Chapter 14: Problem 69
Gives a function \(f(x, y)\) and a positive number \(\epsilon\) In each exercise, show that there exists a \(\delta > 0\) such that for all \((x, y)\) $$ \sqrt{x^{2}+y^{2}} < \delta \Rightarrow|f(x, y)-f(0,0)| < \epsilon $$ $$f(x, y)=x^{2}+y^{2}, \quad \epsilon=0.01$$
Short Answer
Expert verified
Choose \(\delta = 0.1\); it ensures the desired result.
Step by step solution
01
Understand the Problem
We need to prove that given \( f(x, y) = x^2 + y^2 \), there exists a \( \delta > 0 \) such that if \( \sqrt{x^2 + y^2} < \delta \), then \( |f(x, y) - f(0,0)| < \epsilon \) with \( \epsilon = 0.01 \). At \( (0,0) \), \( f(0,0) = 0 \). So, we want \( |x^2 + y^2 - 0| < 0.01 \).
02
Set Up the Inequality
We have \( |f(x, y) - f(0,0)| = |x^2 + y^2| < 0.01 \). This becomes \( x^2 + y^2 < 0.01 \). We need to relate this inequality with \( \sqrt{x^2 + y^2} < \delta \).
03
Connect with \( \sqrt{x^2 + y^2} < \delta \)
Since \( x^2 + y^2 < 0.01 \), we can rewrite it as \( \sqrt{x^2 + y^2} < \sqrt{0.01} \). Simplifying \( \sqrt{0.01} \) gives \( 0.1 \). Thus, if \( \sqrt{x^2 + y^2} < 0.1 \), then we know \( |x^2 + y^2| < 0.01 \).
04
Choose \( \delta \)
From the previous step, \( \sqrt{x^2 + y^2} < \delta \) implies \( x^2 + y^2 < \delta^2 \). We choose \( \delta = 0.1 \) so that \( \sqrt{x^2 + y^2} < 0.1 \) implies \( x^2 + y^2 < 0.01 \).
05
Conclusion
Therefore, we have shown that choosing \( \delta = 0.1 \) satisfies the condition \( \sqrt{x^2 + y^2} < \delta \Rightarrow |f(x, y) - f(0,0)| < \epsilon \) where \( \epsilon = 0.01 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Limits in Functions
Limits are a fundamental concept in calculus. They allow us to evaluate the behavior of functions as inputs approach a certain value. In this exercise, we use the epsilon-delta definition of a limit. This is essentially a challenge-response relationship. Given a tiny number (epsilon, \(\epsilon\)), we must find a tiny neighborhood (delta, \(\delta\)). For each point in this neighborhood, the change in function value remains smaller than \(\epsilon\). This concept helps us understand how a function asymptotically approaches a specific value.
In this specific problem, we examine the function \(f(x, y) = x^2 + y^2\) as it approaches the point \((0,0)\). By using the epsilon-delta definition, we confirm that the function value gets closer to zero without ever actually being zero — this is the heart of the limit process.
In this specific problem, we examine the function \(f(x, y) = x^2 + y^2\) as it approaches the point \((0,0)\). By using the epsilon-delta definition, we confirm that the function value gets closer to zero without ever actually being zero — this is the heart of the limit process.
- The variable \(\epsilon\) represents how close we want the function’s value to be to its limit.
- The variable \(\delta\) tells us how close the input must be to the point of interest.
Exploring Multivariable Calculus
Multivariable calculus extends the concepts of single-variable calculus into multiple dimensions. Instead of dealing with a function of just one variable, such as \(y = x^2\), we now work with functions like \(f(x, y) = x^2 + y^2\), where there are two or more inputs.
In such cases, we look at how these variables interact and influence the outcome of a function. This form of calculus is vital for modeling real-world phenomena, where variables rarely act in isolation. Engineers and scientists use these principles regularly.
In such cases, we look at how these variables interact and influence the outcome of a function. This form of calculus is vital for modeling real-world phenomena, where variables rarely act in isolation. Engineers and scientists use these principles regularly.
- We assess how a multi-variable function behaves when both variables change simultaneously.
- This exercise examines the combined effect of both \(x\) and \(y\) approaching zero.
Ensuring Continuity in Functions
Continuity is a critical feature of functions that ensures smoothness, stability, and predictability. In mathematical terms, a function is continuous at a point if small changes in inputs produce small changes in outputs. In terms of limits, if \( \lim_{(x, y) \to (a, b)} f(x, y) = f(a, b) \), then \(f\) is continuous at that point.
This exercise examines the continuity of \(f(x, y) = x^2 + y^2\) at the origin \((0,0)\). By using the epsilon-delta definition, we can confirm that this function is continuous.
This exercise examines the continuity of \(f(x, y) = x^2 + y^2\) at the origin \((0,0)\). By using the epsilon-delta definition, we can confirm that this function is continuous.
- The continuity means for any small \(\epsilon\), there exists a delta such that any input change under \(\delta\) results in a negligible function change smaller than \(\epsilon\).
- For the function \(f(x,y)\), this holds true because as \(x\) and \(y\) approach 0, the output \(x^2 + y^2\) also approaches 0.