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Gives the first term or two of a sequence along with a recursion formula for the remaining terms. Write out the first ten terms of the sequence. \(a_{1}=1, \quad a_{n+1}=a_{n}+\left(1 / 2^{n}\right)\)

Short Answer

Expert verified
The first ten terms are: 1, 1.5, 1.75, 1.875, 1.9375, 1.96875, 1.984375, 1.9921875, 1.99609375, 1.998046875.

Step by step solution

01

Understand the First Term and Recursion Formula

The first term of the sequence is given as \(a_1 = 1\). The recursion formula for generating subsequent terms from the current term is \(a_{n+1} = a_n + \frac{1}{2^n}\). This means each term is obtained by adding \(\frac{1}{2^n}\) to the previous term.
02

Calculate the Second Term

Using the first term \(a_1 = 1\), apply the recursion formula to find the second term: \(a_2 = a_1 + \frac{1}{2^1} = 1 + \frac{1}{2} = 1.5\).
03

Calculate the Third Term

Using \(a_2 = 1.5\), apply the recursion formula for the third term: \(a_3 = a_2 + \frac{1}{2^2} = 1.5 + \frac{1}{4} = 1.75\).
04

Calculate the Fourth Term

Using \(a_3 = 1.75\), apply the recursion formula for the fourth term: \(a_4 = a_3 + \frac{1}{2^3} = 1.75 + \frac{1}{8} = 1.875\).
05

Calculate the Fifth Term

Using \(a_4 = 1.875\), apply the recursion formula for the fifth term: \(a_5 = a_4 + \frac{1}{2^4} = 1.875 + \frac{1}{16} = 1.9375\).
06

Calculate the Sixth Term

Using \(a_5 = 1.9375\), apply the recursion formula for the sixth term: \(a_6 = a_5 + \frac{1}{2^5} = 1.9375 + \frac{1}{32} = 1.96875\).
07

Calculate the Seventh Term

Using \(a_6 = 1.96875\), apply the recursion formula for the seventh term: \(a_7 = a_6 + \frac{1}{2^6} = 1.96875 + \frac{1}{64} = 1.984375\).
08

Calculate the Eighth Term

Using \(a_7 = 1.984375\), apply the recursion formula for the eighth term: \(a_8 = a_7 + \frac{1}{2^7} = 1.984375 + \frac{1}{128} = 1.9921875\).
09

Calculate the Ninth Term

Using \(a_8 = 1.9921875\), apply the recursion formula for the ninth term: \(a_9 = a_8 + \frac{1}{2^8} = 1.9921875 + \frac{1}{256} = 1.99609375\).
10

Calculate the Tenth Term

Using \(a_9 = 1.99609375\), apply the recursion formula for the tenth term: \(a_{10} = a_9 + \frac{1}{2^9} = 1.99609375 + \frac{1}{512} = 1.998046875\).
11

Write the First Ten Terms

Now that we have calculated each step, the first ten terms of the sequence are: \(1, 1.5, 1.75, 1.875, 1.9375, 1.96875, 1.984375, 1.9921875, 1.99609375, 1.998046875\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

