Chapter 3: Problem 10
Find \(d y / d x\). $$y=(\sin x+\cos x) \sec x$$
Short Answer
Expert verified
\( \frac{d y}{d x} = \sec^2 x \)
Step by step solution
01
Simplify the expression
Start by rewriting the given expression for easier differentiation: \( y = \sec x \sin x + \sec x \cos x \). Now, since \( \sec x = \frac{1}{\cos x} \), replace \( \sec x \) in both terms. The expression becomes \( y = \frac{\sin x}{\cos x} + 1 \).
02
Differentiate each term separately
Differentiate the expression \( y = \frac{\sin x}{\cos x} + 1 \) with respect to \( x \). The derivative of a constant, like 1, is 0. Use the quotient rule to differentiate \( \frac{\sin x}{\cos x} \), where \( u = \sin x \) and \( v = \cos x \).
03
Apply the quotient rule
The quotient rule formula is \( \frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \frac{du}{dx} - u \frac{dv}{dx}}{v^2} \). For \( u = \sin x \) and \( v = \cos x \), \( \frac{du}{dx} = \cos x \) and \( \frac{dv}{dx} = -\sin x \).
04
Substitute derivatives into the quotient rule
Using the derivatives found previously, substitute into the quotient rule: \( \frac{d}{dx} \left( \frac{\sin x}{\cos x} \right) = \frac{\cos x (\cos x) - \sin x (-\sin x)}{(\cos x)^2} = \frac{\cos^2 x + \sin^2 x}{\cos^2 x} \).
05
Simplify the derivative expression
Since \( \cos^2 x + \sin^2 x = 1 \) (from the Pythagorean identity), the expression simplifies to \( \frac{1}{\cos^2 x} = \sec^2 x \).
06
Write the final derivative result
Combine the derivative of the constant \(0\) with the result from step 5: \( \frac{d y}{d x} = \sec^2 x \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quotient Rule
The Quotient Rule is a vital tool in calculus when differentiating ratios of two functions. When you have a function like \( \frac{u}{v} \), where \( u \) and \( v \) are both differentiable functions of \( x \), you'll need the Quotient Rule to correctly find its derivative. This rule states:
- \( \frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \frac{du}{dx} - u \frac{dv}{dx}}{v^2} \)
- \( \frac{d}{dx} \left( \frac{\sin x}{\cos x} \right) = \frac{\cos x (\cos x) - \sin x (-\sin x)}{\cos^2 x} \)
Trigonometric Identities
Trigonometric identities simplify the process of differentiation, especially for functions involving sine, cosine, and other trigonometric terms. These identities are fundamental relationships that hold between various trigonometric functions.
- One crucial identity is the Pythagorean identity: \( \cos^2 x + \sin^2 x = 1 \). This identity facilitates simplifying derivative expressions.
- In solving derivatives like \( \frac{1}{\cos^2 x} \), recognizing that the numerator \( \cos^2 x + \sin^2 x = 1 \) allows us to simplify expressions efficiently.
Calculus Differentiation
Differentiation is the process that allows us to find the rate of change of a function with respect to a variable, typically \( x \). In calculus, differentiation involves generating the derivative of a function, which provides insights into how the function behaves.
- The derivative \( \frac{dy}{dx} \), represents the slope of the tangent line at any point on the curve \( y \).
- This concept is particularly powerful when applied to functions with trigonometric components, like \( y = (\sin x + \cos x) \sec x \).
- By systematically applying rules like the product, quotient, and chain rules, even complex expressions yield manageable results, such as the transformation from a layered expression into \( \sec^2 x \).