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Let \(\mathbf{u}=\langle 3,-2\rangle\) and \(\mathbf{v}=\langle-2,5\rangle .\) Find the \((\mathbf{a})\) component form and (b) magnitude (length) of the vector. $$3 \mathbf{u}$$

Short Answer

Expert verified
The component form is \(\langle 9, -6 \rangle\) and the magnitude is \(3\sqrt{13}\).

Step by step solution

01

Multiply the vectors by scalar

To find the component form of the vector obtained by multiplying a vector by a scalar, you multiply each component of the vector by the scalar. Given \(\mathbf{u}=\langle 3,-2\rangle\), you multiply each component by the scalar 3: \[3 \times 3, 3 \times (-2) = \langle 9, -6 \rangle\].
02

Calculate the Magnitude

The magnitude of a vector \(\mathbf{w} = \langle x, y \rangle\) is calculated using the formula: \[\|\mathbf{w}\| = \sqrt{x^2 + y^2}\].Substitute the components of the vector \(\langle 9, -6 \rangle\):\[\|3\mathbf{u}\| = \sqrt{9^2 + (-6)^2} = \sqrt{81 + 36} = \sqrt{117} = 3\sqrt{13}\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Component Form
In vector mathematics, the component form of a vector is a way to express the vector using its horizontal and vertical parts. This is often presented as \(\langle x, y \rangle\). Imagine you have a vector \(\mathbf{u} = \langle 3, -2 \rangle\). Here, 3 is the horizontal component (along the x-axis), and -2 is the vertical component (along the y-axis).

The beauty of component form is that it simplifies complex operations like addition, subtraction, and scalar multiplication. For scalar multiplication, say we want to multiply the vector \(\mathbf{u}\) by a constant (or scalar) 3. It’s straightforward:
  • Multiply each component of \(\langle 3, -2 \rangle\) separately by 3.
  • The new vector after multiplying: \(3 \times 3 = 9\) and \(3 \times -2 = -6\).
Thus, the component form of the vector \(3\mathbf{u}\) is \(\langle 9, -6 \rangle\). This method is efficient and reduces the likelihood of errors in calculations.
Magnitude of a Vector
The magnitude of a vector, also known as its length, measures how long the vector is in a numerical sense. To find it, one uses the Pythagorean theorem in a vector context. If you have a vector \(\mathbf{w} = \langle x, y \rangle\), its magnitude \(\|\mathbf{w}\|\) is given by the formula:
  • \(\|\mathbf{w}\| = \sqrt{x^2 + y^2}\)
This formula comes from the Pythagorean theorem where the vector is visualized as the hypotenuse of a right triangle. For example, for the vector \(3\mathbf{u} = \langle 9, -6 \rangle\), the magnitude is:
  • Calculate \(\sqrt{9^2 + (-6)^2} = \sqrt{81 + 36} = \sqrt{117}\).
This simplifies to \(3\sqrt{13}\).

The magnitude gives us the "size" of the vector. It is a scalar value, meaning it has magnitude only without direction.
Scalar Multiplication
Scalar multiplication involves scaling a vector by a certain factor. This multiplication affects the vector's magnitude but keeps its direction consistent, unless the scalar is negative, which reverses the direction.

Consider any vector \(\mathbf{u} = \langle 3, -2 \rangle\). When multiplied by a scalar, say 3, each component of \(\mathbf{u}\) is individually multiplied:
  • The horizontal component: \(3 \times 3 = 9\)
  • The vertical component: \(3 \times -2 = -6\)

This procedure transforms the vector to \(\langle 9, -6 \rangle\). This is what we call "stretching" or "shrinking" the vector; in this case, the vector is stretched to three times its original magnitude.
  • A positive scalar increases the size without changing direction.
  • A negative scalar changes the direction while also adjusting the vector's size.
Scalar multiplication helps in geometrical transformations and is a foundational vector operation.

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