Chapter 2: Problem 31
Find the limits Are the functions continuous at the point being approached? $$\lim _{x \rightarrow \pi} \sin (x-\sin x)$$
Short Answer
Expert verified
The limit is 0, and the function is continuous at \( x = \pi \).
Step by step solution
01
Understand the problem
We need to find the limit of the function \( \sin(x - \sin x) \) as \( x \) approaches \( \pi \). Also, we must determine if this function is continuous at \( x=\pi \). This involves evaluating whether the limit of the function equals its value at that point.
02
Simplify the expression
The function inside the sine, \( x - \sin x \), gets closer to \( \pi - \sin \pi = \pi \) as \( x \) approaches \( \pi \) because \( \sin \pi = 0 \).
03
Apply limit to the sine function
Since \( \sin \) is continuous, \( \lim_{x \to \pi} \sin(x - \sin x) = \sin( \lim_{x \to \pi} (x - \sin x)) = \sin(\pi) \), and \( \sin(\pi) = 0 \).
04
Check continuity
A function is continuous at a point if the limit of the function as \( x \) approaches that point equals the function's value at that point. Here, \( f(x) = \sin(x - \sin x) \) and \( f(\pi) = \sin(\pi - \sin \pi) = \sin(\pi) = 0 \). Since \( \lim_{x \to \pi} f(x) = f(\pi) \), \( f(x) \) is continuous at \( x = \pi \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Continuity of Functions
Continuity in calculus is a fundamental concept that tells us when we can expect to smoothly transition from one point to another in a function. A function is said to be continuous at a point \( x = a \) if three specific conditions are met:
Next, we evaluate the limit of \( f(x) \) as \( x \to \pi \) and find it's \( 0 \). As \( \lim_{x \to \pi} f(x) = f(\pi) \), the function is continuous at \( x = \pi \). This seamless connection in the graph of the function at this point exemplifies continuity.
- The function \( f(x) \) is defined at \( x = a \).
- The limit \( \lim_{x \to a} f(x) \) exists.
- The limit equals the function's value, i.e., \( \lim_{x \to a} f(x) = f(a) \).
Next, we evaluate the limit of \( f(x) \) as \( x \to \pi \) and find it's \( 0 \). As \( \lim_{x \to \pi} f(x) = f(\pi) \), the function is continuous at \( x = \pi \). This seamless connection in the graph of the function at this point exemplifies continuity.
Sine Function
The sine function is a periodic and smooth function that oscillates between -1 and 1. It is one of the primary trigonometric functions and is often used to describe wave-like phenomena. The sine function is expressed as \( y = \sin(x) \), and it has several key properties:
- Periodicity: The sine function repeats every \( 2\pi \) radians, meaning \( \sin(x + 2\pi) = \sin(x) \).
- Odd Function: Satisfies \( \sin(-x) = -\sin(x) \).
- Continuous and smooth, with no breaks or jumps.
- Specific values, like \( \sin(0) = 0 \), \( \sin(\pi) = 0 \), and \( \sin(\pi/2) = 1 \).
Evaluating Limits
Evaluating limits is a crucial technique in calculus to understand the behavior of functions as they approach specific points. Limits are used to find the value that a function approaches as the input approaches a particular value, which is essential when determining continuity.When evaluating a limit, certain steps and techniques are beneficial:
- Direct Substitution: Start by substituting the point into the function, if possible.
- Simplification: Simplify the expression, particularly if substitution leads to an indeterminate form like \( \frac{0}{0} \).
- Continuity: Use known results about continuous functions to directly evaluate the limit.