Chapter 12: Problem 25
Express each vector as a product of its length and direction. $$2 \mathbf{i}+\mathbf{j}-2 \mathbf{k}$$
Short Answer
Expert verified
The vector is 3 times the direction vector \( \frac{2}{3}\mathbf{i} + \frac{1}{3}\mathbf{j} - \frac{2}{3}\mathbf{k} \).
Step by step solution
01
Identify the vector components
The given vector is \( \mathbf{v} = 2\mathbf{i} + \mathbf{j} - 2\mathbf{k} \). It has the components: \( a = 2 \), \( b = 1 \), and \( c = -2 \).
02
Calculate the length of the vector
The length (magnitude) of a vector \( \mathbf{v} = a\mathbf{i} + b\mathbf{j} + c\mathbf{k} \) is given by \( \|\mathbf{v}\| = \sqrt{a^2 + b^2 + c^2} \). Substituting the components: \( \|\mathbf{v}\| = \sqrt{2^2 + 1^2 + (-2)^2} = \sqrt{4 + 1 + 4} = \sqrt{9} = 3 \).
03
Find the direction vector
The direction of the vector is given by dividing each component of the vector by its length. Compute the direction vector \( \mathbf{u} = \frac{1}{\|\mathbf{v}\|}(a\mathbf{i} + b\mathbf{j} + c\mathbf{k}) \). For the given vector, \( \mathbf{u} = \frac{1}{3}(2\mathbf{i} + \mathbf{j} - 2\mathbf{k}) \) gives \( \mathbf{u} = \frac{2}{3}\mathbf{i} + \frac{1}{3}\mathbf{j} - \frac{2}{3}\mathbf{k} \).
04
Express the vector as the product of its length and direction
The vector \( \mathbf{v} \) can be expressed as \( \mathbf{v} = \|\mathbf{v}\| \cdot \mathbf{u} \). Substitute the length and direction: \( \mathbf{v} = 3 \cdot \left( \frac{2}{3}\mathbf{i} + \frac{1}{3}\mathbf{j} - \frac{2}{3}\mathbf{k} \right) \). Simplifying gives the original vector: \( \mathbf{v} = 2 \mathbf{i} + \mathbf{j} - 2 \mathbf{k} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
vector magnitude
The magnitude of a vector, often referred to as its length, measures the size or extent of the vector. For a vector in three-dimensional space, given as \( \mathbf{v} = a\mathbf{i} + b\mathbf{j} + c\mathbf{k} \), the magnitude is calculated using the formula \( \|\mathbf{v}\| = \sqrt{a^2 + b^2 + c^2} \). This formula helps us understand the total "distance" or "length" the vector covers in space, regardless of its direction.
In our example with the vector \( 2\mathbf{i} + \mathbf{j} - 2\mathbf{k} \):
In our example with the vector \( 2\mathbf{i} + \mathbf{j} - 2\mathbf{k} \):
- \( a = 2 \), \( b = 1 \), \( c = -2 \)
- Substitute these values into the formula: \( \|\mathbf{v}\| = \sqrt{2^2 + 1^2 + (-2)^2} = \sqrt{9} = 3 \)
unit vector
A unit vector defines the direction of a vector without indicating its magnitude. It is essentially a vector with a magnitude of exactly 1. To find a unit vector in the direction of a vector \( \mathbf{v} \), you need to divide each component of \( \mathbf{v} \) by its magnitude. This process normalizes the vector.
Let's calculate the unit vector for our example:
Let's calculate the unit vector for our example:
- Given the vector \( \mathbf{v} = 2\mathbf{i} + \mathbf{j} - 2\mathbf{k} \), with a magnitude of 3
- The unit vector \( \mathbf{u} = \frac{1}{3}(2\mathbf{i} + \mathbf{j} - 2\mathbf{k}) = \frac{2}{3}\mathbf{i} + \frac{1}{3}\mathbf{j} - \frac{2}{3}\mathbf{k} \)
vector components
Vector components break a vector down into its individual parts along the axes of a coordinate system, generally represented by \( \mathbf{i}, \mathbf{j}, \) and \( \mathbf{k} \) for the x-axis, y-axis, and z-axis respectively. Each component describes how far the vector extends along its respective axis.
For the vector in our exercise, \( \mathbf{v} = 2\mathbf{i} + \mathbf{j} - 2\mathbf{k} \):
For the vector in our exercise, \( \mathbf{v} = 2\mathbf{i} + \mathbf{j} - 2\mathbf{k} \):
- The x-component is 2
- The y-component is 1
- The z-component is -2