/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Use a CAS to perform the followi... [FREE SOLUTION] | 91Ó°ÊÓ

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Use a CAS to perform the following steps implementing the method of Lagrange multipliers for finding constrained extrema: a. Form the function \(h=f-\lambda_{1} g_{1}-\lambda_{2} g_{2},\) where \(f\) is the function to optimize subject to the constraints \(g_{1}=0\) and \(g_{2}=0.\) b. Determine all the first partial derivatives of \(h\), including the partials with respect to \(\lambda_{1}\) and \(\lambda_{2},\) and set them equal to 0 . c. Solve the system of equations found in part (b) for all the unknowns, including \(\lambda_{1}\) and \(\lambda_{2}\). d. Evaluate \(f\) at each of the solution points found in part (c) and select the extreme value subject to the constraints asked for in the exercise. Minimize \(f(x, y, z)=x y+y z\) subject to the constraints \(x^{2}+y^{2}-\) \(2=0\) and \(x^{2}+z^{2}-2=0.\)

Short Answer

Expert verified
The minimum value of \( f(x, y, z) \) given the constraints is \( 2\sqrt{2} \).

Step by step solution

01

Form the Function h

We begin by writing the function for Lagrange multipliers, which is given by \( h(x, y, z, \lambda_1, \lambda_2) = f(x, y, z) - \lambda_1 g_1(x, y, z) - \lambda_2 g_2(x, y, z) \). Here, \( f(x, y, z) = xy + yz \), \( g_1(x, y, z) = x^2 + y^2 - 2 \), and \( g_2(x, y, z) = x^2 + z^2 - 2 \). Thus we have: \[ h(x, y, z, \lambda_1, \lambda_2) = xy + yz - \lambda_1(x^2 + y^2 - 2) - \lambda_2(x^2 + z^2 - 2). \]
02

Calculate First Partial Derivatives

Find the first partial derivatives of \( h \) with respect to \( x, y, z, \lambda_1, \) and \( \lambda_2. \) Set these derivatives equal to zero:- \( \frac{\partial h}{\partial x} = y - 2\lambda_1 x - 2\lambda_2 x = 0 \)- \( \frac{\partial h}{\partial y} = x + z - 2\lambda_1 y = 0 \)- \( \frac{\partial h}{\partial z} = y - 2\lambda_2 z = 0 \)- \( \frac{\partial h}{\partial \lambda_1} = -(x^2 + y^2 - 2) = 0 \)- \( \frac{\partial h}{\partial \lambda_2} = -(x^2 + z^2 - 2) = 0 \).
03

Solve the System of Equations

The equations are:1. \( y = 2\lambda_1 x + 2\lambda_2 x \)2. \( x + z = 2\lambda_1 y \)3. \( y = 2\lambda_2 z \)4. \( x^2 + y^2 = 2 \)5. \( x^2 + z^2 = 2 \).Solve for \( x, y, z, \lambda_1, \lambda_2. \) After solving, we find the solutions to be- \( (x, y, z) = (1, \sqrt{2}, 1) \) with \( \lambda_1 = \frac{1}{\sqrt{2}}, \lambda_2 = \frac{1}{\sqrt{2}} \) and- \( (x, y, z) = (-1, -\sqrt{2}, -1) \) with \( \lambda_1 = -\frac{1}{\sqrt{2}}, \lambda_2 = -\frac{1}{\sqrt{2}} \).
04

Evaluate f at Solution Points

Evaluate \( f(x, y, z) = xy + yz \) at the found solutions:- For \((x, y, z) = (1, \sqrt{2}, 1), f(1, \sqrt{2}, 1) = 1\cdot\sqrt{2} + \sqrt{2}\cdot 1 = 2\sqrt{2}. \)- For \((x, y, z) = (-1, -\sqrt{2}, -1), f(-1, -\sqrt{2}, -1) = -1\cdot(-\sqrt{2}) + (-\sqrt{2})\cdot (-1) = 2\sqrt{2}. \)Both points give the same value of \( f \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constrained Optimization
Constrained optimization is a mathematical method used to find the maximum or minimum of a function within specific boundaries or constraints. Imagine you want to maximize or minimize a quantity, but with some conditions in place. For example, you might want to minimize cost while ensuring production constraints are met.

In the context of the exercise, the function to be minimized is \( f(x, y, z) = xy + yz \). The constraints are given by the equations \( x^2 + y^2 - 2 = 0 \) and \( x^2 + z^2 - 2 = 0 \). These constraints restrict the available solutions to a specific region in space. We use Lagrange multipliers, \( \lambda_1 \) and \( \lambda_2 \), which help incorporate these constraints into the optimization problem, transforming it into a system where all conditions work at once. To find the solution, we set up a new function \( h \) that combines the function to be optimized with the constraints, allowing us to find the constrained extremum.
Partial Derivatives
Partial derivatives are a fundamental tool in calculus used to analyze functions of several variables. They measure how the function changes as one of the variables is changed, keeping the other variables constant.

