/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 Display the values of the functi... [FREE SOLUTION] | 91Ó°ÊÓ

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Display the values of the functions in two ways: (a) by sketching the surface \(z=f(x, y)\) and (b) by drawing an assortment of level curves in the function's domain. Label each level curve with its function value. $$f(x, y)=x^{2}+y^{2}$$

Short Answer

Expert verified
Sketch a paraboloid for the surface and circles centered at the origin as level curves.

Step by step solution

01

Understand the function

The given function is \( f(x, y) = x^2 + y^2 \). This is a basic quadratic function in two variables that represents a paraboloid. The function is symmetric about the origin and the level curves will be circles centered at the origin.
02

Sketch the surface

Sketch the 3D surface of the function \( z = x^2 + y^2 \). This involves plotting the paraboloid, where for each pair \((x, y)\), the height or \(z\)-value is \(x^2 + y^2\). The shape will be a symmetric bowl going upwards from the origin. At the origin, \(z = 0\), and as \((x, y)\) moves away from the origin in any direction, \(z\) increases quadratically.
03

Determine level curves

Level curves are the intersections of the surface with planes \(z = c\), for constant values \(c\). For \(f(x, y) = x^2 + y^2 = c\), the curves are circles: \(x^2 + y^2 = c\) with radius \(\sqrt{c}\), centered at the origin.
04

Draw and label level curves

Plot circles in the xy-plane for various values of \(c\). For example, for \(c = 1, 4, 9\), draw circles with radii \(1, 2, 3\), respectively. Each circle should be labeled with its corresponding \(c\)-value: \(x^2 + y^2 = 1\), \(x^2 + y^2 = 4\), and \(x^2 + y^2 = 9\). This visualizes how the function values change in the domain of \(x\) and \(y\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Paraboloid
A paraboloid is a three-dimensional surface that is often described as a bowl-shaped figure. In mathematics, this surface is formed by revolving a parabola around its axis of symmetry. The given function, \( f(x, y) = x^2 + y^2 \), defines a paraboloid in the Cartesian coordinate system. This particular type of paraboloid is known as a circular paraboloid because its cross-sections parallel to the base plane form circles. In this setup, the variable \( z \) represents the height of the surface at any point \( (x, y) \). When you visualize this function in a 3D space, you can imagine a smooth bowl where the edges rise steadily as you move away from the center, which is located at the origin \((0,0)\). This symmetry is a notable feature of the paraboloid, making it an interesting subject for studying functions in three dimensions.
3D Surface Sketch
Creating a 3D surface sketch of the function \( z = x^2 + y^2 \) requires imagining how this paraboloid appears in space. ### Steps to Sketch a 3D Surface- Begin by finding the base plane, which is the \( xy \)-plane.- For any point \( (x, y) \), compute the height \( z = x^2 + y^2 \).- Plot points by choosing various \( (x, y) \) pairs, calculating \( z \) for each, and marking the position in space.The sketch reveals a symmetric shape that rises upwards from the origin, forming a bowl-like structure. The bowl becomes steeper further from the origin, reflecting the quadratic increase in \( z \) as \( x \) and \( y \) grow larger. These features make it evident that the nature of this surface fits the form of a classic upward-opening paraboloid.
Quadratic Function
The function \( f(x, y) = x^2 + y^2 \) is classified as a quadratic function due to its characteristic square terms in both \( x \) and \( y \). Quadratic functions are a fundamental type of polynomial whose graph typically forms a parabola in two dimensions.### Understanding Quadratic Functions- Coefficients: In its general form \( ax^2 + by^2 \), both coefficients are 1 for this exercise, indicating balanced contributions from \( x \) and \( y \).- Symmetry: Due to equal coefficients, the surface is rotationally symmetric around the \( z \)-axis.- Domain: This function is defined over all real numbers \( (x, y) \), leading to an infinite set of possible inputs.In this 3D context, the quadratic function describes the elevation \( z \) at different points. The level curves, circles plotted in the \( xy \)-plane, provide another perspective on how the function behaves and influences the shape of the surface. These concepts are central in analyzing functions that describe natural and engineered systems.

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Most popular questions from this chapter

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You will explore functions to identify their local extrema. Use a CAS to perform the following steps: a. Plot the function over the given rectangle. b. Plot some level curves in the rectangle. c. Calculate the function's first partial derivatives and use the CAS equation solver to find the critical points. How do the critical points relate to the level curves plotted in part (b)? Which critical points, if any, appear to give a saddle point? Give reasons for your answer. d. Calculate the function's second partial derivatives and find the discriminant \(f_{x x} f_{y y}-f_{x y}^{2}\). e. Using the max-min tests, classify the critical points found in part (c). Are your findings consistent with your discussion in part (c)? $$f(x, y)=x^{2}+y^{3}-3 x y, \quad-5 \leq x \leq 5, \quad-5 \leq y \leq 5$$

By considering different paths of approach, show that the functions have no limit as \((x, y) \rightarrow(0,0)\). $$h(x, y)=\frac{x^{2}+y}{y}$$

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