Chapter 10: Problem 88
If \(\Sigma a_{n}\) converges and \(\Sigma b_{n}\) diverges, can anything be said about their term-by-term sum \(\Sigma\left(a_{n}+b_{n}\right) ?\) Give reasons for your answer.
Short Answer
Expert verified
\(\Sigma (a_n + b_n)\) diverges because \(\Sigma b_n\) dominates the behavior of the sum.
Step by step solution
01
Understand Series Convergence and Divergence
A series \(\Sigma a_n\) is said to converge if the sequence of partial sums \(S_n = a_1 + a_2 + ... + a_n\) approaches a finite limit as \(n\) approaches infinity. Conversely, a series \(\Sigma b_n\) is said to diverge if this sequence does not have a finite limit.
02
Analyze the Properties Given
We are given that \(\Sigma a_n\) converges and \(\Sigma b_n\) diverges. Therefore, \(\Sigma a_n\) approaches a finite limit, while \(\Sigma b_n\) does not approach a finite limit.
03
Consider the Sum of the Two Series
The series \(\Sigma (a_n + b_n)\) is defined as the sum of \(\Sigma a_n\) and \(\Sigma b_n\) term by term. To determine the nature of this new series, we need to analyze the effect of adding a divergent series to a convergent one.
04
Apply the Convergence and Divergence Rule
A basic principle in convergence is that the sum of a convergent series with a divergent one is generally divergent. This is because the divergent part (which does not settle to any finite sum) dominates the behavior of the term-by-term series.
05
Conclude the Divergence of the Sum
Since \(\Sigma b_n\) diverges, adding its terms will cause \(\Sigma (a_n + b_n)\) to diverge as well, despite the convergence of \(\Sigma a_n\). Therefore, the term-by-term sum \(\Sigma (a_n + b_n)\) must diverge.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Convergent Series
A convergent series is one where the infinite sum of its sequence of terms has a finite limit. This means that as you sum the terms step by step, the total ultimately settles towards a specific value. This characteristic is expressed mathematically by the sequence of partial sums. If the sequence of partial sums, denoted as \(S_n = a_1 + a_2 + \ldots + a_n\), approaches a finite limit as \(n\) goes to infinity, then the series \(\Sigma a_n\) is convergent.The idea can be visualized as follows:
- Think of each term as a step in a staircase.
- If every step brings you closer to a certain height and eventually, no matter how many steps you take, you don't go beyond that height, the staircase converges to that height.
Divergent Series
In contrast to convergent series, a divergent series does not approach a finite limit. This occurs when the sum of the series continues to grow indefinitely or oscillates without converging to any specific value. With a divergent series \(\Sigma b_n\), the sequence of partial sums \(S_n = b_1 + b_2 + \ldots + b_n\) behaves erratically, failing to settle down to a steady value as \(n\) heads towards infinity.Consider the following:
- If you picture each term as another step to climb, but instead of reaching a plateau, you find yourself either climbing endlessly or going back and forth without consistency, you're dealing with a divergent staircase.
Partial Sums
Partial sums are an essential tool in analyzing series. They offer a snapshot of the sum of terms within a sequence as you progress term by term. For any given series \(\Sigma a_n\), a partial sum \(S_n\) represents the sum of the first \(n\) terms, mathematically expressed as \(S_n = a_1 + a_2 + \ldots + a_n\).Here's why partial sums are vital:
- They help determine if a series is convergent or divergent.
- By studying the behavior of these sums as \(n\) increases, you get insights into the nature of the full series.
- If \(S_n\) approaches a specific number as \(n\) grows larger, the series is convergent.
- If \(S_n\) balloons without bound, the series diverges.