recursion formula
A recursion formula is a way to define each term in a sequence using the preceding term or terms. It's like a recipe where each step builds upon the last. In our example, the recursion formula is given by \(a_{n+1} = a_n + \frac{1}{2^n}\). This means that to find the next term \(a_{n+1}\), you add \(\frac{1}{2^n}\) to the current term \(a_n\).
Recursion formulas are particularly useful for sequences where each term depends directly on the previous one. Instead of computing each term from scratch, you follow this defined pattern, making calculations simpler and more organized.
Here are a few benefits of recursion formulas:
  • They reduce the complexity of large sequences, as ongoing calculations are simplified.
  • They help in understanding the intrinsic relationships within a sequence.
  • They're ideal for programming and algorithm design due to their iterative nature.
sequence calculation
Sequence calculation involves finding the terms of a sequence based on a given rule or formula.
In our exercise, we've applied the recursion formula to calculate the first ten terms step-by-step. The process unfolds as:
- Start with the initial term, here \(a_1 = 1\).
- Apply the recursion formula to find each subsequent term, one by one.
For example:
  • Second term: \(a_2 = a_1 + \frac{1}{2^1} = 1.5\)
  • Third term: \(a_3 = a_2 + \frac{1}{2^2} = 1.75\)
Repeating the steps eventually leads you to the tenth term.
This process demonstrates two important aspects of sequence calculation:
  • The direct application of the formula to produce reliable results.
  • A methodical approach of building from known values to unknown values.
Such step-by-step calculation not only ensures accuracy but also reinforces the pattern recognition capabilities needed in more advanced mathematical problems.
mathematical sequences
Mathematical sequences are ordered lists of numbers that follow a specific pattern or rule. They can be finite or infinite, and they're a fundamental part of mathematics.
In the provided exercise, we explored a sequence defined recursively. This type of sequence allows for dynamic growth, where each term is influenced directly by its predecessor.
Sequences can be defined by different types of formulas, such as:
  • **Arithmetic Sequences:** Linear sequences where the difference between terms is constant.
  • **Geometric Sequences:** Sequences where each term is obtained by multiplying the previous term by a constant factor.
  • **Recursive Sequences:** Sequences, like ours, where each term relies on previous terms.
Understanding mathematical sequences is essential, as they're used in fields ranging from economics to computer science. They form the basis for series, functions, and models, fostering analytical thinking and problem-solving.
So, whether you're adding fractions as in this exercise, or calculating more complex series, knowing the fundamentals of sequences is invaluable.

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Most popular questions from this chapter

A patient takes a 300 mg tablet for the control of high blood pressure every morning at the same time. The concentration of the drug in the patient's system decays exponentially at a constant hourly rate of \(k=0.12\) a. How many milligrams of the drug are in the patient's system just before the second tablet is taken? Just before the third tablet is taken? b. In the long run, after taking the medication for at least six months, what quantity of drug is in the patient's body just before taking the next regularly scheduled morning tablet?

Using a CAS, perform the following steps to aid in answering questions (a) and (b) for the functions and intervals. Step 1: Plot the function over the specified interval. Step 2: Find the Taylor polynomials \(P_{1}(x), P_{2}(x),\) and \(P_{3}(x)\) at \(\bar{x}=0\) Step 3: Calculate the ( \(n+1\) )st derivative \(f^{(n+1)}(c)\) associated with the remainder term for each Taylor polynomial. Plot the derivative as a function of \(c\) over the specified interval and estimate its maximum absolute value, \(M\) Step 4: Calculate the remainder \(R_{n}(x)\) for each polynomial. Using the estimate \(M\) from Step 3 in place of \(f^{(n+1)}(c),\) plot \(R_{n}(x)\) over the specified interval. Then estimate the values of \(x\) that answer question (a). Step 5: Compare your estimated error with the actual error \(E_{n}(x)=\left|f(x)-P_{n}(x)\right|\) by plotting \(E_{n}(x)\) over the specified interval. This will help answer question (b). Step 6: Graph the function and its three Taylor approximations together. Discuss the graphs in relation to the information discovered in Steps 4 and 5. $$f(x)=(\cos x)(\sin 2 x), \quad|x| \leq 2$$

Use a CAS to perform the following steps for the sequences. a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L\) ? b. If the sequence converges, find an integer \(N\) such that \(\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) \(a_{n}=\sin n\)

a. Use the binomial series and the fact that $$ \frac{d}{d x} \sin ^{-1} x=\left(1-x^{2}\right)^{-1 / 2} $$ to generate the first four nonzero terms of the Taylor series for \(\sin ^{-1} x\). What is the radius of convergence? b. Series for \(\cos ^{-1} x \quad\) Use your result in part (a) to find the first five nonzero terms of the Taylor series for \(\cos ^{-1} x\)

Which of the sequences converge, and which diverge? Give reasons for your answers. \(a_{n}=\frac{1+\sqrt{2 n}}{\sqrt{n}}\)

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