Chapter 11: Problem 56
Give polar coordinates for their centers and identify their radii. $$r=-8 \sin \theta$$
Short Answer
Expert verified
The center is at (0, -4) and the radius is 4.
Step by step solution
01
Identifying Equation Type
The given equation is in the polar form as it involves variables \( r \) and \( \theta \). The general form for a circle in polar coordinates is \( r = a \sin\theta \) or \( r = a \cos\theta \). Here, we have \( r = -8 \sin \theta \).
02
Rewriting the Equation
Since \( r = -8 \sin \theta \) can be rewritten as \( r = -8 \sin \theta + 0 \cos \theta \), it is in the correct format to identify the circle's properties.
03
Identifying Circle Parameters
The general equation for a circle in polar coordinates is \( r = a \sin\theta + b \cos\theta \), which corresponds to a circle with center at \( (x, y) = (b/2, a/2) \). In our equation, \( a = -8 \) and \( b = 0 \), so the center is at \( (0/2, -8/2) = (0, -4) \).
04
Calculating Radius
In a polar equation of the form \( r = a \sin\theta + b \cos\theta \), the radius of the circle is given by \( \frac{\sqrt{a^2 + b^2}}{2} \). For this equation, \( a = -8 \) and \( b = 0 \), so the radius is \( \frac{\sqrt{(-8)^2 + 0^2}}{2} = 4 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
circle equation
A circle equation in polar coordinates often appears in the forms of either \( r = a \sin\theta \) or \( r = a \cos\theta \). These are common representations for circles when dealing with polar coordinates, where \( r \) is the radial distance from the origin and \( \theta \) is the angle. Each form describes a circle but with different orientations in the polar plane:
- \( r = a \sin\theta \) generally depicts a circle centered vertically away from the origin.
- \( r = a \cos\theta \) generally depicts a circle centered horizontally away from the origin.
radius calculation
To calculate the radius of a circle in polar coordinates represented as \( r = a \sin\theta + b \cos\theta \), we use the formula \( \frac{\sqrt{a^2 + b^2}}{2} \). This formula derives from the standard properties of a circle, adapted to polar coordinates. In the solution provided, \( a = -8 \) and \( b = 0 \). Let's break it down:
- The term \( \sqrt{(-8)^2 + 0^2} \) gives \( 8 \), which is the hypotenuse of the right triangle formed by \( a \) and \( b \).
- Dividing by 2 simplifies our radius to \( 4 \), meaning the radial distance from the circle's center to its edge is 4 units.
polar form
Polar form is a way to express coordinates and geometric figures using a radius and an angle. Unlike Cartesian coordinates, which use \(x\) and \(y\) values, polar coordinates use \( r \) (the distance from the origin) and \( \theta \) (the angle from the positive x-axis) to define a point or shape. In the exercise solution, we see a perfect example of polar form in the equation \( r = -8 \sin\theta \). Here’s a more in-depth look:
- \( r \) measures how far the point is from the origin, and it's dynamic as \( \theta \) changes.
- The angle \( \theta \) is measured in radians, which is crucial for accurately locating the point on the polar grid.
- Negative values for \( r \) or coefficients like \(-8\) impact the direction or orientation of the shape, such as reflecting it across the axis.