Chapter 11: Problem 28
Sketch the region defined by the inequality. $$0 \leq r^{2} \leq \cos \theta$$
Short Answer
Expert verified
Sketch the region between θ from -π/2 to π/2 with 0 ≤ r ≤ √cosθ.
Step by step solution
01
Understand the Inequality Bounds
The given inequality is \(0 \leq r^2 \leq \cos \theta\). This means that the radius squared, \(r^2\), should be greater than or equal to 0 but less than or equal to \(\cos \theta\). The inequality \(0 \leq r^2\) is always true because \(r^2\) is never negative in real numbers.
02
Transform Inequality to Polar Form
We express \(r\) in terms of \(\theta\), with \(0 \leq r^2 \leq \cos \theta\) implying \(0 \leq r \leq \sqrt{\cos \theta}\). Now consider points only where \(\cos \theta \geq 0\) because the square root of a negative number is not defined in the real plane.
03
Determine Range for \(\theta\)
\(\cos \theta\) is non-negative when \(\theta\) is between \(-\frac{\pi}{2}\) and \(\frac{\pi}{2}\). This is critical since outside this range, \(\cos \theta\) becomes negative and the inequality \(r^2 \leq \cos \theta\) can't hold.
04
Sketch the Region
Draw a polar plot with the origin at the center. From \(\theta = -\frac{\pi}{2}\) to \(\frac{\pi}{2}\), plot the radial lines up to \(r = \sqrt{\cos \theta}\). This results in a symmetrical region about the y-axis that starts from the origin and ends at the maximum radius at \(\theta = 0\), where \(r = 1\).
05
Analyze the Region
The sketched region lies in the first and fourth quadrants of the polar plane. It resembles a sort of cardoid shape but with the longest point extending up to 1 on the positive x-axis. It tapers off as \(\theta\) approaches \(-\frac{\pi}{2}\) and \(\frac{\pi}{2}\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inequality
An inequality is a mathematical statement that defines the relationship between two values that are not equal. In this exercise, the inequality is given by \[0 \leq r^2 \leq \cos \theta\]. This inequality tells us that the square of the radius, \(r^2\), must be non-negative and not greater than \(\cos \theta\).
This is important, as it defines the range of \(r\) in terms of \(\theta\).
In essence, the inequality splits into two parts:
This is important, as it defines the range of \(r\) in terms of \(\theta\).
In essence, the inequality splits into two parts:
- \(r^2 \geq 0\), which is always true since squaring any real number results in a non-negative value.
- \(r^2 \leq \cos \theta\), which imposes the condition that \(r\) can only equate to a square root of a non-negative cosine value.
Polar Plot
The polar plot is a graphical representation where each point on the plane is defined by a distance from a reference point and an angle from a reference direction. In the context of our inequality \[0 \leq r \leq \sqrt{\cos \theta}\], a polar plot helps visualize the region satisfying these conditions. In polar coordinates, the values of \(r\) vary based on \(\theta\), giving us a curve or region instead of a single line or shape in Cartesian coordinates.
Choosing \(r\) values from 0 to \(\sqrt{\cos \theta}\) as \(\theta\) varies from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\), we can sketch these points in the polar plane. The reference direction is usually the positive x-axis.
Choosing \(r\) values from 0 to \(\sqrt{\cos \theta}\) as \(\theta\) varies from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\), we can sketch these points in the polar plane. The reference direction is usually the positive x-axis.
- The angle \(\theta = 0\) corresponds to the positive x-axis direction.
- \(r = \sqrt{\cos \theta}\) gives us the distance from the origin.
- As we increase \(\theta\), the radius changes, creating a dynamic shape in the plot.
Trigonometric Functions
Trigonometric functions relate the angles of a triangle to the lengths of its sides. In our exercise, the cosine function is key. \(\cos \theta\) determines the maximum allowable value of \(r^2\), limiting our polar plot area.
Understanding cosine helps us know when the inequality holds:
Understanding cosine helps us know when the inequality holds:
- \(\cos \theta\) is positive in the first and fourth quadrants (i.e., angles between \(-\frac{\pi}{2}\) and \(\frac{\pi}{2}\)).
- At \(\theta = 0\), \(\cos \theta\) reaches its peak value of 1, making \(r = 1\) the longest radial distance in our plot.
Region Sketching
Region sketching in polar coordinates involves plotting points that satisfy given conditions, then interpreting these points as a complete shape or region. For inequality \[0 \leq r \leq \sqrt{\cos \theta}\], region sketching starts by identifying acceptable \(r\) values for each \(\theta\).
To accomplish this:
At \(\theta = 0\), the region hits its maximum width, tapering as \(\theta\) nears limits to \(-\frac{\pi}{2}\) and \(\frac{\pi}{2}\). This approach transforms equations into a visual understanding, anchoring abstract math in tangible geometry.
To accomplish this:
- Fix \(\theta\) within the allowable range (\(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\)) where \(\cos \theta\) is non-negative.
- Calculate corresponding \(r\) values using \(r = \sqrt{\cos \theta}\).
- Plot these points on the polar plane, joining them to form the region satisfying the inequality.
At \(\theta = 0\), the region hits its maximum width, tapering as \(\theta\) nears limits to \(-\frac{\pi}{2}\) and \(\frac{\pi}{2}\). This approach transforms equations into a visual understanding, anchoring abstract math in tangible geometry.