Chapter 14: Problem 20
(A) find the function's domain, (b) find the function's range, (c) describe the function's level curves, (d) find the boundary of the function's domain, (e) determine if the domain is an open region, a closed region, or neither, and (f) decide if the domain is bounded or unbounded. $$f(x, y)=x^{2}-y^{2}$$
Short Answer
Step by step solution
Finding the Function's Domain
Finding the Function's Range
Describing the Function's Level Curves
Finding the Boundary of the Function's Domain
Determining if the Domain is Open, Closed, or Neither
Determining if the Domain is Bounded or Unbounded
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of a Function
It's important to understand that if a function has any mathematical expressions such as square roots, logarithms, or fractions, their domains could have restrictions—but here, we freely use all of \( \mathbb{R}^2 \).
Range of a Function
To see how the range could be all of \( \mathbb{R} \), consider:
- When \( x^2 > y^2 \), the result is positive.
- When \( x^2 < y^2 \), the result is negative.
- When \( x^2 = y^2 \), the result is zero.
Level Curves
Depending on the constant \( c \):
- If \( c > 0 \), the hyperbola opens along the \( x \)-axis.
- If \( c < 0 \), it opens along the \( y \)-axis.
- If \( c = 0 \), it forms the degenerate case where the level curve represents the lines \( x = y \) and \( x = -y \).
Open and Closed Sets
A set is termed **open** if it does not include its boundary, and it's **closed** if it includes its boundary. In \( \mathbb{R}^2 \), which is essentially the entire plane, there is no real boundary, making it conventionally both open and closed. Because it extends infinitely without a defined "edge," there are no exterior points to consider.
- This unique property of being both open and closed is known as being "clopen."
- Often considered open since there isn’t a boundary to include or exclude."