/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 Let \(C\) be the ellipse in whic... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(C\) be the ellipse in which the plane \(2 x+3 y-z=0\) meets the cylinder \(x^{2}+y^{2}=12 .\) Show, without evaluating either line integral directly, that the circulation of the field \(\mathbf{F}=x \mathbf{i}+y \mathbf{j}+z \mathbf{k}\) around \(C\) in either direction is zero.

Short Answer

Expert verified
The circulation is zero because the curl of the field is zero.

Step by step solution

01

Understand the Problem

We are asked to find the circulation of the vector field \( \mathbf{F} = x \mathbf{i} + y \mathbf{j} + z \mathbf{k} \) around the ellipse where the plane \( 2x + 3y - z = 0 \) intersects the cylinder \( x^2 + y^2 = 12 \). We know that circulation can be related to the line integral of a vector field over a closed curve.
02

Use Stokes' Theorem

Stokes' Theorem relates the line integral of a vector field \( \mathbf{F} \) over a closed curve \( C \) to the surface integral of the curl of \( \mathbf{F} \) over a surface \( S \) that is bounded by \( C \). Mathematically, it states that \( \oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (abla \times \mathbf{F}) \cdot d\mathbf{S} \). We can use this theorem since \( C \) is a closed curve.
03

Compute the Curl of the Field

The curl of a vector field \( \mathbf{F} = x\mathbf{i} + y\mathbf{j} + z\mathbf{k} \) is computed using the determinant form:\[abla \times \mathbf{F} = \begin{vmatrix}\mathbf{i} & \mathbf{j} & \mathbf{k} \\frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \x & y & z\end{vmatrix}\]Calculating this determinant, we find \( abla \times \mathbf{F} = \mathbf{0} \).
04

Apply the Result of the Curl to Stokes' Theorem

Since the curl \( abla \times \mathbf{F} = \mathbf{0} \), the surface integral \( \iint_S (abla \times \mathbf{F}) \cdot d\mathbf{S} = 0 \). By Stokes' Theorem, the line integral \( \oint_C \mathbf{F} \cdot d\mathbf{r} \) equals this surface integral, which is zero. Thus, the circulation around \( C \) is zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Calculus
Vector calculus is a branch of mathematics that deals with vector fields and differential operators. It extends the principles of calculus to multi-dimensional spaces. In vector calculus, you deal with quantities that have both a magnitude and a direction, such as velocity, force, or fields like magnetic or electric fields.

Some of the basic operations in vector calculus include:
  • Gradient: Applies to scalar fields and points to the direction of greatest increase of a function.
  • Divergence: Measures the rate at which "stuff" is exiting or entering a point in a vector field.
  • Curl: Indicates the rotation of a vector field at a point.
Vector calculus is essential in fields like physics and engineering for modeling and solving real-world problems. It provides tools to describe how fields change in space, especially in contexts involving electromagnetism and fluid dynamics.
Line Integral
A line integral, often encountered in vector calculus, is a method to integrate a function along a curve or path. It's an extension of definite integrals to functions of several variables. Typically, line integrals are used to find the work done by a force field when an object moves along a path.

In formal terms, if you have a vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \) and a smooth curve \( C \), the line integral of \( \mathbf{F} \) along \( C \) is written as \( \int_C \mathbf{F} \cdot d\mathbf{r} \), which expands into the integral form \( \int_C (P dx + Q dy + R dz) \). Here, \( d\mathbf{r} \) is a small vector element along the curve.

Line integrals are widely used in physics, for example, to compute the work done by electric and magnetic fields on charges.
Curl of a Vector Field
The curl of a vector field is a measure of its rotational effect at a given point. It is a vector that describes the infinitesimal rotation or circulation at each point in the field. The mathematical representation of the curl is obtained using a cross product of the del operator with the vector field.

