac{3}{x}\). Recall that \(\frac{3}{x}\) can be rewritten as \(3x^{-1}\). Differentiating \(3x^{-1}\) with respect to \(x\) gives:\[ \frac{d}{dx}(3x^{-1}) = 3(-1)x^{-2} = -\frac{3}{x^2} \]
02

Differentiate the sine function

Next, consider the trigonometric term \(5\sin x\). The derivative of \(\sin x\) is \(\cos x\). Therefore, differentiating \(5\sin x\) with respect to \(x\) gives:\[ \frac{d}{dx}(5\sin x) = 5\cos x \]
03

Combine the derivative results

Combine the results from Step 1 and Step 2 to find the overall derivative of the function \(y\):\[ \frac{dy}{dx} = -\frac{3}{x^2} + 5\cos x \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

derivative of trigonometric functions
Differentiating trigonometric functions is a fundamental part of calculus, which is essential for understanding how functions change. One of the most common trigonometric functions you will encounter is the sine function, denoted as \( \sin x \). The derivative of \( \sin x \) with respect to \( x \) is \( \cos x \). This means that at any point on the sine wave, the slope is determined by the cosine of that point.

When you have a constant multiplied by a trigonometric function, like in the term \( 5\sin x \), the constant can be factored out when differentiating. Therefore, the derivative of \( 5\sin x \) is simply \( 5\cos x \). This rule is quite handy and simplifies the process of differentiation.
  • Remember: The derivative of \( \sin x \) is \( \cos x \).
  • If multiplied by a constant, factor out the constant. E.g., \( 5\sin x \rightarrow 5\cos x \).
power rule
The power rule is a critical aspect of calculus, used to differentiate functions that are polynomials or can be rewritten as polynomials. It's particularly useful for expressions of the form \( x^n \), where \( n \) is any real number. According to the power rule, to find the derivative, you:
  • Multiply the exponent \( n \) by the coefficient of \( x^n \).
  • Subtract one from the exponent.
For example, if you have \( 3x^{-1} \), applying the power rule:

  • Bring down \( -1 \) to multiply by 3, giving \( 3(-1) = -3 \).
  • Subtract 1 from \( -1 \) to get \( -2 \), resulting in \(-3x^{-2} \).
So, the derivative of \( 3x^{-1} \) is \( -\frac{3}{x^2} \). This concept is especially helpful in calculus as it simplifies taking derivatives of many algebraic functions.
sum rule in differentiation
The sum rule is a straightforward yet powerful principle in differentiation. It states that the derivative of a sum of functions is the sum of their derivatives. This means if you have a function composed of several terms added together, you can differentiate each term independently and then add those results.

For instance, consider the function \( y = \frac{3}{x} + 5\sin x \). Using the sum rule, you differentiate each piece separately:

  • Apply the power rule to \( \frac{3}{x} \), rewritten as \( 3x^{-1} \), which gives \(-\frac{3}{x^2} \).
  • Differentiate \( 5\sin x \) using the derivative of trigonometric functions rule, giving \( 5\cos x \).
Finally, you combine the results:

\( \frac{dy}{dx} = -\frac{3}{x^2} + 5\cos x \). This rule simplifies the differentiation process, especially for functions that are sums of simpler functions.

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