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Find the derivatives of the functions. $$y=\frac{2 x+5}{3 x-2}$$

Short Answer

Expert verified
The derivative is \( y' = \frac{-19}{(3x - 2)^2} \).

Step by step solution

01

Identify the Quotient Rule

The function given, \(y = \frac{2x+5}{3x-2}\), is in the form of a quotient. To find its derivative, we need to apply the quotient rule which is given by \(\left(\frac{u}{v}\right)' = \frac{vu' - uv'}{v^2}\), where \(u = 2x + 5\) and \(v = 3x - 2\).
02

Differentiate the Numerator and Denominator

Calculate the derivatives of the numerator \(u\) and the denominator \(v\). For the numerator \(u = 2x + 5\), the derivative \(u' = 2\). For the denominator \(v = 3x - 2\), the derivative \(v' = 3\).
03

Apply the Quotient Rule

Substitute the values obtained into the quotient rule formula: \[ y' = \frac{(3x - 2)(2) - (2x + 5)(3)}{(3x - 2)^2} \]. Expand both products in the numerator.
04

Simplify the Numerator

Calculate each term in the numerator: \(3x \cdot 2 = 6x\), \(-2 \cdot 2 = -4\), \(2x \cdot 3 = 6x\), and \(5 \cdot 3 = 15\). Therefore, the numerator becomes \(6x - 4 - 6x - 15\).
05

Combine Terms in the Numerator

Combine and simplify the like terms in the numerator: \(6x - 6x - 4 - 15 = -19\).
06

Write the Simplified Derivative

The derivative of the function is \( y' = \frac{-19}{(3x - 2)^2} \). This is the simplest form of the derivative.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a core concept in calculus that deals with how a function changes as its input changes. When we differentiate a function, we're essentially finding the rate at which it changes.
For example, if you think about a car on a road, differentiation helps you know how its position changes over time.
For the function given in the exercise, it's set up as a quotient of two expressions. This means we'll use specific rules to find how this function behaves as its variable, in this case, 'x', changes.
Derivatives
Derivatives are the results we get when we apply the process of differentiation. They tell us how a function's output (or value) changes as 'x' changes.
In mathematics, derivatives can be denoted as "dy/dx" or as "y'" (read as y prime).
In the context of the exercise, we used the _Quotient Rule_ to find the derivative of the function. This rule is handy when dealing with functions given as fractions or quotients, like \(y = \frac{2x+5}{3x-2}\). Here, each component contributes to the overall rate of change in a precise way.
By finding the derivatives of individual parts—numerator and denominator—we can combine them to get the overall derivative, which gives us a full picture of the function's behavior.
Simplification in Calculus
Simplification is an important part of calculus that makes complex expressions easier to work with and interpret. Once differentiation is applied, the resulting derivative might look complicated.
It’s crucial to simplify to make sense of what the expression really tells us.
  • Simplified expressions are more concise and generally, they help us recognize patterns or properties we might otherwise miss.
  • In our exercise, after applying the Quotient Rule, we ended up with a complex expression in the form of a fraction.
  • The simplification involved combining like terms in the numerator to reach the expression \(-19\) for the derivative's numerator.
Breaking down the parts and reducing them to their simplest form helps in understanding the essential elements and properties of the function's behavior.

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