For a vector field \( \mathbf{F} = x\mathbf{i} + y\mathbf{j} + z\mathbf{k} \), the curl is calculated as:\[abla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \x & y & z \end{vmatrix}\]
When the curl equals zero, the field is said to be irrotational, meaning there is no curling or swirling motion in that area. In our problem case, since \( abla \times \mathbf{F} = \mathbf{0} \), it implies that the vector field does not cause any rotational movement, leading to the result that the circulation, or line integral around the loop, is zero.
Surface Integral
A surface integral extends the concept of line integrals to effects distributed over a surface in three-dimensional space. Surface integrals are crucial when dealing with fields distributed over surfaces, such as electromagnetic fields over a surface area, and are widely used in physics and engineering.

If \( \mathbf{F} \) represents a vector field, then the surface integral over a surface \( S \) is written as \( \iint_S \mathbf{F} \cdot d\mathbf{S} \). Here, \( d\mathbf{S} \) represents a small portion of the surface with a direction given by the normal vector to the surface.
Surface integrals are often used with Stokes' Theorem, which connects the surface integral of the curl of a vector field to the line integral around its boundary. This connection is particularly helpful in our exercise, allowing us to conclude that the circulation around the ellipse \( C \) is zero without directly computing the integrals. Stokes' Theorem effectively simplifies complex calculations into more manageable forms, demonstrating the beauty and utility of vector calculus.

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Most popular questions from this chapter

a. A torus of revolution (doughnut) is obtained by rotating a circle \(C\) in the \(x z\) -plane about the \(z\) -axis in space. (See the accompanying figure.) If \(C\) has radius \(r>0\) and center \((R, 0,0),\) show that a parametrization of the torus is $$\begin{aligned}\mathbf{r}(u, v)=&((R+r \cos u) \cos v) \mathbf{i} \\\&+((R+r \cos u) \sin v) \mathbf{j}+(r \sin u) \mathbf{k}\end{aligned}$$ where \(0 \leq u \leq 2 \pi\) and \(0 \leq v \leq 2 \pi\) are the angles in the figure.b. Show that the surface area of the torus is \(A=4 \pi^{2} R r\)

\(\mathbf{F}\) is the velocity field of a fluid flowing through a region in space. Find the flow along the given curve in the direction of increasing \(t.\) $$\begin{aligned} &\mathbf{F}=-4 x y \mathbf{i}+8 y \mathbf{j}+2 \mathbf{k}\\\ &\mathbf{r}(t)=t \mathbf{i}+t^{2} \mathbf{j}+\mathbf{k}, \quad 0 \leq t \leq 2 \end{aligned}$$

Suppose that \(f(t)\) is differentiable and positive for \(a \leq t \leq b .\) Let \(C\) be the path \(\mathbf{r}(t)=t \mathbf{i}+f(t) \mathbf{j}, a \leq t \leq b\) and \(\mathbf{F}=y \mathbf{i} .\) Is there any relation between the value of the work integral $$ \int_{C} \mathbf{F} \cdot d \mathbf{r} $$ and the area of the region bounded by the \(t\) -axis, the graph of \(f\) and the lines \(t=a\) and \(t=b ?\) Give reasons for your answer.

Use the surface integral in Stokes' Theorem to calculate the flux of the curl of the field \(\mathbf{F}\) across the surface \(S\) in the direction of the outward unit normal \(\mathbf{n}\).$$\begin{aligned} &\mathbf{F}=2 z \mathbf{i}+3 x \mathbf{j}+5 y \mathbf{k}\\\ &S: \quad \mathbf{r}(r, \theta)=(r \cos \theta) \mathbf{i}+(r \sin \theta) \mathbf{j}+\left(4-r^{2}\right) \mathbf{k}\\\ &0 \leq r \leq 2, \quad 0 \leq \theta \leq 2 \pi \end{aligned}$$

Use the surface integral in Stokes' Theorem to calculate the circulation of the field \(\mathbf{F}\) around the curve \(C\) in the indicated direction. \(\mathbf{F}=\left(y^{2}+z^{2}\right) \mathbf{i}+\left(x^{2}+y^{2}\right) \mathbf{j}+\left(x^{2}+y^{2}\right) \mathbf{k}.\) \(C:\) The square bounded by the lines \(x=\pm 1\) and \(y=\pm 1\) in the \(x y\) -plane, counterclockwise when viewed from above.

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