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Show that the limits do not exist. $$\lim _{(x, y) \rightarrow(1,1)} \frac{x y^{2}-1}{y-1}$$

Short Answer

Expert verified
The limit does not exist as it yields different results for different paths.

Step by step solution

01

Understand the Limit and Identify Indeterminacy

We are asked to find if the limit \( \lim_{(x, y) \rightarrow (1, 1)} \frac{x y^{2} - 1}{y - 1} \) exists. First, substitute \((x, y) = (1, 1)\) in the expression: \( \frac{1 \cdot 1^2 - 1}{1 - 1} \). This gives \( \frac{0}{0} \), indicating an indeterminate form.
02

Test Different Paths

To determine if a limit exists, test paths leading to \((1, 1)\). If different paths yield different results, the limit doesn't exist. Start with the path \(y = x\):Substitute \(y = x\):\[ \frac{x (x^2) - 1}{x - 1} = \frac{x^3 - 1}{x - 1} \].
03

Simplify the Expression for y = x

Factor the expression \( x^3 - 1 \) as \((x - 1)(x^2 + x + 1)\).Thus, \[ \frac{(x - 1)(x^2 + x + 1)}{x - 1} = x^2 + x + 1 \] when \( x eq 1 \). As \( x \rightarrow 1 \), this expression approaches \(3\).
04

Test Another Path

Now, test the path \(y = x^2\):Substitute \(y = x^2\):\[ \frac{x(x^2)^2 - 1}{x^2 - 1} = \frac{x^5 - 1}{x^2 - 1} \].
05

Simplify the Expression for y = x^2

Factor \(x^5 - 1\) as \((x - 1)(x^4 + x^3 + x^2 + x + 1)\).Thus, \[ \frac{(x - 1)(x^4 + x^3 + x^2 + x + 1)}{x^2 - 1} \] factors further to \((x - 1)(x + 1)\).This reduces to \(x^4 + x^3 + x^2 + x + 1\). As \(x \rightarrow 1\), it approaches \(5\).
06

Conclude Based on Path Differences

As the expression approaches \(3\) using the path \(y = x\) and \(5\) using \(y = x^2\), different limits for different paths imply that the limit:\[ \lim_{(x, y) \rightarrow (1, 1)} \frac{x y^{2} - 1}{y - 1} \] does not exist.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indeterminate Forms
When evaluating a limit, one might encounter expressions like \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \). These are known as indeterminate forms. Such forms are a signal that the traditional methods of plugging the points directly into the function won't give a definitive answer.
They demand further analysis to uncover the behavior of the function as it approaches a particular point. Indeterminate forms arise when both the numerator and the denominator approach zero (or infinity simultaneously).
In our exercise, substituting \((x, y) = (1, 1)\) into \( \frac{x y^{2} - 1}{y - 1} \) results in \( \frac{0}{0} \), which is indeterminate. This necessitates alternative approaches, such as path testing or algebraic manipulation, to find any potential limits.
Indeterminate forms are pivotal in calculus because they hint at complex behavior. Solving such problems often involves creative techniques to simplify or reframe the expression. This might include factoring, using L'Hôpital's rule for derivatives, or substituting alternative variable paths.
Path Testing in Multivariable Calculus
Path testing is the technique used to evaluate limits in multivariable calculus when a direct approach leads to an indeterminate form.
The idea is to approach the limit point, in this case, \((1,1)\), along different paths to see if they yield the same limit value. Different outcomes along different paths indicate that the general limit does not exist. For example, in our exercise, we tested the paths \(y = x\) and \(y = x^2\). These are two of the countless paths we could choose to approach \((1,1)\).
With \(y = x\), the limit approaches 3. With \(y = x^2\), it approaches 5. Since the results depend on the path, the overall limit \( \lim_{(x, y) \rightarrow (1, 1)} \frac{x y^{2} - 1}{y - 1} \) does not exist. Path testing is crucial due to multivariable functions' complexity. It highlights the function's potential dependency on the path of approach rather than simply the proximity to a point.
When limits are path-independent, they exist; when they vary across paths, they expose the function's nuanced behavior.
Limits in Multivariable Functions
Limits in multivariable functions extend the single-variable concept of a limit. In essence, a limit exists at a point if, regardless of the direction from which it's approached, we end up with the same value.
However, evaluating limits in multivariable calculus can be more challenging due to the infinite number of paths that can be taken toward a limit point. This scenario requires testing multiple paths, as a consistent limit across various paths generally indicates the existence of a limit. Understanding limits in multivariable functions helps predict behavior near specific points. For example, engineers use them to analyze stress concentration at a point or scientists to model thermal properties near a material's boundary.
In multivariable situations, continuity also becomes crucial, as a lack of a limit suggests a discontinuity or a "break" in the function at that point. For the problem given, as shown through path testing, and due to differing limit values from different paths, no singular limit exists as \((x, y)\) approaches \((1, 1)\).
This highlights the importance of testing paths and verifying results through multiple approaches to ensure a precise understanding of the function's behavior. Overall, limits in multivariable functions demand careful consideration of various approaches and thorough analysis to deduce meaningful conclusions.

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