/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Find the limits Are the function... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the limits Are the functions continuous at the point being approached? $$\lim _{x \rightarrow \pi} \sin (x-\sin x)$$

Short Answer

Expert verified
The limit is 0, and the function is continuous at \( x = \pi \).

Step by step solution

01

Understand the problem

We need to find the limit of the function \( \sin(x - \sin x) \) as \( x \) approaches \( \pi \). Also, we must determine if this function is continuous at \( x=\pi \). This involves evaluating whether the limit of the function equals its value at that point.
02

Simplify the expression

The function inside the sine, \( x - \sin x \), gets closer to \( \pi - \sin \pi = \pi \) as \( x \) approaches \( \pi \) because \( \sin \pi = 0 \).
03

Apply limit to the sine function

Since \( \sin \) is continuous, \( \lim_{x \to \pi} \sin(x - \sin x) = \sin( \lim_{x \to \pi} (x - \sin x)) = \sin(\pi) \), and \( \sin(\pi) = 0 \).
04

Check continuity

A function is continuous at a point if the limit of the function as \( x \) approaches that point equals the function's value at that point. Here, \( f(x) = \sin(x - \sin x) \) and \( f(\pi) = \sin(\pi - \sin \pi) = \sin(\pi) = 0 \). Since \( \lim_{x \to \pi} f(x) = f(\pi) \), \( f(x) \) is continuous at \( x = \pi \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Continuity of Functions
Continuity in calculus is a fundamental concept that tells us when we can expect to smoothly transition from one point to another in a function. A function is said to be continuous at a point \( x = a \) if three specific conditions are met:
  • The function \( f(x) \) is defined at \( x = a \).
  • The limit \( \lim_{x \to a} f(x) \) exists.
  • The limit equals the function's value, i.e., \( \lim_{x \to a} f(x) = f(a) \).
For example, consider the function \( f(x) = \sin(x - \sin x) \) at \( x = \pi \). We first check if \( f(x) \) is defined by evaluating it at this point. With \( f(\pi) = \sin(\pi - \sin \pi) = \sin(\pi) = 0 \), we see that it is defined.
Next, we evaluate the limit of \( f(x) \) as \( x \to \pi \) and find it's \( 0 \). As \( \lim_{x \to \pi} f(x) = f(\pi) \), the function is continuous at \( x = \pi \). This seamless connection in the graph of the function at this point exemplifies continuity.
Sine Function
The sine function is a periodic and smooth function that oscillates between -1 and 1. It is one of the primary trigonometric functions and is often used to describe wave-like phenomena. The sine function is expressed as \( y = \sin(x) \), and it has several key properties:
  • Periodicity: The sine function repeats every \( 2\pi \) radians, meaning \( \sin(x + 2\pi) = \sin(x) \).
  • Odd Function: Satisfies \( \sin(-x) = -\sin(x) \).
  • Continuous and smooth, with no breaks or jumps.
  • Specific values, like \( \sin(0) = 0 \), \( \sin(\pi) = 0 \), and \( \sin(\pi/2) = 1 \).
Understanding these properties helps when evaluating limits and determining continuity. In our case with the function \( \sin(x - \sin x) \), recognizing that sine is continuous means the limit \( \lim_{x \to \pi} \sin(x-\sin x) \) equals \( \sin(\pi) = 0 \). This predictability of sine's behavior aids in both limit evaluation and continuity confirmation.
Evaluating Limits
Evaluating limits is a crucial technique in calculus to understand the behavior of functions as they approach specific points. Limits are used to find the value that a function approaches as the input approaches a particular value, which is essential when determining continuity.When evaluating a limit, certain steps and techniques are beneficial:
  • Direct Substitution: Start by substituting the point into the function, if possible.
  • Simplification: Simplify the expression, particularly if substitution leads to an indeterminate form like \( \frac{0}{0} \).
  • Continuity: Use known results about continuous functions to directly evaluate the limit.
In the exercise, we dealt with \( \lim_{x \to \pi} \sin(x - \sin x) \). By examining \( x - \sin x \), we see as \( x \to \pi \), this simplifies to \( \pi \), since \( \sin(\pi) = 0 \). Hence, the sine continuity property allows direct evaluation: \( \lim_{x \to \pi} \sin(\pi) = \sin(\pi) = 0 \). This technique simplifies potentially complex problems, leading to straightforward solutions.

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