/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Match the equation with the surf... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Match the equation with the surface it defines. Also, identify each surface by type (paraboloid, ellipsoid, etc.). The surfaces are labeled (a)-(1). $$x=z^{2}-y^{2}$$

Short Answer

Expert verified
The equation defines a hyperbolic paraboloid.

Step by step solution

01

Recognize the Equation Type

The equation given is \( x = z^2 - y^2 \). This fits the form of a hyperbolic paraboloid, which is an equation of the type \( z = x^2/a^2 - y^2/b^2 \) but revolved so that \( x \), \( y \), \( z \) are permutable.
02

Understand the Standard Form

The standard form for a hyperbolic paraboloid involves one squared variable added and one squared variable subtracted, as in the equation \( z = x^2/a^2 - y^2/b^2 \). The equation \( x = z^2 - y^2 \) maintains this characteristic structure of having one square positive and one square negative.
03

Identify the Surface

By analogy to the standard form, the equation \( x = z^2 - y^2 \) describes a hyperbolic paraboloid. It can typically be visualized as a saddle surface or a Pringles chip, having contours that open in opposite directions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hyperbolic Paraboloid
A hyperbolic paraboloid is a fascinating type of surface that is often compared to familiar shapes like a saddle or a Pringles chip. This surface is known for its distinctive features, including curves that open in two opposite directions.

Mathematically, a hyperbolic paraboloid can be expressed with equations of the form:
  • \( z = x^2/a^2 - y^2/b^2 \)
  • \( x = z^2/c^2 - y^2/d^2 \)
These forms indicate that one of the variables is squared and added, while another squared variable is subtracted. This combination results in the saddle-like shape.

What's intriguing about the hyperbolic paraboloid is how it represents a simple yet visually complex structure that can be rotated into different orientations, still maintaining its essential properties. This flexibility in representation often makes surface identification an engaging task for students.
Equation Recognition
Recognizing the type of surface defined by an equation is crucial in calculus and geometry. When presented with an equation like \( x = z^2 - y^2 \), the goal is to identify its structural form.

The first step is to see if the equation contains squared terms, as these hints at paraboloids. Here, one positive squared term \( z^2 \) and one negative squared term \( y^2 \) imply a surface that bends in opposite directions. This is characteristic of a hyperbolic paraboloid.

Understanding the signs and arrangement of terms within an equation helps determine the surface type efficiently. For instance, whenever there are
  • squared terms
  • opposite signs
in a rearranged equation from the standard form, it signals a hyperbolic paraboloid. Being attentive to these details empowers students with the skills to decode complex surface equations.
Surface Identification
Identifying surfaces based on equations requires a blend of visualization and analytical skills. For equation \( x = z^2 - y^2 \), recognizing it as a hyperbolic paraboloid involves associating the mathematical structure with real-world shapes, such as a saddle.

Key identifiers for surfaces like hyperbolic paraboloids include:
  • The presence of squared terms with opposite signs indicating curves in different directions
  • A focus on cycles or rotations that don't alter the surface's nature
Understanding these properties aids in the visualization of the surface in three-dimensional space.

Practicing surface identification by aligning equations with visual models enriches comprehension and boosts confidence in tackling calculus problems. These skills are essential for students to conceptualize more complex geometric interpretations in advanced mathematics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the distance between points \(P_{1}\) and \(P_{2}\). $$P_{1}(3,4,5), \quad P_{2}(2,3,4)$$

a. Express the area \(A\) of the cross-section cut from the ellipsoid $$x^{2}+\frac{y^{2}}{4}+\frac{z^{2}}{9}=1$$ by the plane \(z=c\) as a function of \(c .\) (The area of an ellipse with semiaxes \(a\) and \(b\) is \(\pi a b\).) b. Use slices perpendicular to the \(z\) -axis to find the volume of the ellipsoid in part (a). c. Now find the volume of the ellipsoid $$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}+\frac{z^{2}}{c^{2}}=1.$$ Does your formula give the volume of a sphere of radius \(a\) if \(a=b=c ?\)

Suppose that \(A, B,\) and \(C\) are vertices of a triangle and that \(a, b\) and \(c\) are, respectively, the midpoints of the opposite sides. Show that \(\overrightarrow{A a}+\overrightarrow{B b}+\overrightarrow{C c}=0\).

Location A bird flies from its nest \(5 \mathrm{km}\) in the direction \(60^{\circ}\) north of east, where it stops to rest on a tree. It then flies \(10 \mathrm{km}\) in the direction due southeast and lands atop a telephone pole. Place an \(x y\) -coordinate system so that the origin is the bird's nest, the \(x\) -axis points east, and the \(y\) -axis points north. a. At what point is the tree located? b. At what point is the telephone pole?

In computer graphics and perspective drawing, we need to represent objects seen by the eye in space as images on a two-dimensional plane. Suppose that the eye is at \(E\left(x_{0}, 0,0\right)\) as shown here and that we want to represent a point \(P_{1}\left(x_{1}, y_{1}, z_{1}\right)\) as a point on the \(y z\) -plane. We do this by projecting \(P_{1}\) onto the plane with a ray from \(E .\) The point \(P_{1}\) will be portrayed as the point \(P(0, y, z) .\) The problem for us as graphics designers is to find \(y\) and \(z\) given \(E\) and \(P_{1}\). a. Write a vector equation that holds between \(\overrightarrow{E P}\) and \(\overrightarrow{E P}_{1} .\) Use the equation to express \(y\) and \(z\) in terms of \(x_{0}, x_{1}, y_{1},\) and \(z_{1}\) b. Test the formulas obtained for \(y\) and \(z\) in part (a) by investigating their behavior at \(x_{1}=0\) and \(x_{1}=x_{0}\) and by seeing what happens as \(x_{0} \rightarrow \infty\). What do you find?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.