Chapter 16: Problem 3
Which fields are conservative, and which are not? $$\mathbf{F}=y \mathbf{i}+(x+z) \mathbf{j}-y \mathbf{k}$$
Short Answer
Expert verified
The field \( \mathbf{F} = y \mathbf{i} + (x+z) \mathbf{j} - y \mathbf{k} \) is not conservative.
Step by step solution
01
Understand Conservative Fields
A vector field \( \mathbf{F} \) is conservative if there exists a scalar potential function \( f \) such that \( \mathbf{F} = abla f \). This means the field is path independent and its curl is zero: \( abla \times \mathbf{F} = \mathbf{0} \).
02
Compute the Curl of \( \mathbf{F} \)
For \( \mathbf{F} = y \mathbf{i} + (x + z) \mathbf{j} - y \mathbf{k} \), the curl \( abla \times \mathbf{F} \) is determined using the determinant formula:\[abla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \ y & x+z & -y\end{vmatrix}\]Calculate the partial derivatives and evaluate the resulting determinant.
03
Evaluate the Determinant
Expand the determinant:\[(\frac{\partial (-y)}{\partial y} - \frac{\partial (x+z)}{\partial z})\mathbf{i} - (\frac{\partial (-y)}{\partial x} - \frac{\partial y}{\partial z})\mathbf{j} + (\frac{\partial (x+z)}{\partial x} - \frac{\partial y}{\partial y})\mathbf{k}\]Calculate each component: - \( i \): \( (0 - 1) = -1 \)- \( j \): \( (0 - 0) = 0 \)- \( k \): \( (1 - 1) = 0 \)Thus, \( abla \times \mathbf{F} = -\mathbf{i} \).
04
Determine if \( \mathbf{F} \) is Conservative
Since the curl \( abla \times \mathbf{F} = -\mathbf{i} eq \mathbf{0} \), the field \( \mathbf{F} \) is not conservative, as the requirement \( abla \times \mathbf{F} = \mathbf{0} \) is not satisfied.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Curl of a Vector Field
The curl of a vector field is an important concept in vector calculus. It measures the tendency of a field to rotate around a point. If you imagine a tiny paddle wheel placed in the field, the curl tells you how the wheel would spin.
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To find the curl of a vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \), we use the cross product of the del operator \( abla \) and \( \mathbf{F} \):\[ abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right)\mathbf{i} - \left( \frac{\partial R}{\partial x} - \frac{\partial P}{\partial z} \right)\mathbf{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right)\mathbf{k} \]
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To find the curl of a vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \), we use the cross product of the del operator \( abla \) and \( \mathbf{F} \):\[ abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right)\mathbf{i} - \left( \frac{\partial R}{\partial x} - \frac{\partial P}{\partial z} \right)\mathbf{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right)\mathbf{k} \]
- The components \( P, Q, R \) are the functions defining the field's direction along the \( x, y, z \) axes respectively.
- By computing these derivatives, you can find out whether a vector field has a rotational component.
Scalar Potential Function
In the context of vector fields, a scalar potential function represents the potential energy at any point in the field.
For a vector field to be conservative, this function must exist.
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The scalar potential function \( f \) is such that the vector field \( \mathbf{F} \) equals the gradient of \( f \):\[ \mathbf{F} = abla f \]
For a vector field to be conservative, this function must exist.
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The scalar potential function \( f \) is such that the vector field \( \mathbf{F} \) equals the gradient of \( f \):\[ \mathbf{F} = abla f \]
- If \( \mathbf{F} \) is conservative, it can be expressed as the derivative of some scalar field \( f \).
- This means that \( \mathbf{F} \) will be path-independent, leading to the same outcome regardless of the path taken.
Path Independence
Path independence is a property of conservative vector fields. It means that the integral of a vector field along a path depends only on the starting and ending points, not on the path itself.
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In a conservative field:
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In a conservative field:
- The line integral \( \int_C \mathbf{F} \cdot d\mathbf{r} \) is the same for any path \( C \) between two points.
- This is equivalent to saying that the integral over any closed path is zero, like walking a loop and returning to the start.
- Path independence simplifies calculating work done by or against forces in such fields since only endpoints matter.
Determinant Formula in Vector Calculus
The determinant formula plays a key role in vector calculus. It helps calculate the curl of a vector field using determinants, which are mathematical structures that simplify complex calculations.
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To use the determinant formula for the curl:\[ abla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \ P & Q & R \end{vmatrix} \]
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To use the determinant formula for the curl:\[ abla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \ P & Q & R \end{vmatrix} \]
- First, write the components of the vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \) in the last row.
- The middle row consists of the partial derivative operators \( \frac{\partial}{\partial x}, \frac{\partial}{\partial y}, \frac{\partial}{\partial z} \).
- Compute the determinant to find the curl, essentially finding how parts of the field vary.