In the exercise, we calculate the partial derivatives of the function \( h(x, y, z, \lambda_1, \lambda_2) \), which include \( \frac{\partial h}{\partial x}, \frac{\partial h}{\partial y}, \frac{\partial h}{\partial z}, \frac{\partial h}{\partial \lambda_1}, \) and \( \frac{\partial h}{\partial \lambda_2} \). Setting these derivatives equal to zero leads to a system of equations. This step is crucial because it's at the heart of finding points that satisfy both the function and the constraints. By setting these derivatives to zero, we are searching for points where the functions stop changing—indicative of maximum or minimum values.
Systems of Equations
A system of equations consists of multiple equations that must be solved simultaneously. These systems arise naturally when working with Lagrange multipliers in constrained optimization.

In the solution, after setting the partial derivatives to zero, we end up with a set of equations such as:
  • \( y = 2\lambda_1 x + 2\lambda_2 x \)
  • \( x + z = 2\lambda_1 y \)
  • \( y = 2\lambda_2 z \)
  • \( x^2 + y^2 = 2 \)
  • \( x^2 + z^2 = 2 \)
To find the solution, we solve this system for all unknowns: \( x, y, z, \lambda_1, \lambda_2 \). The solution provides the critical points that satisfy the constraints. In mathematical analysis, systems of equations allow us to understand how multiple conditions interact and influence possible solutions.
Mathematical Analysis
Mathematical analysis involves examining and interpreting mathematical concepts and their interrelations, often to unravel complex problems. It allows us to delve deep into functions, their extremes, and the constraints binding them.

In this exercise, mathematical analysis leads us through evaluating a function at critical points to verify and extract meaningful insights. After solving the system of equations, two solutions were found: \((1, \sqrt{2}, 1)\) and \((-1, -\sqrt{2}, -1)\). Evaluating the function \( f(x, y, z) = xy + yz \) at these points yielded the same minimum value \( 2\sqrt{2} \).

This analysis step involves both computational parts, solving systems and calculating derivatives, and interpretative parts, understanding what these solutions imply. It's a perfect example of how mathematical analysis turns abstract equations into understandable, practical decisions.

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Most popular questions from this chapter

An important partial differential equation that describes the distribution of heat in a region at time \(t\) can be represented by the one-dimensional heat equation $$\frac{\partial f}{\partial t}=\frac{\partial^{2} f}{\partial x^{2}}$$ Show that \(u(x, t)=\sin (\alpha x) \cdot e^{-\beta t}\) satisfies the heat equation for constants \(\alpha\) and \(\beta .\) What is the relationship between \(\alpha\) and \(\beta\) for this function to be a solution?

(A) find the function's domain, (b) find the function's range, (c) describe the function's level curves, (d) find the boundary of the function's domain, (e) determine if the domain is an open region, a closed region, or neither, and (f) decide if the domain is bounded or unbounded. $$f(x, y)=\ln \left(9-x^{2}-y^{2}\right)$$

To find the extreme values of a function \(f(x, y)\) on a curve \(x=x(t), y=y(t),\) we treat \(f\) as a function of the single variable \(t\) and use the Chain Rule to find where \(d f / d t\) is zero. As in any other single-variable case, the extreme values of \(f\) are then found among the values at the a. critical points (points where \(d f / d t\) is zero or fails to exist), and b. endpoints of the parameter domain. Find the absolute maximum and minimum values of the following functions on the given curves. Functions: a. \(f(x, y)=2 x+3 y\) b. \(g(x, y)=x y\) c. \(h(x, y)=x^{2}+3 y^{2}\) Curves: i) The semiellipse \(\left(x^{2} / 9\right)+\left(y^{2} / 4\right)=1, \quad y \geq 0\) ii) The quarter ellipse \(\left(x^{2} / 9\right)+\left(y^{2} / 4\right)=1, \quad x \geq 0, \quad y \geq 0\) Use the parametric equations \(x=3 \cos t, y=2 \sin t\).

Find the limits. $$\lim _{(x, y) \rightarrow\left(1 / 27, \pi^{3}\right)} \cos \sqrt[3]{x y}$$

You will explore functions to identify their local extrema. Use a CAS to perform the following steps: a. Plot the function over the given rectangle. b. Plot some level curves in the rectangle. c. Calculate the function's first partial derivatives and use the CAS equation solver to find the critical points. How do the critical points relate to the level curves plotted in part (b)? Which critical points, if any, appear to give a saddle point? Give reasons for your answer. d. Calculate the function's second partial derivatives and find the discriminant \(f_{x x} f_{y y}-f_{x y}^{2}\). e. Using the max-min tests, classify the critical points found in part (c). Are your findings consistent with your discussion in part (c)? $$\begin{aligned} &f(x, y)=x^{4}+y^{2}-8 x^{2}-6 y+16, \quad-3 \leq x \leq 3,\\\ &-6 \leq y \leq 6 \end{aligned}$$

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