Chapter 17: Problem 44
Solve the differential equations.Some of the equations can be solved by the method of undetermined coefficients, but others cannot. $$y^{\prime \prime}+9 y=9 x-\cos x$$
Short Answer
Expert verified
The general solution is \(y(x) = C_1 \cos(3x) + C_2 \sin(3x) + x + \frac{9}{10} \cos x\).
Step by step solution
01
Identify the Type of Differential Equation
The given differential equation is \(y'' + 9y = 9x - \cos x\). This is a second-order linear non-homogeneous differential equation. We will apply the method of undetermined coefficients to solve it.
02
Find the Complementary Solution
To find the complementary solution, solve the associated homogeneous equation: \(y'' + 9y = 0\). The characteristic equation is \(r^2 + 9 = 0\), which has roots \(r = \pm 3i\). Hence, the complementary solution is \(y_c = C_1 \cos(3x) + C_2 \sin(3x)\).
03
Propose a Particular Solution
A particular solution for the non-homogeneous part \(9x - \cos x\) can be proposed.For the \(9x\) part, propose \(Ax + B\).For the \(-\cos x\) part, propose \(C \cos x + D \sin x\).Thus, the trial solution is \(y_p = Ax + B + C \cos x + D \sin x\).
04
Substitute and Solve for Coefficients
Differentiate the trial solution to find \(y_p''\), substitute \(y_p''\) and \(y_p\) into the original equation, and equate coefficients:- Substitute into \(y'' + 9y = 9x - \cos x\) to get a system of equations for \(A, B, C,\) and \(D\).- Solve these equations to find the coefficients. The result is \(A = 1\), \(B = 0\), \(C = \frac{9}{10}\), \(D = 0\).
05
Write the General Solution
The general solution is the sum of the complementary and particular solutions:\[ y(x) = C_1 \cos(3x) + C_2 \sin(3x) + x + \frac{9}{10} \cos x. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Method of Undetermined Coefficients
The method of undetermined coefficients is a powerful technique used to solve non-homogeneous linear differential equations. This method is generally applied when the non-homogeneous part of the equation is a simple function like polynomials, exponentials, sines, or cosines. It utilizes the fact that the solution to a differential equation consists of a complementary solution and a particular solution.
To apply the method:
To apply the method:
- Start by identifying the type of differential equation you are dealing with, ensuring it is linear and with constant coefficients.
- Formulate a guess for the particular solution based on the form of the non-homogeneous part. This involves assuming a structure for the solution and determining the unknown coefficients.
- Substitute this guessed particular solution back into the differential equation to form a system of equations for those coefficients.
- Solve the system to find the values of these coefficients, giving you the particular solution.
Non-Homogeneous Differential Equation
A non-homogeneous differential equation is characterized by the presence of a non-zero term that is independent of the function being solved. In other words, its structure is given by:
The solution to such equations involves finding two different types of solutions:
- \( L[y] = g(x) \)
- where \( L \) is a linear differential operator, and \( g(x) \) is the non-homogeneous part, not equal to zero.
The solution to such equations involves finding two different types of solutions:
- The complementary solution, which solves the related homogeneous equation.
- The particular solution, which accounts for the non-homogeneous component.
Complementary Solution
The complementary solution is a vital component in solving both homogeneous and non-homogeneous differential equations. It represents the solution to the associated homogeneous equation:
In our example, the differential equation \( y'' + 9y = 0 \) is solved by finding the roots of the characteristic equation \( r^2 + 9 = 0 \). These roots are complex, \( r = \pm 3i \), leading to a complementary solution of the form:
- For an equation like \( y'' + ay' + by = 0 \), finding solutions involves solving the characteristic equation \( r^2 + ar + b = 0 \).
In our example, the differential equation \( y'' + 9y = 0 \) is solved by finding the roots of the characteristic equation \( r^2 + 9 = 0 \). These roots are complex, \( r = \pm 3i \), leading to a complementary solution of the form:
- \( y_c = C_1 \cos(3x) + C_2 \sin(3x) \)
Particular Solution
The particular solution is the part of the solution that accounts for the non-homogeneous component of a differential equation. Using the method of undetermined coefficients, a guessed form is assumed which includes arbitrary constants to solve for. The selection of this trial solution relies on mimicking the form of the non-homogeneous portion of the equation.
For instance, considering the term \( 9x - \cos x \) from our example equation, a good trial solution would take on forms that handle each part:
After these calculations, you derive a specific solution that fits the non-homogeneous aspects, completing the overall general solution when added to the complementary solution.
For instance, considering the term \( 9x - \cos x \) from our example equation, a good trial solution would take on forms that handle each part:
- For the linear term \( 9x \), a guess of \( Ax + B \) is used.
- For the trigonometric part \( -\cos x \), a guess of \( C \cos x + D \sin x \) is made.
After these calculations, you derive a specific solution that fits the non-homogeneous aspects, completing the overall general solution when added to the complementary solution.