Chapter 2: Problem 17
Gives a function \(f(x)\) and numbers \(L, c,\) and \(\epsilon \geq 0 .\) In each case, find an open interval about \(c\) on which the inequality \(|f(x)-L|<\epsilon\) holds. Then give a value for \(\delta>0\) such that for all \(x\) satisfying \(0<|x-c|<\delta\) the inequality \(|f(x)-L|<\epsilon\) holds. \(f(x)=\sqrt{x+1}, \quad L=1, \quad c=0, \quad \epsilon=0.1\)
Short Answer
Step by step solution
Write the Inequality
Simplify the Inequality
Find the Open Interval
Choose \(\delta\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Epsilon-Delta
- \(\epsilon\) (epsilon) represents how close the output should be to the limit.
- \(\delta\) (delta) shows how close the input must be to \( c \) to ensure this closeness of the output.
Interval
- "Open interval" implies that the endpoints \(-0.19\) and \(0.21\) are not included, allowing for the flexibility necessary in limit discussions.
- Identifying the correct interval helps narrow down which values of \( x \) are acceptable while maintaining the specified proximity to the function's limit.
Inequality
- It ensures that the output values of the function \( f(x) \) stay within a "neighborhood" or bounded distance from the limit \( L \).
- By solving \(|\sqrt{x+1} - 1| < 0.1\), we find critical points that define where this condition holds true.
Square Root Function
- Square root functions are only defined for non-negative values of \( x + 1 \) in the real number system.
- They have a smooth, gradually increasing curve.